Reporting services 计算总计时忽略SSRS列组
我有一个SSR矩阵，如下所示：Reporting services 计算总计时忽略SSRS列组,reporting-services,Reporting Services,我有一个SSR矩阵，如下所示： +--------------------+-------------------------+ | | Date | + +----------+--------------+ | | Quantity | All Quantity | +----------+---------+----------+-----
+--------------------+-------------------------+
| | Date |
+ +----------+--------------+
| | Quantity | All Quantity |
+----------+---------+----------+--------------+
| Employee | Total | | |
+ +---------+----------+--------------+
| | Product | | |
+----------+---------+----------+--------------+
Employee1 Product1 200 2012-01
Employee1 Product1 500 2012-02
Employee1 Product1 900 2012-03
Employee1 Product2 300 2012-01
Employee1 Product2 500 2012-02
Employee1 Product2 40 2012-03
Employee2 Product1 450 2012-01
Employee2 Product1 50 2012-02
Employee2 Product1 30 2012-03
Employee2 Product2 0 2012-01
Employee2 Product2 50 2012-02
Employee2 Product2 120 2012-03
员工行组产品行组列组Quantity所有数量日期组中获得数量
的总金额。但使用我的表达式，它使用来自所有日期组的数据计算所有数量
我的意思是，对于日期“2012-07-13”，所有数量应为1000，对于日期“2012-06-12”，应为500。但事实并非如此，两个日期都显示为1500。我应该如何解决这个问题
我的表达是：
Sum（字段！数量.Value，“员工”）
数据集如下所示：
+--------------------+-------------------------+
| | Date |
+ +----------+--------------+
| | Quantity | All Quantity |
+----------+---------+----------+--------------+
| Employee | Total | | |
+ +---------+----------+--------------+
| | Product | | |
+----------+---------+----------+--------------+
Employee1 Product1 200 2012-01
Employee1 Product1 500 2012-02
Employee1 Product1 900 2012-03
Employee1 Product2 300 2012-01
Employee1 Product2 500 2012-02
Employee1 Product2 40 2012-03
Employee2 Product1 450 2012-01
Employee2 Product1 50 2012-02
Employee2 Product1 30 2012-03
Employee2 Product2 0 2012-01
Employee2 Product2 50 2012-02
Employee2 Product2 120 2012-03
这是我所拥有的，我所得到的，我所需要的一个例子
//IF I USE Sum(Fields!Quantity.Value)
Date1 Date2
Quantity All Quantity Quantity All Quantity
Employee1 Total 590 - 190 -
100 100 50 50
200 100 50 50
150 150 40 40
50 50 30 30
90 50 20 20
//IF I USE Sum(Fields!Quantity.Value, "Employee")
Date1 Date2
Quantity All Quantity Quantity All Quantity
Employee1 Total 590 - 190 -
100 780 50 780
200 780 50 780
150 780 40 780
50 780 30 780
90 780 20 780
//I NEED TO GET
Date1 Date2
Quantity All Quantity Quantity All Quantity
Employee1 Total 590 - 190 -
100 590 50 190
200 590 50 190
150 590 40 190
50 590 30 190
90 590 20 190
如果您可以在SQL中执行操作，那么它将始终比在RDL中更快，但是，至少有一种方法可以在报表中执行。
使用上面的第二个选项，
总和（字段！数量.值，“员工”）：
在我在下面指示的单元格*，给它一个名称。它将是文本框11或其他什么，称之为EmployeeTotal。
在我用插入符号^标记的单元格中，输入以下表达式
=ReportItems!EmployeeTotal.Value
然后你会得到你想要的（见附图）
下次，如果您提供的数据集示例与您提供的要显示的数据集示例相匹配，我们将更容易为您提供帮助
e、 g.在我运行来测试这个的模型中，我使用这个查询来创建我认为是您的真实数据集：
![SELECT 'Employee1' AS Employee, 'Product1' AS Product, 100 AS Quantity, '2012-01' AS Date
UNION ALL
SELECT 'Employee1' AS Employee, 'Product2' AS Product, 200 AS Quantity, '2012-01' AS Date
UNION ALL
SELECT 'Employee1' AS Employee, 'Product3' AS Product, 150 AS Quantity, '2012-01' AS Date
UNION ALL
SELECT 'Employee1' AS Employee, 'Product4' AS Product, 50 AS Quantity, '2012-01' AS Date
UNION ALL
SELECT 'Employee1' AS Employee, 'Product5' AS Product, 90 AS Quantity, '2012-01' AS Date
UNION ALL
SELECT 'Employee1' AS Employee, 'Product1' AS Product, 50 AS Quantity, '2012-02' AS Date
UNION ALL
SELECT 'Employee1' AS Employee, 'Product2' AS Product, 50 AS Quantity, '2012-02' AS Date
UNION ALL
SELECT 'Employee1' AS Employee, 'Product3' AS Product, 40 AS Quantity, '2012-02' AS Date
UNION ALL
SELECT 'Employee1' AS Employee, 'Product4' AS Product, 30 AS Quantity, '2012-02' AS Date
UNION ALL
SELECT 'Employee1' AS Employee, 'Product5' AS Product, 20 AS Quantity, '2012-02' AS Date
如果您可以在SQL中执行操作，那么它将始终比在RDL中更快，但是，至少有一种方法可以在报表中执行。
使用上面的第二个选项，
总和（字段！数量.值，“员工”）：
在我在下面指示的单元格*，给它一个名称。它将是文本框11或其他什么，称之为EmployeeTotal。
在我用插入符号^标记的单元格中，输入以下表达式
=ReportItems!EmployeeTotal.Value
然后你会得到你想要的（见附图）
下次，如果您提供的数据集示例与您提供的要显示的数据集示例相匹配，我们将更容易为您提供帮助
e、 g.在我运行来测试这个的模型中，我使用这个查询来创建我认为是您的真实数据集：
![SELECT 'Employee1' AS Employee, 'Product1' AS Product, 100 AS Quantity, '2012-01' AS Date
UNION ALL
SELECT 'Employee1' AS Employee, 'Product2' AS Product, 200 AS Quantity, '2012-01' AS Date
UNION ALL
SELECT 'Employee1' AS Employee, 'Product3' AS Product, 150 AS Quantity, '2012-01' AS Date
UNION ALL
SELECT 'Employee1' AS Employee, 'Product4' AS Product, 50 AS Quantity, '2012-01' AS Date
UNION ALL
SELECT 'Employee1' AS Employee, 'Product5' AS Product, 90 AS Quantity, '2012-01' AS Date
UNION ALL
SELECT 'Employee1' AS Employee, 'Product1' AS Product, 50 AS Quantity, '2012-02' AS Date
UNION ALL
SELECT 'Employee1' AS Employee, 'Product2' AS Product, 50 AS Quantity, '2012-02' AS Date
UNION ALL
SELECT 'Employee1' AS Employee, 'Product3' AS Product, 40 AS Quantity, '2012-02' AS Date
UNION ALL
SELECT 'Employee1' AS Employee, 'Product4' AS Product, 30 AS Quantity, '2012-02' AS Date
UNION ALL
SELECT 'Employee1' AS Employee, 'Product5' AS Product, 20 AS Quantity, '2012-02' AS Date
有没有可能在问题的末尾添加一个示例数据集？我刚刚添加了它。这是一个非常简单的数据集，不清楚“数量”和“所有数量”的区别是什么。尽管如此，我认为如果您的分组是正确的，那么简单的总和（Fields！Quantity.Value）
（不要指定任何分组）应该可以做到这一点。“Quantity”是员工组中一个产品的数量。“所有数量”是一名员工所有产品数量的总和（与员工总数类似）。简单Sum（Fields！Quantity.Value）
在“总计”行中正确计算总计，但我在每一行中都需要它，这就是问题所在。我刚刚添加了一个示例，说明了我所拥有的、得到的和需要的。有没有可能在问题的末尾添加一个示例数据集？我刚刚添加了它。这是一个非常简单的数据集，不清楚“数量”和“所有数量”的区别是什么。尽管如此，我认为如果您的分组是正确的，那么简单的总和（Fields！Quantity.Value）
（不要指定任何分组）应该可以做到这一点。“Quantity”是员工组中一个产品的数量。“所有数量”是一名员工所有产品数量的总和（与员工总数类似）。简单的Sum（Fields！Quantity.Value）
在“总计”行中正确计算总计，但我在每一行中都需要它，这就是问题所在。我刚刚添加了一个示例，说明了我所拥有的、得到的和需要的。