使用Zend Framework 2 Restful Web服务进行路由

我想通过使用Zend Framework 2（更准确地说是2.1.5）实现RESTful Web服务。如果我访问，我会得到一个404，相应的消息是“rest（解析为无效的控制器类或别名：rest）”。出了什么问题

您可以在我的github存储库中看到我的源代码：

路线定义如下：

return array(
    'router' => array(
        'routes' => array(
            'rest' => array(
                'type' => 'ZendMvcRouterHttpSegment',
                'options' => array(
                'route' => '/:controller[.:formatter][/:id]',
                'constraints' => array(
                    'controller' => '[a-zA-Z][a-zA-Z0-9_-]*',
                    'formatter' => '[a-zA-Z][a-zA-Z0-9_-]*',
                    'id' => '[a-zA-Z0-9_-]*'
                ),
            ),
         ),
         'home' => array(
         ...

---

您的路由没有定义控制器所属的命名空间，您需要向路由

默认值添加
\uuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu

        'rest' => array(
            'type' => 'ZendMvcRouterHttpSegment',
            'options' => array(
                'route' => '/:controller[.:formatter][/:id]',
                'defaults' => array(
                    // tell the router which namespace :controller belongs to
                    '__NAMESPACE__' => 'Application\Controller',
                ),
                'constraints' => array(
                    'controller' => '[a-zA-Z][a-zA-Z0-9_-]*',
                    'formatter' => '[a-zA-Z][a-zA-Z0-9_-]*',
                    'id' => '[a-zA-Z0-9_-]*'
                ),
            ),
        ),

您确定类型有效吗

type' => 'ZendMvcRouterHttpSegment',

对此

type' => 'Segment',

在
YourModule/Controller
文件夹中是否确实有
RestController
类。如果是这样，您是否已将其映射到
module.config.php
中
controllers
数组的
invokables
部分？也就是说，
'YourModule\Controller\Rest'=>'YourModule\Controller\RestController'，
谢谢，正如您在我的存储库中看到的，我想我已经完成了这两项工作。还有什么建议吗？