Routes Nuxt子域路由

我正在尝试在Nuxt中实现子域路由。这就是我需要做的：

/pages/username/index.vue:
username1.mydomain.com (this page should display "hello, i am username1")
username2.mydomain.com (this page should display "hello, i am username2")
username3.mydomain.com (this page should display "hello, i am username3")
username4.mydomain.com (this page should display "hello, i am username4")
and so on

/pages/username/content.vue
username1.mydomain.com/content (this page should display "content by username1")
username2.mydomain.com/content (this page should display "content by username2")
username3.mydomain.com/content (this page should display "content by username3")
username4.mydomain.com/content (this page should display "content by username4")
and so on

我发现（尚未实现），但它使用@Nuxtjs/router（我认为）覆盖vue路由器-想知道是否有更好的方法，我真的很喜欢nuxt“创建页面，而不需要定义路由”的方法。 有没有办法在nuxt中做到这一点，理想情况下不使用vue路由器，保持nuxt的默认页面/路由行为

// router.js

import Router from 'vue-router'

export function createRouter(ssrContext, createDefaultRouter, routerOptions) {
  const options = routerOptions || createDefaultRouter(ssrContext).options

  let routesDirectory = null

  if (process.server && ssrContext && ssrContext.nuxt && ssrContext.req) {
    const req = ssrContext.req

    const domainLevel = (req.headers.host.match(/\./g) || []).length + 1

    // Get routes directory by hostname

    routesDirectory = domainLevel > 2 ? 'sub-domain' : 'root-domain'
    // Save to the object that will be sent to the client as inline-script
    ssrContext.nuxt.routesDirectory = routesDirectory
  }
  if (process.client) {
    // Get what we saved on SSR
    if (window.__NUXT__ && window.__NUXT__.routesDirectory) {
      routesDirectory = window.__NUXT__.routesDirectory
    }
  }

  function isUnderDirectory(route, directory) {
    const path = route.path
    return path === '/' + directory || path.startsWith('/' + directory + '/')
  }

  let newRoutes = options.routes
  if (routesDirectory) {
    newRoutes = options.routes
      .filter((route) => {
        // remove routes from other directories
        const toRemove =
          routesDirectory === 'sub-domain'
            ? 'root-domain'
            : 'sub-domain'
        return !isUnderDirectory(route, toRemove)
      })
      .map((route) => {
        // remove directory from path and name
        if (isUnderDirectory(route, routesDirectory)) {
          return {
            ...route,
            path: route.path.substr(routesDirectory.length + 1) || '/',
            name: route.name.substr(routesDirectory.length + 1) || 'index'
          }
        }
        return route
      })
  }

  return new Router({
    ...options,
    routes: newRoutes
  })
}

---

如果您有预先确定的用户名列表，此模块“”可以帮助您

以下是一份：

使用类似以下的文件树：

|   
|─pages
|   ├───username1
|   ├───username2
|   ├───username3
|   └───main-domain

答复如下：

但如果无法预测您的用户名，则应使用路由器处理子域，如下所示：

|   
|─pages
|   ├───username1
|   ├───username2
|   ├───username3
|   └───main-domain