Ruby on rails 如何更改简易日历的日期
我正在Rails中使用simple_calendar创建日历 然而,日历日期在图像中显示为2018-08-23 我想在日历上逐日显示日期,如23,而不是2018-08-23 \u month\u calendar.html.erbRuby on rails 如何更改简易日历的日期,ruby-on-rails,Ruby On Rails,我正在Rails中使用simple_calendar创建日历 然而,日历日期在图像中显示为2018-08-23 我想在日历上逐日显示日期,如23,而不是2018-08-23 \u month\u calendar.html.erb <div class="simple-calendar"> <div class="calendar-heading"> <%= link_to t('simple_calendar.previous', default:
<div class="simple-calendar">
<div class="calendar-heading">
<%= link_to t('simple_calendar.previous', default: 'Previous'), calendar.url_for_previous_view %>
<span class="calendar-title"><%= t('date.month_names')[start_date.month] %> <%= start_date.year %></span>
<%= link_to t('simple_calendar.next', default: 'Next'), calendar.url_for_next_view %>
</div>
<table class="table table-striped">
<thead>
<tr>
<% date_range.slice(0, 7).each do |day| %>
<th><%= t('date.abbr_day_names')[day.wday] %></th>
<% end %>
</tr>
</thead>
<tbody>
<% date_range.each_slice(7) do |week| %>
<tr>
<% week.each do |day| %>
<%= content_tag :td, class: calendar.td_classes_for(day) do %>
<% if defined?(Haml) && respond_to?(:block_is_haml?) && block_is_haml?(block) %>
<% capture_haml(day, sorted_events.fetch(day, []), &block) %>
<% else %>
<% block.call day, sorted_events.fetch(day, []) %>
<% end %>
<% end %>
<% end %>
</tr>
<% end %>
</tbody>
</table>
</div>
根据,您必须在日期
对象上调用日期
我假设在您的例子中,date
对象是名为day
的对象,因此您必须更改视图中的两行(在if/else
语句中):
<% if defined?(Haml) && respond_to?(:block_is_haml?) && block_is_haml?(block) %>
<% capture_haml(day.day, sorted_events.fetch(day, []), &block) %>
<% else %>
<% block.call day.day, sorted_events.fetch(day, []) %>
<% end %>