Ruby on rails 如何更改简易日历的日期

Ruby on rails 如何更改简易日历的日期,ruby-on-rails,Ruby On Rails,我正在Rails中使用simple_calendar创建日历 然而,日历日期在图像中显示为2018-08-23 我想在日历上逐日显示日期,如23,而不是2018-08-23 \u month\u calendar.html.erb <div class="simple-calendar"> <div class="calendar-heading"> <%= link_to t('simple_calendar.previous', default:

我正在Rails中使用simple_calendar创建日历

然而,日历日期在图像中显示为2018-08-23

我想在日历上逐日显示日期,如23,而不是2018-08-23

\u month\u calendar.html.erb

<div class="simple-calendar">
  <div class="calendar-heading">
    <%= link_to t('simple_calendar.previous', default: 'Previous'), calendar.url_for_previous_view %>
    <span class="calendar-title"><%= t('date.month_names')[start_date.month] %> <%= start_date.year %></span>
    <%= link_to t('simple_calendar.next', default: 'Next'), calendar.url_for_next_view %>
  </div>

  <table class="table table-striped">
    <thead>
      <tr>
        <% date_range.slice(0, 7).each do |day| %>
          <th><%= t('date.abbr_day_names')[day.wday] %></th>
        <% end %>
      </tr>
    </thead>

    <tbody>
      <% date_range.each_slice(7) do |week| %>
        <tr>
          <% week.each do |day| %>
            <%= content_tag :td, class: calendar.td_classes_for(day) do %>
              <% if defined?(Haml) && respond_to?(:block_is_haml?) && block_is_haml?(block) %>
                <% capture_haml(day, sorted_events.fetch(day, []), &block) %>
              <% else %>
                <% block.call day, sorted_events.fetch(day, []) %>
              <% end %>
            <% end %>
          <% end %>
        </tr>
      <% end %>
    </tbody>
  </table>
</div>

根据,您必须在
日期
对象上调用
日期

我假设在您的例子中,
date
对象是名为
day
的对象,因此您必须更改视图中的两行(在
if/else
语句中):


<% if defined?(Haml) && respond_to?(:block_is_haml?) && block_is_haml?(block) %>
  <% capture_haml(day.day, sorted_events.fetch(day, []), &block) %>
<% else %>
  <% block.call day.day, sorted_events.fetch(day, []) %>
<% end %>