Ruby on rails 如何用Ruby编写石头、布、剪刀游戏

我试图添加两个特性：第一个是当玩家按下x时，它显示分数，第二个是当玩家按下q退出游戏时

我想将

x=>'：SCORE'

添加到

条目\u to \u SYM

散列中，但当玩家按x时，我不希望计算机选择某些内容

ENTRY_TO_SYM = { 'p'=>:PAPER, 'r'=>:ROCK, 's'=>:SCISSORS, 'x' => :SCORE , 'q' => :QUIT}
VALID_ENTRIES = ENTRY_TO_SYM.keys
COMPUTER_CHOICES = ENTRY_TO_SYM.values
# WINNERS and LOSERS from the player's perspective, the first value of each
# pair being the player's choice, the second, the computer's choice.
WINNERS = [[:SCISSORS, :PAPER], [:PAPER, :ROCK], [:ROCK, :SCISSORS]]
LOSERS =  WINNERS.map { |i,j| [j,i] }

class RockPaperScissors
  def initialize
    @player_score = @computer_score = @ties = 0
  end

  def play(winning_score)
    while @player_score < winning_score && @computer_score < winning_score
      puts "Player score: #{@player_score}, " +
           "Computer score: #{@computer_score}, Ties: #{@ties}"

      player = player_choice 
      computer = COMPUTER_CHOICES.sample
      puts "\nPlayer chooses #{player.to_s}"
      puts "Computer chooses #{computer.to_s}"

      case player_outcome [player, computer]
      when :WIN
        puts "#{player.to_s} beats #{computer.to_s}, player wins the round"
        @player_score += 1
      when :LOSE
        puts "#{computer.to_s} beats #{player.to_s}, computer wins the round"
        @computer_score += 1
      else
        puts "Tie, choose again"
        @ties += 1
      end
    end
    puts "\nFinal score: player: #{@player_score}, " +
         "computer: #{@computer_score} (ties: #{@ties})"
    puts (@player_score == 2) ? "Player wins!" : "Yea! Computer wins!"
  end


  private

  def player_choice
    loop do
      print "Choose rock (r), paper (p) or scissors (s) || OPTION choose (x) if you want to display the score and (q) to quit the game : "
      choice = gets.chomp.downcase
      return ENTRY_TO_SYM[choice] if ENTRY_TO_SYM.key?(choice)
      puts "That entry is invalid. Please re-enter"
    end
  end

  def player_outcome(plays)
    return :WIN  if WINNERS.include?(plays)
    return :LOSE if LOSERS.include?(plays)
    :TIE
  end
end


RockPaperScissors.new.play(3)

ENTRY\u TO\u SYM={'p'=>：纸，'r'=>：石头，'s'=>：剪刀，'x'=>：得分，'q'=>：退出}
有效的\u条目=条目\u到\u SYM.keys
计算机选项=输入符号值
#从玩家的角度来看，赢家和输家，各有其价值
#配对是玩家的选择，第二个是电脑的选择。
胜利者=[[剪刀，布，布，石头，石头，剪刀]]
失败者=胜利者
类剪刀
def初始化
@玩家得分=@computer得分=@ties=0
结束
def播放（赢取分数）
而@player\u score

我会这样做来计算结果：

  values = {
  'Paper' => {
               'Paper'   => 'Ties'
               'Rock'    => 'Wins'
               'Scissors'=> 'Loses'
             }
  'Rock' =>  {
               'Paper'   => 'Loses'
               'Rock'    => 'Ties'
               'Scissors'=> 'Wins'
             }
  'Scissors' => {
                 'Paper'   => 'Wins'
                 'Rock'    => 'Loses'
                 'Scissors'=> 'Ties'
                }
  }
  ENTRY_TO_SYM = { 'p'=>'Paper', 'r'=>'Rock', 's'=>'Scissors', 'x' => :SCORE , 'q' => :QUIT}

  def player_choice
     loop do
       print "Choose rock (r), paper (p) or scissors (s) || OPTION choose (x) 
       if you want to display the score and (q) to quit the game : "
       choice = gets.chomp.downcase
       return ENTRY_TO_SYM[choice] if ENTRY_TO_SYM.key?(choice)
       puts "That entry is invalid. Please re-enter"
     end
  end

---

措辞并不完美，这是未经测试的，需要结果部分，所以请修改它，直到它符合您的要求为止；）

考虑编写

WINNERS={'s'=>'p'，p'=>'r'，r'=>'s'}

。然后，如果变量

player

和

computer

分别保持

'r'

、

'p'

或

's'

，如果

WINNERS[player]==computer[player]==true

，玩家获胜，计算机获胜；否则他们又扔了。你知道这是如何简化你的问题的吗？你不需要符号

：石头

，

：纸

和

：剪刀

。我很困惑，你是在和？你的问题和这两个有什么关系？