Ruby on rails 如何使用Rails 5在控制器内按属性排序has_one关系的子级？

我小时候有两个模特，一个是这样的关系：

class HotelThai < ApplicationRecord

  belongs_to :hotel

  #validates :hotel_id, presence: true
  validates :hotel_name, presence: true
  validates :description, presence: true

end

class HotelEng < ApplicationRecord

  belongs_to :hotel

  validates :hotel_name, presence: true
  validates :description, presence: true

end

但我得到的是：

PG::UndefinedTable: ERROR: missing FROM-clause entry for table "hotel_eng" LINE 1: ...tels" WHERE "hotels"."is_highlight" = $1 ORDER BY hotel_eng.... ^ : SELECT "hotels".* FROM "hotels" WHERE "hotels"."is_highlight" = $1 ORDER BY hotel_eng.hotel_name ASC LIMIT $2 OFFSET $3

---

那么，有人知道如何解决这个问题，或者知道如何用其他方法解决这个问题吗？

如果您想使用order by the columns，您需要连接相关的表。为此使用联接或包含方法

def index
  hotel = I18n.locale == :th ? :hotel_thai : :hotel_eng
  @normal_hotel = Hotel.where(is_highlight: false).
    joins(hotel).order("#{hotel.to_s.pluralize}.hotel_name ASC").
    paginate(page: params[:page], per_page: 10)
  normal_hotel_group = @normal_hotel.in_groups(2)
  ...
end

在订单状态下使用多元化方法

PG::UndefinedTable: ERROR: missing FROM-clause entry for table "hotel_eng" LINE 1: ...tels" WHERE "hotels"."is_highlight" = $1 ORDER BY hotel_eng.... ^ : SELECT "hotels".* FROM "hotels" WHERE "hotels"."is_highlight" = $1 ORDER BY hotel_eng.hotel_name ASC LIMIT $2 OFFSET $3

def index
  hotel = I18n.locale == :th ? :hotel_thai : :hotel_eng
  @normal_hotel = Hotel.where(is_highlight: false).
    joins(hotel).order("#{hotel.to_s.pluralize}.hotel_name ASC").
    paginate(page: params[:page], per_page: 10)
  normal_hotel_group = @normal_hotel.in_groups(2)
  ...
end