Ruby on rails Ruby Rest客户端文章，如何发送头

Ruby rest客户端无法发送头，当我触发Ruby的post请求时，我的java服务无法读取头，如下所示。My Service layers抛出错误标头companyID丢失。当在Postman中运行相同的http请求时，它可以工作

response = RestClient::Request.new({
      method: :post,
      url: 'https://example.com/submitForm',
      headers:{content_type: 'application/x-www-form-urlencoded',
              companyID:'Company1',
              Authorization:'Basic HELLO1234'},
      payload: { data: str_res}
    }).execute do |response, request, result|
      case response.code
      when 400
        [ :error, JSON.parse(response.to_str) ]
      when 200
        [ :success, JSON.parse(response.to_str) ]
        puts request.headers 
      else
        fail "Invalid response #{response.to_str} received."
      end
    end

这是有效的邮递员代码。需要类似的红宝石休息，请建议

POST /submitForm HTTP/1.1
Host: example.com
companyID: Company1
Authorization: Basic HELLO1234
Content-Type: application/x-www-form-urlencoded
Cache-Control: no-cache
Postman-Token: 528cafa1-2b5d-13a1-f227-bfe0171a9437

data=My Own data

---

尝试使用RestClient post方法：

result = RestClient.post(
  'https://example.com/submitForm', 
  payload, 
  {
    content_type: 'application/x-www-form-urlencoded', 
    companyID: 'Company1', 
    Authorization: 'Basic HELLO1234'
  }
)

本例中的有效负载是一个字符串，因此您需要为application/x-www-form-urlencoded找到合适的结构。例如：

payload.to_json => '{"data": "str_res"}'

---

下面的工作。看起来标题应该在同一行中

payloadString = "data=My Own data" 

    response = RestClient::Request.new({
  method: :post,
  url: 'https://example.com/submitForm',
  payload: payloadString,
  headers: {content_type: 'application/x-www-form-urlencoded', companyID:'Company1', Authorization:'Basic HELLO1234'}
   }).execute do |response, request, result|
  case response.code
  when 400
    [ :error, JSON.parse(response.to_str) ]
  when 200
    [ :success, JSON.parse(response.to_str) ]
  else
    fail "Invalid response #{response.to_str} received."
  end
end

---

应该是

公司ID

？您有

companyID

（看起来可能区分大小写），这只是问题中的一个输入错误，请更正。还需要帮助吗