Ruby on rails 如何在Rails中添加批准预订请求?
我有一个预约资源。要批准预订,我在我的BookingController中添加了批准方法:Ruby on rails 如何在Rails中添加批准预订请求?,ruby-on-rails,ruby,Ruby On Rails,Ruby,我有一个预约资源。要批准预订,我在我的BookingController中添加了批准方法: def approve @booking = Booking.find_by_id(params[:id]) @booking.update(state: "approved") if @booking.state == "approved" flash[:success] = "Booking successfully approved" redirect_to bookings_pat
def approve
@booking = Booking.find_by_id(params[:id])
@booking.update(state: "approved")
if @booking.state == "approved"
flash[:success] = "Booking successfully approved"
redirect_to bookings_path
else
flash[:error] = "Booking not approved"
redirect_to bookings_path
end
结束
为了批准预订,我使用了以下链接:
<td><%= link_to 'Approve', bookings_approve(id: booking.id), class: "button-xs success" %></td>
我不确定要批准的链接和相应的路由定义。如何定义路线和到APROVE的链接
每个预订都有一个状态字段,我想在按下“批准”按钮时将其更改为“批准”。
提前谢谢 您可以执行以下操作:
resources :bookings do
member do
post :approve
end
end
这将为您提供(在rake routes
上):
然后做:
<td>
<%= link_to 'Approve', approve_booking_path(booking), class: "button-xs success", method: :post %>
</td>
状态
!=<代码>状态…请发布您的路线。rb
这似乎是在向预订添加列(例如布尔预订.批准
)或新的批准
表之间的选择。你需要知道是谁批准的,什么时候批准的吗?审批是否可以有其他相关信息?如果是这样,一个新的审批
资源从长远来看可以节省您的工作。
<td>
<%= link_to 'Approve', approve_booking_path(booking), class: "button-xs success", method: :post %>
</td>
@booking.update(state: "approved")