Ruby on rails 有没有办法通过在Rails中使用Fast JSON API来选择外部对象的一个属性?
我正在创建一个使用Rails后端API的旅游应用程序。我决定使用Fast JSON API来序列化我的数据。我有一份国家名单;每个国家都有许多城市,每个城市都有许多景点 这些是我的模型之间的关联列表Ruby on rails 有没有办法通过在Rails中使用Fast JSON API来选择外部对象的一个属性?,ruby-on-rails,json,api,fastjsonapi,Ruby On Rails,Json,Api,Fastjsonapi,我正在创建一个使用Rails后端API的旅游应用程序。我决定使用Fast JSON API来序列化我的数据。我有一份国家名单;每个国家都有许多城市,每个城市都有许多景点 这些是我的模型之间的关联列表 Country.rb has_many :cities has_many :attractions, through: :locality Localities.rb has_many :attractions belongs_to :country Attraction.rb belongs
Country.rb
has_many :cities
has_many :attractions, through: :locality
Localities.rb
has_many :attractions
belongs_to :country
Attraction.rb
belongs_to :locality
当我为单个景点序列化数据时,我只希望包括城市的名称属性和它所属国家的名称属性。我目前正在通过添加可选参数来实现这一点,以包括地区和国家名称
def show
attraction = Attraction.find_by(slug: params[:slug])
options = {}
options[:include] = [:locality, :'locality.country.name']
render json: AttractionSerializer.new(attraction, options).serialized_json
end
但是,这将提供国家的所有属性和关系,包括国家内嵌套的所有不相关地区的列表,当我的数据集变得更大时,这将变得非常低效。见下文:
{
"data": {
"id": "1",
"type": "attraction",
"attributes": {
"name": "Plaza de España",
"description": "Site of the World Exposition in 1929",
"types": null,
"latitude": 40.4232824,
"longitude": -3.7107257,
"slug": "plaza-de-espana",
"locality": {
"id": 1,
"name": "Seville",
"country_id": 168,
"created_at": "2020-06-10T05:43:47.474Z",
"updated_at": "2020-06-10T05:43:47.474Z",
"slug": "seville",
"latitude": 37.3886303,
"longitude": -5.9953403
}
},
"relationships": {
"locality": {
"data": {
"id": "1",
"type": "locality"
}
}
}
},
"included": [
{
"id": "1",
"type": "locality",
"attributes": {
"name": "Seville",
"latitude": 37.3886303,
"longitude": -5.9953403,
"slug": "seville"
},
"relationships": {
"country": {
"data": {
"id": "168",
"type": "country"
}
}
}
},
{
"id": "168",
"type": "country",
"attributes": {
"name": "Spain",
"slug": "spain",
"iso_3166_1_alpha2": "ES",
"iso_3166_1_alpha3": "ESP",
"iso_3166_1_numeric": "724"
},
"relationships": {
"localities": {
"data": [
{
"id": "1",
"type": "locality"
},
{
"id": "2",
"type": "locality"
},
{
"id": "3",
"type": "locality"
},
{
"id": "4",
"type": "locality"
},
{
"id": "5",
"type": "locality"
},
{
"id": "6",
"type": "locality"
}
]
},
"attractions": {
"data": [
{
"id": "1",
"type": "attraction"
}
]
}
}
}
]
}
有没有办法在JSON中只包含一个属性(即国家名称),而不是整个对象?(景点嵌套在国家/地区下方两层)
非常感谢。您需要创建多个序列化程序,这些序列化程序协同工作以实现此目的
class AttractionSerializer
include FastJsonapi::ObjectSerializer
attributes :attraction_attr_1, :attraction_attr_2, etc.
belongs_to :locality, serializer: AttractionLocalitySerializer
end
class AttractionLocalitySerializer
include FastJsonapi::ObjectSerializer
attributes :name
belongs_to :country, serializer: AttractionCountrySerializer
end
class AttractionCountrySerializer
include FastJsonapi::ObjectSerializer
attributes :name
end