Ruby 创建一个空扫描函数

如何创建空扫描函数？这是我的

lexicon.rb

文件

    require 'ex48/lexicon.rb'
    require "test/unit"

    class TestNAME < Test::Unit::TestCase
      def test_directions()
        assert_equal(Lexicon.scan("north"), [['direction', 'north']])
        result = Lexicon.scan("north south east")

        assert_equal(result, [['direction', 'north'],
               ['direction', 'south'],
               ['direction', 'east']])
      end

      def test_verbs()
        assert_equal(Lexicon.scan("go"), [['verb', 'go']])
        result = Lexicon.scan("go kill eat")
        assert_equal(result, [['verb', 'go'],
               ['verb', 'kill'],
               ['verb', 'eat']])
      end


      def test_stops()
        assert_equal(Lexicon.scan("the"), [['stop', 'the']])
        result = Lexicon.scan("the in of")
        assert_equal(result, [['stop', 'the'],
               ['stop', 'in'],
               ['stop', 'of']])
      end


      def test_nouns()
       assert_equal(Lexicon.scan("bear"), [['noun', 'bear']])
       result = Lexicon.scan("bear princess")
       assert_equal(result, [['noun', 'bear'],
               ['noun', 'princess']])
      end

      def test_numbers()
        assert_equal(Lexicon.scan("1234"), [['number', 1234]])
        result = Lexicon.scan("3 91234")
        assert_equal(result, [['number', 3],
               ['number', 91234]])
      end


      def test_errors()
        assert_equal(Lexicon.scan("ASDFADFASDF"), [['error', 'ASDFADFASDF']])
        result = Lexicon.scan("bear IAS princess")
        assert_equal(result, [['noun', 'bear'],
               ['error', 'IAS'],
               ['noun', 'princess']])
      end

    end

需要'ex48/lexicon.rb'
需要“测试/单元”
类TestNAME

以下是步骤：

在顶部写下require。让它发挥作用

创建第一个测试用例测试方向的空版本。确保它运行正常

写下测试用例的第一行。让它失败

转到

lexicon.rb

文件，创建一个空扫描函数

运行测试，确保扫描至少正在运行，即使扫描失败

填写psuedo代码注释，了解扫描应如何工作以使测试通过

编写与注释匹配的代码，直到测试通过

返回测试方向并写出其余的行

返回到lexicon.rb中的scan并对其进行操作，以使新的测试代码通过

一旦你完成了，你就有了第一次通过的测试，然后你就进入下一个测试

无论如何，我如何创建一个空扫描函数？任何答案都可以。

def扫描 结束

将上述函数添加到文件中。

添加代码

require 'ex48/lexicon.rb'
require "test/unit"

class TestNAME < Test::Unit::TestCase
  def test_directions()
    assert_equal(Lexicon.scan("north"), [['direction', 'north']])
    result = Lexicon.scan("north south east")

    assert_equal(result, [['direction', 'north'],
           ['direction', 'south'],
           ['direction', 'east']])
  end

  def test_verbs()
    assert_equal(Lexicon.scan("go"), [['verb', 'go']])
    result = Lexicon.scan("go kill eat")
    assert_equal(result, [['verb', 'go'],
           ['verb', 'kill'],
           ['verb', 'eat']])
  end


  def test_stops()
    assert_equal(Lexicon.scan("the"), [['stop', 'the']])
    result = Lexicon.scan("the in of")
    assert_equal(result, [['stop', 'the'],
           ['stop', 'in'],
           ['stop', 'of']])
  end


  def test_nouns()
   assert_equal(Lexicon.scan("bear"), [['noun', 'bear']])
   result = Lexicon.scan("bear princess")
   assert_equal(result, [['noun', 'bear'],
           ['noun', 'princess']])
  end

  def test_numbers()
    assert_equal(Lexicon.scan("1234"), [['number', 1234]])
    result = Lexicon.scan("3 91234")
    assert_equal(result, [['number', 3],
           ['number', 91234]])
  end


  def test_errors()
    assert_equal(Lexicon.scan("ASDFADFASDF"), [['error', 'ASDFADFASDF']])
    result = Lexicon.scan("bear IAS princess")
    assert_equal(result, [['noun', 'bear'],
           ['error', 'IAS'],
           ['noun', 'princess']])
  end
   def scan()
   end

end

     def
      scan()
     end

加 def scan（）结束 希望有帮助

一个函数是

    def
      (your code)
    end

    def
      scan ()
    end

所以一个扫描函数是

    def
      (your code)
    end

    def
      scan ()
    end

---

我很确定这是一个

语法错误

，您需要一个换行符、分号或括号来告诉Ruby没有参数列表……另外

scan

需要更改为

self.scan

（因为它是一个类方法），并且该行需要包装在

类词典中

/

end

。除此之外，@JörgWMittag还指出了一个错误，这很好。你应该在扫描之后添加“（）”。如果你要将

def scan（）end

添加到你的

Lexicon

类中，你的代码仍然可以工作，因为这个（实例）方法永远不会被调用。是的，这是最重要的事情，尤其是当你为一个问题挣扎了一段时间的时候。你现在可以休息一下了，去吧，杀了，吃了！