Ruby 用红宝石打印矩形

如何使用Ruby打印如下矩形：

* = = = *
* = = = *
* * * * *
* = = = *
* = = = *

在这种情况下，行和列的长度相同，并且必须为奇数

例如：

r=矩形（5）

应打印：

* = = = *
* = = = *
* * * * *
* = = = *
* = = = *

如果：

r=矩形（7）

应打印：

* = = = = = *
* = = = = = *
* * * * * * *
* = = = = = *
* = = = = = *
* * * * * * *
* = = = = = *

提前谢谢。

[由我解决]：D

def square(n)
  begin
    if n.odd?
      1.upto(n) do | row |
        if row % 3 != 0
          puts "#{'*'} #{'= ' * (n - 2)}#{'*'}"
        else
          puts "#{'* ' * n}"
        end
      end
    else
      puts 'Must odd number!'
    end
  rescue
    puts 'Must integer number!'
  end
end

square（5）

输出：

square（7）

输出：

square（8）

输出：

必须是奇数

def rectangle(n)
  puts("-----------------For #{n}--------------------")
  if n % 2 == 1
    for i in (1..n)
      for j in (1..n)
        if j == 1 || j == n || 0 == i % 3
          print "* "
        else
          print "= "
        end
      end
      print("\n")
    end
  end
end

rectangle(3)
rectangle(5)
rectangle(7)
rectangle(9)
rectangle(11)

-----------------For 3--------------------
* = * 
* = * 
* * * 

-----------------For 5--------------------
* = = = * 
* = = = * 
* * * * * 
* = = = * 
* = = = * 

-----------------For 7--------------------
* = = = = = * 
* = = = = = * 
* * * * * * * 
* = = = = = * 
* = = = = = * 
* * * * * * * 
* = = = = = * 

-----------------For 9--------------------
* = = = = = = = * 
* = = = = = = = * 
* * * * * * * * * 
* = = = = = = = * 
* = = = = = = = * 
* * * * * * * * * 
* = = = = = = = * 
* = = = = = = = * 
* * * * * * * * * 

-----------------For 11--------------------
* = = = = = = = = = * 
* = = = = = = = = = * 
* * * * * * * * * * * 
* = = = = = = = = = * 
* = = = = = = = = = * 
* * * * * * * * * * * 
* = = = = = = = = = * 
* = = = = = = = = = * 
* * * * * * * * * * * 
* = = = = = = = = = * 
* = = = = = = = = = *

square（8.5）
输出：

必须是整数

def rectangle(n)
  puts("-----------------For #{n}--------------------")
  if n % 2 == 1
    for i in (1..n)
      for j in (1..n)
        if j == 1 || j == n || 0 == i % 3
          print "* "
        else
          print "= "
        end
      end
      print("\n")
    end
  end
end

rectangle(3)
rectangle(5)
rectangle(7)
rectangle(9)
rectangle(11)

-----------------For 3--------------------
* = * 
* = * 
* * * 

-----------------For 5--------------------
* = = = * 
* = = = * 
* * * * * 
* = = = * 
* = = = * 

-----------------For 7--------------------
* = = = = = * 
* = = = = = * 
* * * * * * * 
* = = = = = * 
* = = = = = * 
* * * * * * * 
* = = = = = * 

-----------------For 9--------------------
* = = = = = = = * 
* = = = = = = = * 
* * * * * * * * * 
* = = = = = = = * 
* = = = = = = = * 
* * * * * * * * * 
* = = = = = = = * 
* = = = = = = = * 
* * * * * * * * * 

-----------------For 11--------------------
* = = = = = = = = = * 
* = = = = = = = = = * 
* * * * * * * * * * * 
* = = = = = = = = = * 
* = = = = = = = = = * 
* * * * * * * * * * * 
* = = = = = = = = = * 
* = = = = = = = = = * 
* * * * * * * * * * * 
* = = = = = = = = = * 
* = = = = = = = = = *

square（'blabla'）
输出：

必须是整数
只是为了好玩修改@spn答案

def rectangle(n)
  puts("-----------------For #{n}--------------------")
  if n % 2 == 1
    for i in (1..n)
      for j in (1..n)
        if j == 1 || j == n || 0 == i % 3
          print "* "
        else
          print "= "
        end
      end
      print("\n")
    end
  end
end

rectangle(3)
rectangle(5)
rectangle(7)
rectangle(9)
rectangle(11)

-----------------For 3--------------------
* = * 
* = * 
* * * 

-----------------For 5--------------------
* = = = * 
* = = = * 
* * * * * 
* = = = * 
* = = = * 

-----------------For 7--------------------
* = = = = = * 
* = = = = = * 
* * * * * * * 
* = = = = = * 
* = = = = = * 
* * * * * * * 
* = = = = = * 

-----------------For 9--------------------
* = = = = = = = * 
* = = = = = = = * 
* * * * * * * * * 
* = = = = = = = * 
* = = = = = = = * 
* * * * * * * * * 
* = = = = = = = * 
* = = = = = = = * 
* * * * * * * * * 

-----------------For 11--------------------
* = = = = = = = = = * 
* = = = = = = = = = * 
* * * * * * * * * * * 
* = = = = = = = = = * 
* = = = = = = = = = * 
* * * * * * * * * * * 
* = = = = = = = = = * 
* = = = = = = = = = * 
* * * * * * * * * * * 
* = = = = = = = = = * 
* = = = = = = = = = *

def rectangle(count)
  return 'Must odd number more than 1' unless count.is_a?(Integer) && count.odd? && count > 1
  Array.new(count) { |index| (index + 1) % 3 == 0 ?
                               "#{'* ' * count}".chomp(" ") :
                               "#{'*'} #{'= ' * (count - 2)}#{'*'}" }.join("\n")
end

现在呢

puts rectangle(2) # will print Must odd number more than 1
puts rectangle("asdf") # will print Must odd number more than 1

最好避免将
放入方法中。因此，您可以在web、Telegrambot等中再次使用它们。另外，通过您自己（但相同）的消息复制Ruby异常也不是一个好主意。
我首先创建两行：（有很多方法可以实现这一点）

然后我将定义一个重复模式：

pattern = [a, a, b].cycle

最后，我将打印图案大小的时间：

让我们首先定义一个方法来构造这两种类型的线

def make_line(n, mid_char)
  ['*', *[mid_char]*(n-2), '*'].join(' ')
end

make_line(5, '*') #=> "* * * * *" 
make_line(5, '#') #=> "* # # # *" 

现在创建一个方法，以所需的模式绘制线。只有当
（i+1）%3
等于零时，
i
第四行（基零）才由星星和空格组成；除此之外，该行还包含英镑符号

def draw(n)
  all_stars = make_line(n, '*')
  two_stars = make_line(n, '#')  
  n.times { |i| puts ((i+1) % 3).zero? ? all_stars : two_stars }
end


矩形（3）
看起来怎么样？你知道如何打印字符吗？你知道怎么写循环吗？您面临的具体问题是什么？谢谢大家，已经解决了。只需对我使用模运算：DYour代码实际上打印的是
#
，而不是
=
，并且缺少空格。将返回什么
square（'blablabla'）
）@SPN，现在在每第三行结束时有额外的空白。考虑使用保护子句进行参数检查。类似于
raisetypeerror的东西，除非n是a？整数
作为方法的第一行。
平方（1）
返回
必须是整数打印“*”
将在每行末尾产生一个多余的空格。
除非count.is_是？（整数）和&count.odd？
可能更容易阅读。不必覆盖数组中的
nil
值，您可以将一个块传递给
array.new
来直接指定元素。Cycle+take，我喜欢。这里的所有答案都很好，但这个答案简单而优雅。我把这个答案标记为我问题的答案谢谢！
pattern = [a, a, b].cycle

puts pattern.take(size)
* = = = = = *
* = = = = = *
* * * * * * *
* = = = = = *
* = = = = = *
* * * * * * *
* = = = = = *

def make_line(n, mid_char)
  ['*', *[mid_char]*(n-2), '*'].join(' ')
end

make_line(5, '*') #=> "* * * * *" 
make_line(5, '#') #=> "* # # # *" 

def draw(n)
  all_stars = make_line(n, '*')
  two_stars = make_line(n, '#')  
  n.times { |i| puts ((i+1) % 3).zero? ? all_stars : two_stars }
end

draw 5
* # # # *
* # # # *
* * * * *
* # # # *
* # # # *
draw 6
* # # # # *
* # # # # *
* * * * * *
* # # # # *
* # # # # *
* * * * * *
draw 7
* # # # # # *
* # # # # # *
* * * * * * *
* # # # # # *
* # # # # # *
* * * * * * *
* # # # # # *