Ruby 使用正则表达式删除字符串中的\项

我有一个如下所示的示例字符串

 "{:@text=>"\"Question 12\" must be answered when  \"question 10 / Question 11 (or Question 9)\" answered"}"

我只想提取文本：

“在回答问题10/问题11（或问题9）时，必须回答问题12”

我试着用这个：

@object.scan(/@text=>"(.*?)"/).flatten.map{ |msg| msg.gsub(/(\.|\s+)/, '').strip }

但是，它只返回一个

\

---

我还可以尝试什么？

您可以尝试使用

/\/\w+/

[13] pry(main)> str
=> "{:@text=>\"\\\"Question 12\\\" must be answered when  \\\"question 10 / Question 11 (or Question 9)\\\" answered\"}"
[14] pry(main)> str.scan(/\/|\w+/).join(" ")
=> "text Question 12 must be answered when question 10 / Question 11 or Question 9 answered"

---

这不是一个有效的字符串。您拥有以下字符串：

 "#{:@text=>"

其次是：

 \"Question 12\" must be answered when  \"question 10 / Question 11 (or Question 9)\" answered"}"

使用单引号：

str = '{:@text=>"\"Question 12\" must be answered when  \"question 10 / Question 11 (or Question 9)\" answered"}'

然后

puts str.gsub(/\{:@text=>|\"|\\|\}/,'')
  #=> Question 12 must be answered when  question 10 / Question 11 (or Question 9) answered