Ruby 返回两个日期时间之间每小时的数组

我希望输出的

date\u glob

如下所示：

{2015-{07-{19-{21,22,23},20-{00,01,02,03,04,05,06,07,08,09,10}}}}

我感谢你的帮助。下面是我的脚本

require 'date'

date_glob = ""; y = 0; m = 0;
(DateTime.new(2015,7,19,21,0,0)..DateTime.new(2015,7,20,10,0,0)).each do |d|
  if d.year != y
    date_glob = "#{date_glob.chomp(',')}}}," if y != 0
    date_glob+= "#{d.year}-{"
    m = 0
  end
  if d.month != m
    date_glob = "#{date_glob.chomp(',')}}," if m != 0
    date_glob+= sprintf("%02d-{",d.month)
  end
  date_glob+= sprintf("%02d-",d.day)
  date_glob+= sprintf("%02d,",d.hour)
  y = d.year
  m = d.month
end
date_glob = "{#{date_glob.chomp(',')}}}}"

---

一个简单的解决方案可以是：

date = DateTime.new(2015,7,19,21,0,0)
end_date = DateTime.new(2015,7,20,10,0,0)
hash = {}
while date <= end_date
  hash[date.year] ||= {}
  hash[date.year][date.month] ||= {}
  hash[date.year][date.month][date.day] ||= []
  hash[date.year][date.month][date.day] << date.hour
  date = date.in(1.hour)
end

hash
=> {2015=>{7=>{19=>[21, 22, 23], 20=>[0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10]}}} 

hash.to_s.gsub("=>",'-').gsub("[","{").gsub("]","}").gsub(/\s+/,'')
=> "{2015-{7-{19-{21,22,23},20-{0,1,2,3,4,5,6,7,8,9,10}}}}"

date=DateTime.new（2015,7,19,21,0,0）
结束日期=日期时间。新（2015,7,20,10,0,0）
哈希={}
而日期{7=>{19=>[21,22,23]，20=>[0,1,2,3,4,5,6,7,8,9,10]}
hash.to_.gsub（“=>”，“-”）.gsub（“[”，“{”）.gsub（“]，“}”）.gsub（/\s+/，”）
=> "{2015-{7-{19-{21,22,23},20-{0,1,2,3,4,5,6,7,8,9,10}}}}"
{2015-{07-{19-{21,22,23}，20-{00,01,02,03,04,05,06,07,08,09,10}}}
应该是字符串吗？如果是这样，你需要用引号括起来。