Ruby中的if语句冲突
我尝试在支持Ruby 1.8.7的在线IDE中运行此代码,但无法识别elsif语句;e、 如果我输入85,它仍然返回超重Ruby中的if语句冲突,ruby,if-statement,ide,ruby-1.8.7,puts,Ruby,If Statement,Ide,Ruby 1.8.7,Puts,我尝试在支持Ruby 1.8.7的在线IDE中运行此代码,但无法识别elsif语句;e、 如果我输入85,它仍然返回超重 def prompt print ">> " end puts "Welcome to the Weight-Calc 3000! Enter your weight below!" prompt; weight = gets.chomp() if weight > "300" puts "Over-weight" elsif weight &l
def prompt
print ">> "
end
puts "Welcome to the Weight-Calc 3000! Enter your weight below!"
prompt; weight = gets.chomp()
if weight > "300"
puts "Over-weight"
elsif weight < "100"
puts "Under-weight"
end
但是,当我运行以下程序时,它运行得很好:
def prompt
print ">> "
end
puts "Welcome to the Weight-Calc 3000! Enter your weight below!"
prompt; weight = gets.chomp()
if weight > "300"
puts "Over-weight"
elsif weight > "100" && weight < "301"
puts "You're good."
end
你知道如何解决这个问题吗?问题是你试图比较从左到右计算的字符串,而不是数字 将它们转换为整数或浮点数,并进行比较
weight = Integer(gets.chomp())
if weight > 300
puts "Over-weight"
elsif weight < 100
puts "Under-weight"
end
问题是,您试图比较从左到右求值的字符串,而不是数字 将它们转换为整数或浮点数,并进行比较
weight = Integer(gets.chomp())
if weight > 300
puts "Over-weight"
elsif weight < 100
puts "Under-weight"
end
与
您正在比较两个字符串
应该是
if weight.to_i > 300
与
您正在比较两个字符串
应该是
if weight.to_i > 300