从各种Sails.js模型关联中获取扁平JSON

我有这样的层次结构：

PersonTeamDepartment

我想从这样一个人身上提取扁平化记录：

{ 
  "name": "Foo",
  "id": 1,
  ...
  "team": {
    "name": "MGMT",
    "id": 1,
    "department": 1
    ...
  },
  "department": {
    "name": "Top",
    "id": 1,
    "office": 1
    ...
  }
}

这些是模型：

人

// A person that belongs to a team
module.exports = {

  attributes: {
    name: {
      type: 'string',
      required: true
    },

    //Assosiations    
    team: {
      model: 'team'
    },
    department: {
      model: 'department',
      via: 'team.department'
    }, 
  }
};

团队

系

// A department that has many teams
module.exports = {

  attributes: {
    name: {
      type: 'string',
      required: true
    },

    teams: {
      collection: 'team',
      via: 'department'
    }
  }
};

我不能这样做（是的，它有更多的级别）：

---

有没有更好的方法？

如果您使用Mongo，您可以使用Promissions。看起来好多了

var composeRecord
Person.findById(1).then(function(people){
    composeRecord = people[0]
    return Team.findById(people[0].team)
}).then(function (teams) {
    composeRecord.team = teams[0]
    return Department.findById(teams[0].department)
}).then(function(departments){
    composeRecord.department = departments[0]
    return Office.findById(departments[0].office)
}).then(function(offices){
    composeRecord.office = offices[0]
    return Company.findById(offices[0].company)
}).then(function(companies){
    composeRecord.company = companies[0]
    res.json(composeRecord)
}).catch(function (err) {
    console.log(err)
})

---

如果您使用的是MySQL o PG之类的关系数据库，那么您应该编写一个

数据库查询并使用@FilipeMoraisJorge。它可以工作，但如果您使用连接编写查询，它会工作得更快。因此，我选择对数据库不可知还是执行得更快。再次感谢。你也可以试试。Id支持深度填充。如果你有合适的密钥，你的代码就会更像这个人。findById（1）。填充（'team'）。填充（'department'）。填充（'office'）。填充（'company'）。然后（）

function (req, res) {

        Person.findById(1).exec(function (err, people) {
            Team.findById(people[0].team).exec(function (err, teams) {
                Department.findById(teams[0].department).exec(function (err, departments) {
                    Office.findById(departments[0].office).exec(function (err, offices) {
                        Company.findById(offices[0].company).exec(function (err, companies) {

                            var composeRecord = Object.assign(
                                people[0], {
                                    team: teams[0],
                                    department: departments[0],
                                    office: offices[0],
                                    company: companies[0],
                                });

                            res.send(composeRecord);

                        })
                    })
                })
            })
        })  
    }

var composeRecord
Person.findById(1).then(function(people){
    composeRecord = people[0]
    return Team.findById(people[0].team)
}).then(function (teams) {
    composeRecord.team = teams[0]
    return Department.findById(teams[0].department)
}).then(function(departments){
    composeRecord.department = departments[0]
    return Office.findById(departments[0].office)
}).then(function(offices){
    composeRecord.office = offices[0]
    return Company.findById(offices[0].company)
}).then(function(companies){
    composeRecord.company = companies[0]
    res.json(composeRecord)
}).catch(function (err) {
    console.log(err)
})