Scala 移除n+；从df开始的1行

我有一个数据帧

number  time     td
1       1        1
1       1        11
1       2        2
1       10       9
1       14       10
2       1        1
2       11       10
2       15       20
2       15       21
2       16       21
2       17       21
2       18       21

如果当前td>10，我需要删除第n+1行，然后移动到第n+2行，并重复此步骤

结果

number  time     td
1       1        1
1       1        11
1       10       9
1       14       10
2       1        1
2       11       10
2       15       20
2       16       21
2       18       21

我如何才能做到这一点？

检查下面的代码

scala> df.show(false)
+------+----+---+
|number|time|td |
+------+----+---+
|1     |1   |1  |
|1     |1   |11 |
|1     |2   |2  |
|1     |10  |9  |
|1     |14  |10 |
|2     |1   |1  |
|2     |11  |10 |
|2     |15  |20 |
|2     |15  |21 |
|2     |16  |21 |
|2     |17  |21 |
|2     |18  |21 |
+------+----+---+

输出

+------+----+---+
|number|time|td |
+------+----+---+
|1     |1   |1  |
|1     |1   |11 |
|1     |10  |9  |
|1     |14  |10 |
|2     |1   |1  |
|2     |11  |10 |
|2     |15  |20 |
|2     |16  |21 |
|2     |18  |21 |
+------+----+---+

+------+----+---+
|number|time|td |
+------+----+---+
|1     |1   |1  |
|1     |1   |11 |
|1     |10  |9  |
|1     |14  |10 |
|2     |1   |1  |
|2     |11  |10 |
|2     |15  |20 |
|2     |16  |21 |
|2     |18  |21 |
+------+----+---+