将case类应用于嵌套形式Scala Play中的独立字段

我试图将一个case类应用于Scala播放表单中的单个字段。我尝试应用它的字段是

exerciseName

在

setsForm

变量中

  case class ExerciseName(exerciseName:String)
  case class WorkoutSet(exerciseName:ExerciseName, number:Int)
  case class WorkoutSets(sets:List[WorkoutSet]) 
  val setsForm:Form[WorkoutSets] = Form( 
    mapping( 
      "workoutSets" -> list(mapping
      (   
        //i need to get exerciseName to be of type ExerciseName somehow...
        "exerciseName" ->nonEmptyText,  
        "workoutSet" -> number(min=1,max=20)
        )(WorkoutSet.apply)(WorkoutSet.unapply))
    )(WorkoutSets.apply)(WorkoutSets.unapply)
  )

我想知道是否有人能给我一些关于这方面的见解

谢谢

val setsForm:Form[WorkoutSets] = Form(
    mapping(
      "sets" -> list(
        mapping(
          "exerciseName" -> mapping("exerciseName" -> nonEmptyText)(ExerciseName.apply)    (ExerciseName.unapply),
          "workoutSet" -> number(min=1,max=20)
        )(WorkoutSet.apply)(WorkoutSet.unapply)
      )
    )(WorkoutSets.apply)(WorkoutSets.unapply)
)

我还建议将ExerciseName的字段名改为“name”，以避免混淆