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Scala Spark-平面图中Seq[double]的转换符号_Scala_Apache Spark - Fatal编程技术网

Scala Spark-平面图中Seq[double]的转换符号

Scala Spark-平面图中Seq[double]的转换符号,scala,apache-spark,Scala,Apache Spark,我试图改变平面图中的Seq[double]符号。我得到类型不匹配错误 import util.Random.nextDouble var numbers = Seq.fill(1000)(nextDouble) val nrdd = sc.parallelize(numbers) val mrdd = nrdd.flatMap(a => (a)* -1.0) 我认为您只是在寻找map方法,而不是flatMap val mrdd = nrdd.map(a => -a)

我试图改变平面图中的Seq[double]符号。我得到类型不匹配错误

import util.Random.nextDouble
var numbers = Seq.fill(1000)(nextDouble)
val nrdd = sc.parallelize(numbers)    
val mrdd = nrdd.flatMap(a => (a)* -1.0)

我认为您只是在寻找
map
方法,而不是
flatMap

val mrdd = nrdd.map(a => -a)