Scala 我应该如何导入缓存、ws、jdbc和specs2%测试

Scala 我应该如何导入缓存、ws、jdbc和specs2%测试,scala,playframework,Scala,Playframework,我正在将我的项目从play 2.4.3升级到2.5.0 我在plugin.sbt文件中添加了Play2.5.0的sbt插件,如下所示 addSbtPlugin("com.typesafe.play" % "sbt-plugin" % "2.5.0") 当我编译代码时添加后,它会抛出一个错误 [info] Loading project definition from /Users/ege/Sites/Aeione/greenroom6-services-v3/greenroom6-servic

我正在将我的项目从play 2.4.3升级到2.5.0

我在plugin.sbt文件中添加了Play2.5.0的sbt插件,如下所示

addSbtPlugin("com.typesafe.play" % "sbt-plugin" % "2.5.0")
当我编译代码时添加后,它会抛出一个错误

[info] Loading project definition from /Users/ege/Sites/Aeione/greenroom6-services-v3/greenroom6-services-v3/project
[info] Compiling 1 Scala source to /Users/ege/Sites/Aeione/greenroom6-services-v3/greenroom6-services-v3/project/target/scala-2.10/sbt-0.13/classes...
[error] /Users/ege/Sites/Aeione/greenroom6-services-v3/greenroom6-services-v3/project/Common.scala:4: object PlayScala is not a member of package play
[error] import play.PlayScala
[error]        ^
[error] /Users/ege/Sites/Aeione/greenroom6-services-v3/greenroom6-services-v3/project/Common.scala:49: not found: value jdbc
[error]     jdbc,
[error]     ^
[error] /Users/ege/Sites/Aeione/greenroom6-services-v3/greenroom6-services-v3/project/Common.scala:50: not found: value cache
[error]     cache,
[error]     ^
[error] /Users/ege/Sites/Aeione/greenroom6-services-v3/greenroom6-services-v3/project/Common.scala:51: not found: value ws
[error]     ws,
[error]     ^
[error] /Users/ege/Sites/Aeione/greenroom6-services-v3/greenroom6-services-v3/project/Common.scala:52: not found: value specs2
[error]     specs2 % Test,
[error]     ^
[error] 5 errors found
[error] (compile:compileIncremental) Compilation failed

有人能帮我导入这些依赖项吗?

我认为您的导入是错误的。据认为,它应该是:

import sbt._
import Keys._
import play.sbt._
import Play.autoImport._
import PlayKeys._

您是否已在项目中启用该插件
enablePlugins(PlayScala)
yes它是enabledlazy val common=(文件中的项目(“modules/common”))。enablePlugins(PlayScala,LauncherJarPlugin)我已经在build.sbt文件中这样添加了。谢谢@pme。。我想知道在文档中你在哪里找到了这个特殊的部分你检查了我答案中的链接了吗?以下是准确的章节:@MANOJ.S.RAMASWAMY in Stackoverflow,感谢您的upvoting;)。