Scala slick模式-获取连接的表
用斯里克做我的第一步,我有这张桌子Scala slick模式-获取连接的表,scala,slick,scalaquery,Scala,Slick,Scalaquery,用斯里克做我的第一步,我有这张桌子 case class Employee(name: String,last: String,department: Option[Int] = None,id: Option[Int] = None) class Employees (tag: Tag) extends Table[Employee](tag, "EMPLOYEES") { // Auto Increment the id primary key column def id = col
case class Employee(name: String,last: String,department: Option[Int] = None,id: Option[Int] = None)
class Employees (tag: Tag) extends Table[Employee](tag, "EMPLOYEES") {
// Auto Increment the id primary key column
def id = column[Int]("ID", O.PrimaryKey, O.AutoInc)
def name = column[String]("NAME", O.NotNull)
def last = column[String]("LAST", O.NotNull)
def dept = foreignKey("EMP_FK",deptId,departments)(_.id)
def * = (name,last,deptId.?, id.?) <> (Employee.tupled, Employee.unapply)
val departments = TableQuery[Departments]
}
case class DepartmentManager(id:Int,name:String,manager:String)
case class Department(id:Option[Int],name:String,managerId:Int)
class Departments (tag: Tag) extends Table[Department](tag, "DEPARTMENTS") {
val employees = TableQuery[Employees]
def id = column[Int]("ID", O.PrimaryKey, O.AutoInc)
def name = column[String]("NAME", O.NotNull)
def managerId = column[Int]("MANAGER_ID", O.Nullable)
def manager = foreignKey("EMP_FK",managerId,employees)(_.id)
def * = (id.?,name,managerId) <> (Department.tupled, Department.unapply)
}
case class Employee(姓名:String,姓氏:String,部门:Option[Int]=None,id:Option[Int]=None)
类雇员(tag:tag)扩展表[Employee](tag,“Employees”){
//自动递增id主键列
def id=列[Int](“id”,O.PrimaryKey,O.AutoInc)
def name=列[字符串](“名称”,O.NotNull)
def last=列[字符串](“last”,O.NotNull)
def dept=外键(“EMP_FK”,deptId,departments)(.id)
def*=(姓名、姓氏、部门号、id号)(Employee.tuple、Employee.unapply)
val部门=表格查询[部门]
}
案例类部门经理(id:Int,name:String,manager:String)
案例类部门(id:Option[Int],name:String,managerId:Int)
类部门(标记:标记)扩展表[部门](标记,“部门”){
val员工=TableQuery[员工]
def id=列[Int](“id”,O.PrimaryKey,O.AutoInc)
def name=列[字符串](“名称”,O.NotNull)
def managerId=列[Int](“管理器ID”,O.Nullable)
def manager=foreignKey(“EMP_FK”,managerId,employees)(uu.id)
def*=(id.?,名称,managerId)(Department.tuple,Department.unapply)
}
但我得到了编译错误:
查询[Nothing,Nothing,Seq]类型的表达式不符合
预期类型列表[部门经理]
我尝试过这样做(只是为了检查,我知道这很糟糕):
def all:List[DepartmentManager]=db.withSession{implicit session=>
val employees=TableQuery[employees]
val x=用于{
(d,e)部门经理(t.'u 1,t.'u 2,t.'u 3)).托利斯
}
但它并没有给我想要的结果——后者的结果(t.'u 1,t.'u 2,t.'u 3)看起来像
(1,Foo,(雇员路径@1076478352._2).姓名(雇员路径)
@1076478352._2).最后一次)
请告知案例类员工(姓名:String,姓氏:String,部门:Option[Int]=None,id:Option[Int]=None)
case class Employee(name: String, last: String, department: Option[Int] = None, id: Option[Int] = None)
class Employees (tag: Tag) extends Table[Employee](tag, "EMPLOYEES") {
// Auto Increment the id primary key column
val departments = TableQuery[Departments]
def id = column[Int]("ID", O.PrimaryKey, O.AutoInc)
def name = column[String]("NAME", O.NotNull)
def last = column[String]("LAST", O.NotNull)
def deptId = column[Int]("DEPARTMENT", O.NotNull)
def deptFK = foreignKey("EMP_DEP_FK", deptId, departments)(_.id)
def * = (name, last, deptId.?, id.?) <>(Employee.tupled, Employee.unapply)
}
case class DepartmentManager(id: Int, name: String, manager: String)
case class Department(id: Option[Int], name: String, managerId: Int)
class Departments (tag: Tag) extends Table[Department](tag, "DEPARTMENTS") {
val employees = TableQuery[Employees]
def id = column[Int]("ID", O.PrimaryKey, O.AutoInc)
def name = column[String]("NAME", O.NotNull)
def managerId = column[Int]("MANAGER_ID", O.Nullable)
def managerFK = foreignKey("DEP_MAN_FK", managerId, employees)(_.id)
def * = (id.?, name, managerId) <>(Department.tupled, Department.unapply)
}
def all(implicit s: Session): List[DepartmentManager] = {
val employees = TableQuery[Employees]
val x = for {
(d, e) <- departments join employees on (_.managerId === _.id)
} yield (d.id, d.name, e.name + " " + e.last)
x.list.map(t => DepartmentManager(t._1, t._2, t._3))
}
类雇员(tag:tag)扩展表[Employee](tag,“Employees”){
//自动递增id主键列
val部门=表格查询[部门]
def id=列[Int](“id”,O.PrimaryKey,O.AutoInc)
def name=列[字符串](“名称”,O.NotNull)
def last=列[字符串](“last”,O.NotNull)
def deptId=列[Int](“部门”,O.NotNull)
def deptFK=外键(“EMP_DEP_FK”,deptId,departments)(.id)
def*=(姓名、姓氏、部门号、id号)(Employee.tuple、Employee.unapply)
}
案例类部门经理(id:Int,name:String,manager:String)
案例类部门(id:Option[Int],name:String,managerId:Int)
类部门(标记:标记)扩展表[部门](标记,“部门”){
val employees=TableQuery[employees]
def id=列[Int](“id”,O.PrimaryKey,O.AutoInc)
def name=列[字符串](“名称”,O.NotNull)
def managerId=列[Int](“管理器ID”,O.Nullable)
def managerFK=foreignKey(“副经理、经理、员工”)(.id)
def*=(id.?,名称,managerId)(Department.tuple,Department.unapply)
}
def all(隐式s:会话):列表[部门经理]={
val employees=TableQuery[employees]
val x=用于{
(d、e)部门经理(t._1、t._2、t._3))
}
您需要隐式
会话
对象来调用查询中的列表
或迭代器
方法。谢谢,我已经在会话中编辑了我的问题,但经理名称的结果如下所示:(EMPLOYEES Path@1076478352.\u 2).name(EMPLOYEES Path@1076478352.\u 2).LAST
case class Employee(name: String, last: String, department: Option[Int] = None, id: Option[Int] = None)
class Employees (tag: Tag) extends Table[Employee](tag, "EMPLOYEES") {
// Auto Increment the id primary key column
val departments = TableQuery[Departments]
def id = column[Int]("ID", O.PrimaryKey, O.AutoInc)
def name = column[String]("NAME", O.NotNull)
def last = column[String]("LAST", O.NotNull)
def deptId = column[Int]("DEPARTMENT", O.NotNull)
def deptFK = foreignKey("EMP_DEP_FK", deptId, departments)(_.id)
def * = (name, last, deptId.?, id.?) <>(Employee.tupled, Employee.unapply)
}
case class DepartmentManager(id: Int, name: String, manager: String)
case class Department(id: Option[Int], name: String, managerId: Int)
class Departments (tag: Tag) extends Table[Department](tag, "DEPARTMENTS") {
val employees = TableQuery[Employees]
def id = column[Int]("ID", O.PrimaryKey, O.AutoInc)
def name = column[String]("NAME", O.NotNull)
def managerId = column[Int]("MANAGER_ID", O.Nullable)
def managerFK = foreignKey("DEP_MAN_FK", managerId, employees)(_.id)
def * = (id.?, name, managerId) <>(Department.tupled, Department.unapply)
}
def all(implicit s: Session): List[DepartmentManager] = {
val employees = TableQuery[Employees]
val x = for {
(d, e) <- departments join employees on (_.managerId === _.id)
} yield (d.id, d.name, e.name + " " + e.last)
x.list.map(t => DepartmentManager(t._1, t._2, t._3))
}