scala.util.Try块的返回值

我对scala.util.Try API中的示例有一个问题。

案例成功率（v）=> … Success（v）//很明显，返回值是Success（value）
案例失败（e）=> … 分开

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它像递归一样再次调用了divide函数。它一直在呼唤自己，直到成功

例如，在repl中运行时

scala> divide
Enter an Int that you'd like to divide:
Enter an Int that you'd like to divide by:
You must've divided by zero or entered something that's not an Int. Try again!
Info from the exception: / by zero
Enter an Int that you'd like to divide:

我已经传递了分母值零，所以它再次调用了除法函数

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希望，它会有帮助。

这是因为该函数是递归的，总是等待用户的输入，所以当函数失败时，它只会说你搞糟了，然后再试一次

// Input any non-parsable Int should return an Failure(e) instance, right?
// Why is the return value divide, the method itself?
// What does returning divide mean?

scala> divide
Enter an Int that you'd like to divide:
Enter an Int that you'd like to divide by:
You must've divided by zero or entered something that's not an Int. Try again!
Info from the exception: / by zero
Enter an Int that you'd like to divide: