使用sed将模式删除到第一个空格引用
我需要从以下位置删除我的后缀日志行:使用sed将模式删除到第一个空格引用,sed,Sed,我需要从以下位置删除我的后缀日志行: Jun 12 06:19:20 cm postfix: 123123: to=<xxxxx@xxx.xxx>, relay=x.x.x.x, conn_use=3, delay=2, delays=1.6/0/0.01/0.32, dsn=2.0.0, status=sent (250 2.0.0 Ok: queued as XXXXXXX) Jun 12 06:19:20 cm后缀:123123:to=,relay=x.x.x.x,conn_
Jun 12 06:19:20 cm postfix: 123123: to=<xxxxx@xxx.xxx>, relay=x.x.x.x, conn_use=3, delay=2, delays=1.6/0/0.01/0.32, dsn=2.0.0, status=sent (250 2.0.0 Ok: queued as XXXXXXX)
Jun 12 06:19:20 cm后缀:123123:to=,relay=x.x.x.x,conn_use=3,delay=2,delays=1.6/0/0.01/0.32,dsn=2.0.0,status=sent(250 2.0.0.0 Ok:排队为XXXXXXX)
为此:
Jun 12 06:19:20 cm postfix: 123123: to=<xxxxx@xxx.xxx>, relay=x.x.x.x, delay=2, delays=1.6/0/0.01/0.32, dsn=2.0.0, status=sent (250 2.0.0 Ok: queued as XXXXXXX)
Jun 12 06:19:20 cm后缀:123123:to=,relay=x.x.x.x,delay=2,delays=1.6/0/0.01/0.32,dsn=2.0.0,status=sent(250 2.0.0确定:作为XXXXXXX排队)
我只需要删除“conn_use=3”。该值可能是可变的(例如conn_use=12.5)
我试过:
sed的/conn\u use=.*\/'
但它会删除所有内容直到最后一个(基本上,在“as”之后):XXXXXXX)sed方法:
sed 's/conn_use=[^,]*, //' file
输出:
Jun 12 06:19:20 cm postfix: 123123: to=<xxxxx@xxx.xxx>, relay=x.x.x.x, delay=2, delays=1.6/0/0.01/0.32, dsn=2.0.0, status=sent (250 2.0.0 Ok: queued as XXXXXXX)
Jun 12 06:19:20 cm后缀:123123:to=,relay=x.x.x.x,delay=2,delays=1.6/0/0.01/0.32,dsn=2.0.0,status=sent(250 2.0.0确定:作为XXXXXXX排队)
-匹配除[^,]*
,
- sed方法:
sed 's/conn_use=[^,]*, //' file
输出:
Jun 12 06:19:20 cm postfix: 123123: to=<xxxxx@xxx.xxx>, relay=x.x.x.x, delay=2, delays=1.6/0/0.01/0.32, dsn=2.0.0, status=sent (250 2.0.0 Ok: queued as XXXXXXX)
Jun 12 06:19:20 cm后缀:123123:to=,relay=x.x.x.x,delay=2,delays=1.6/0/0.01/0.32,dsn=2.0.0,status=sent(250 2.0.0确定:作为XXXXXXX排队)
-匹配除[^,]*
,
sed 's/conn_use=[^,]*, //'<<< 'Jun 12 06:19:20 cm postfix: 123123: to=<xxxxx@xxx.xxx>, relay=x.x.x.x, conn_use=3, delay=2, delays=1.6/0/0.01/0.32, dsn=2.0.0, status=sent (250 2.0.0 Ok: queued as XXXXXXX)'
sed的/conn_use=[^,]*,/”voila:
sed 's/conn_use=[^,]*, //'<<< 'Jun 12 06:19:20 cm postfix: 123123: to=<xxxxx@xxx.xxx>, relay=x.x.x.x, conn_use=3, delay=2, delays=1.6/0/0.01/0.32, dsn=2.0.0, status=sent (250 2.0.0 Ok: queued as XXXXXXX)'
sed's/conn_use=[^,]*,//':D在终端上测试后,我浪费了一些时间来复制输出:3是的,我对u的尊敬(没有可怜):3没关系,我希望你知道该怎么做:D在终端上测试后,我浪费了一些时间来复制输出:3是的,我对u的尊敬(没有可怜):3没关系,我希望你知道该怎么做