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Sencha touch 将数据加载到JSON存储中_Sencha Touch_Jsonp - Fatal编程技术网

Sencha touch 将数据加载到JSON存储中

Sencha touch 将数据加载到JSON存储中,sencha-touch,jsonp,Sencha Touch,Jsonp,在这里,我面临一些有关应用程序和服务器之间交互的难题。我真的希望你能帮助我。我喜欢将JSONP文件提供的用户信息(姓名、年龄等)加载到JSON存储中。我该怎么办?事先非常感谢 登录功能如下所示: onSigninCommand: function(view, username, password) { var data1 = username; var data2 = password; var me = this; loginView = me.getLoginView

在这里,我面临一些有关应用程序和服务器之间交互的难题。我真的希望你能帮助我。我喜欢将JSONP文件提供的用户信息(姓名、年龄等)加载到JSON存储中。我该怎么办?事先非常感谢

登录功能如下所示:

onSigninCommand: function(view, username, password) {
   var data1 = username;
   var data2 = password;
   var me = this;
   loginView = me.getLoginView();
   if (username.length === 0 || password.length === 0) {
       loginView.showSignInFailedMessage('keine eingabe');
       return;
   }
   console.log('Username: ' + username + '\n' + 'Password: ' + password);
   Ext.util.JSONP.request({
       url: 'http://127.0.0.1:4712/talentcommunity/getuserinfo',
       headers: {
           'content-type': 'application/x-www-form-urlencoded ; charset=utf-8'
       },
       method: 'post',
       params: {
           user: data1,
           pw: data2
       },
       callbackKey: 'callback',

       success: function (response) {

  console.log(response);

  var loginResponse = response;

  if (loginResponse.msg == "OK") {

       var jsonResponse = Ext.JSON.decode(response.responseText);
       XXX.store.MyJsonPStore.loadData(jsonResponse);
       me.signInSuccess();
  }

  else {
       loginView.showSignInFailedMessage('token null.');
  }
},

failure: function(response) {
    loginView.showSignInFailedMessage('token null.');
}
});
Ext.define('xxx.store.MyJsonPStore', {
   extend: 'Ext.data.Store',
   alias: 'store.myStore',

   requires: [
   'xxx.model.user'
   ],

   config: {
      model: 'xxx.model.user',
      storeId: 'myStore',
      proxy: {
         type: 'jsonp',
         url: 'http://127.0.0.1/talentcommunity/getuserinfo',
         autoAppendParams: false,
         reader: {
           type: 'json'
         }
      }
   }
商店定义如下:

onSigninCommand: function(view, username, password) {
   var data1 = username;
   var data2 = password;
   var me = this;
   loginView = me.getLoginView();
   if (username.length === 0 || password.length === 0) {
       loginView.showSignInFailedMessage('keine eingabe');
       return;
   }
   console.log('Username: ' + username + '\n' + 'Password: ' + password);
   Ext.util.JSONP.request({
       url: 'http://127.0.0.1:4712/talentcommunity/getuserinfo',
       headers: {
           'content-type': 'application/x-www-form-urlencoded ; charset=utf-8'
       },
       method: 'post',
       params: {
           user: data1,
           pw: data2
       },
       callbackKey: 'callback',

       success: function (response) {

  console.log(response);

  var loginResponse = response;

  if (loginResponse.msg == "OK") {

       var jsonResponse = Ext.JSON.decode(response.responseText);
       XXX.store.MyJsonPStore.loadData(jsonResponse);
       me.signInSuccess();
  }

  else {
       loginView.showSignInFailedMessage('token null.');
  }
},

failure: function(response) {
    loginView.showSignInFailedMessage('token null.');
}
});
Ext.define('xxx.store.MyJsonPStore', {
   extend: 'Ext.data.Store',
   alias: 'store.myStore',

   requires: [
   'xxx.model.user'
   ],

   config: {
      model: 'xxx.model.user',
      storeId: 'myStore',
      proxy: {
         type: 'jsonp',
         url: 'http://127.0.0.1/talentcommunity/getuserinfo',
         autoAppendParams: false,
         reader: {
           type: 'json'
         }
      }
   }
输入JSONP文件具有以下结构:

{"msg": "OK",
    "user": {
      "token": "xyz",
      "firstName": "Bertha",
      "lastName": "Muster",
      "age": "24",
  }
}

嗨,你能弄明白吗?