Sequelize.js Sequelize-如何使用软删除行的相同主键添加/升级行
我正在使用sequelize ORM。我有一个表格模型,其中我们通过Sequelize.js Sequelize-如何使用软删除行的相同主键添加/升级行,sequelize.js,upsert,soft-delete,Sequelize.js,Upsert,Soft Delete,我正在使用sequelize ORM。我有一个表格模型,其中我们通过paranoid:true启用了软删除 问题:是否有方法进行upsert,以便在对象已存在于表中但被软删除时,只清除deletedAt列 示例设置:model.js const Sequelize = require('sequelize') const sequelize = new Sequelize( dbName, username, password, { host, dialect:
paranoid:true
启用了软删除
问题:是否有方法进行upsert,以便在对象已存在于表中但被软删除时,只清除deletedAt列
示例设置:model.js
const Sequelize = require('sequelize')
const sequelize = new Sequelize(
dbName,
username,
password,
{
host,
dialect: 'mysql',
port
}
)
const model = sequelize.define(
'sample_table',
{
uid: {
type: Sequelize.STRING(60),
allowNull: false
primaryKey: true
},
deletedAt: {
type: Sequelize.Date,
allowNull: true,
default: null
}
},
{
tableName: 'sample_table'
deletedAt: true,
paranoid: true
}
)
示例用法:
const model = require('./model.js')
(async () => {
const myModel = await model.create({
uid: 'sample-uid'
})
await myModel.destroy()
// error is encountered because uid already exists
await model.create({
uid: 'sample-uid'
})
})()
可以,但您应该手动执行此操作(例如,添加一个catch以创建方法,并使用
.restore()
清除deletedAt列)
或者您可以在uid+deletedAt上添加主键,代码应该可以正常工作
const model = require('./model.js')
(async () => {
const myModel = await model.create({
uid: 'sample-uid'
})
await myModel.destroy()
// if primary key uid and deletedAt then no error here
await model.create({
uid: 'sample-uid'
})
})()
谢谢最后我做了你的第一个建议。实际上,对于关联生成的方法,我在原型中扩展了生成方法的功能。第二个建议也适用于我的案例,因为它不适用于高度填充的表。