Shell 将grep作为if条件传递

你好，我正在尝试通过grep作为if条件。也就是说，如果grep与表达式匹配，那么我将打印文件名和行号。到目前为止，我有：

for javaFile in `ls -f *.java` ; do
  if  grep -q '^[^/]{2}.*https' $javaFile || grep -q '^[^/]{2}.*http' $javaFile ;
  then
   echo "The file $javaFile has : " >> ~/Desktop/$1_externalServers.txt
   grep -nrE '^[^/]{2}.*http' $javaFile >> ~/Desktop/$1_externalServers.txt     
   grep -nrE '^[^/]{2}.*https' $javaFile >> ~/Desktop/$1_externalServers.txt
   grep -nrE '^[^/]{2}.*ftp' $javaFile  >> ~/Desktop/$1_externalServers.txt
fi
done

---

但是当我这样做时，我的输出文件是空的。我能知道为什么吗/

grep

需要扩展正则表达式的

-E

选项，并且您不应该解析

ls

的输出：

for javaFile in *.java; do
  if  grep -Eq '^[^/]{2}.*https?' "$javaFile" ;
  then
    echo "The file $javaFile has : " >> ~/Desktop/$1_externalServers.txt
    grep -nrE '^[^/]{2}.*http' $javaFile >> ~/Desktop/$1_externalServers.txt     
    grep -nrE '^[^/]{2}.*https' $javaFile >> ~/Desktop/$1_externalServers.txt
    grep -nrE '^[^/]{2}.*ftp' $javaFile  >> ~/Desktop/$1_externalServers.txt
  fi
done

我还使用

grep-Eq'^[^/]{2}.*https？“$javaFile”

regex将您的2个

grep

命令组合成一个命令。

这就是我所做的

  for javaFile in `ls -f *.java` ; do
    if  `cat $javaFile | grep -rqE '^[^/]{2}.*http'` || `cat $javaFile | grep -rqE '^[^/]{2}.*https'` || `cat $javaFile | grep -rqE '^[^/]{2}.*ftp'` ;
    then
echo "The file $javaFile has : " >> ~/Desktop/$1_externalServers.txt
    grep -nrE '^[^/]{2}.*http' $javaFile >> ~/Desktop/$1_externalServers.txt        
    grep -nrE '^[^/]{2}.*https' $javaFile >> ~/Desktop/$1_externalServers.txt
    grep -nrE '^[^/]{2}.*ftp' $javaFile  >> ~/Desktop/$1_externalServers.txt
    fi
    done

---

输出结果与我预期的一样：）

将`ls-f*.java`中的javaFile替换为*.java中的javaFile。没关系，我得到了答案：$