Spring boot SpringBoot正在抛出一个JpaSystemException而不是ClientException

当方法

handleException（）

抛出

ClientException

时，为什么SpringBoot抛出

JpaSystemException

而不是

ClientException

@RestController
@RequestMapping(path = "/api/clients")
public class ClientController {

    private Logger logger = LoggerFactory.getLogger(getClass());

    @Autowired
    private MessageByLocaleService messageByLocaleService;

    @Autowired
    private PersonService personService;

    @PostMapping(path = "/saveperson", consumes = MediaType.APPLICATION_JSON_VALUE, produces = MediaType.APPLICATION_JSON_VALUE)
    public ResponseEntity<Void> savePerson(@RequestBody @Valid Person person) throws Exception {
        try {
            this.personService.save(person);
        }catch(ClientException ce){
            logger.info(ce.getMessage());
        }catch(JpaSystemException jse){
            logger.info(jse.getMessage());  // <<<<< is catching this exception instead ClientException
        }catch (Exception e){
            logger.info(e.getMessage());
        }
        return new ResponseEntity<Void>(HttpStatus.CREATED);
    }
}

@Service
@Transactional
public class PersonServiceImpl implements PersonService {

    @Autowired
    private PersonRepository personRepository;

    @Autowired
    private MessageByLocaleService messageByLocaleService;

    @Override
    public Person save(Person client) throws ClientException {
        try {
            return this.personRepository.save(client); //trying to save the client throw a MySQLIntegrityConstraintViolationException: Duplicate entry..
        } catch (DataIntegrityViolationException dive) {
            Throwable th = dive.getCause();
            if (th != null && th instanceof ConstraintViolationException) {

                ConstraintViolationException violationException = (ConstraintViolationException) th;
                violationException.printStackTrace();

                handleException(dive, violationException); 

            }
        }
        return null;
    }

    private void handleException(DataIntegrityViolationException dive, ConstraintViolationException violationException) throws ClientException {
        try {
            String ukName = violationException.getConstraintName();
            String ukMessage = messageByLocaleService.getMessage(ukName);

            if (ukMessage != null) {
                ClientException ce = new ClientException(dive.getMostSpecificCause().getMessage(), ukMessage);
                throw ce; 
            }

        } catch (NoSuchMessageException ex) {
            throw new ClientException(violationException.getCause().getMessage(), "UnknownError : " + violationException.getCause().getMessage());
        }
    }   
}

@RestController
@请求映射（path=“/api/clients”）
公共类客户端控制器{
私有记录器Logger=LoggerFactory.getLogger（getClass（））；
@自动连线
私有消息ByLocaleService消息ByLocaleService；
@自动连线
私人私人服务；
@PostMapping（path=“/saveperson”，consumes=MediaType.APPLICATION\u JSON\u VALUE，products=MediaType.APPLICATION\u JSON\u VALUE）
public ResponseEntity savePerson（@RequestBody@Valid Person）引发异常{
试一试{
这个。personService。save（个人）；
}捕获（客户例外ce）{
logger.info（ce.getMessage（））；
}捕获（JpaSystemException jse）{
logger.info（jse.getMessage（））；//
handleException（）
仅为
DataIntegrityViolationException
-
JpaSystemException
调用，我想我不明白

接收DataIntegrityViolationException和ConstraintViolationException作为参数。您看到我给出的链接了吗？捕获特定异常时，您只能处理该异常及其子异常（它扩展了该异常）.

JpaSystemException

不是

DataIntegrityViolationException

的子项，您正在

捕获它。@vasan当然这是我的困难，但我仍然无法理解其观点。我只是将服务更改为
@Transactional（rollboor=Exception.class）
现在可以正确地捕捉到客户异常。这有意义吗？