Spring mvc 在spring3中集成tiles,获取java.lang.NoSuchFieldError:补丁异常
让我知道如何从dispatcher和应用程序上下文初始化磁贴,如果需要在web.xml中进行任何更改, 这是我的tiles.xmlSpring mvc 在spring3中集成tiles,获取java.lang.NoSuchFieldError:补丁异常,spring-mvc,tiles,Spring Mvc,Tiles,让我知道如何从dispatcher和应用程序上下文初始化磁贴,如果需要在web.xml中进行任何更改, 这是我的tiles.xml <definition name="contact" extends="mainLayout"> <put-attribute name="title" value="Contact Manager" /> <put-attribute name="body" value="/WEB-INF/jsp/contact.j
<definition name="contact" extends="mainLayout">
<put-attribute name="title" value="Contact Manager" />
<put-attribute name="body" value="/WEB-INF/jsp/contact.jsp" />
</definition>
</tiles-definitions>
<bean class="org.springframework.web.servlet.view.tiles2.TilesConfigurer" id="tilesConfigurer">
<property name="definitions">
<list>
<value>WEB-INF/tiles.xml</value>
</list>
</property>
</bean>
<bean class="org.springframework.web.servlet.view.UrlBasedViewResolver" id="viewResolver">
<property name="viewClass">
<value>
org.springframework.web.servlet.view.tiles2.TilesView
</value>
</property>
在应用程序上下文中,我使用了
<definition name="contact" extends="mainLayout">
<put-attribute name="title" value="Contact Manager" />
<put-attribute name="body" value="/WEB-INF/jsp/contact.jsp" />
</definition>
</tiles-definitions>
<bean id="tilesConfigurer" class="org.springframework.web.servlet.view.tiles2.TilesConfigurer">
<property name="definitions">
<list>
<value>/WEB-INF/tiles.xml</value>
</list>
</property>
</bean>
<bean id="viewResolver" class="org.springframework.web.servlet.view.UrlBasedViewResolver">
<property name="requestContextAttribute" value="requestContext"/>
<property name="viewClass" value="org.springframework.web.servlet.view.tiles2.TilesView"/>
</bean>
<bean class="org.springframework.web.servlet.view.tiles2.TilesConfigurer" id="tilesConfigurer">
<property name="definitions">
<list>
<value>WEB-INF/tiles.xml</value>
</list>
</property>
</bean>
<bean class="org.springframework.web.servlet.view.UrlBasedViewResolver" id="viewResolver">
<property name="viewClass">
<value>
org.springframework.web.servlet.view.tiles2.TilesView
</value>
</property>
/WEB-INF/tiles.xml
调度员看起来像这样
<definition name="contact" extends="mainLayout">
<put-attribute name="title" value="Contact Manager" />
<put-attribute name="body" value="/WEB-INF/jsp/contact.jsp" />
</definition>
</tiles-definitions>
<bean class="org.springframework.web.servlet.mvc.support.ControllerClassNameHandlerMapping"/>
<bean class="org.springframework.web.servlet.view.tiles2.TilesConfigurer" id="tilesConfigurer">
<property name="definitions">
<list>
<value>WEB-INF/tiles.xml</value>
</list>
</property>
</bean>
<bean class="org.springframework.web.servlet.view.UrlBasedViewResolver" id="viewResolver">
<property name="viewClass">
<value>
org.springframework.web.servlet.view.tiles2.TilesView
</value>
</property>
索引控制器-->
新控制器
<definition name="contact" extends="mainLayout">
<put-attribute name="title" value="Contact Manager" />
<put-attribute name="body" value="/WEB-INF/jsp/contact.jsp" />
</definition>
</tiles-definitions>
<bean class="org.springframework.web.servlet.view.tiles2.TilesConfigurer" id="tilesConfigurer">
<property name="definitions">
<list>
<value>WEB-INF/tiles.xml</value>
</list>
</property>
</bean>
<bean class="org.springframework.web.servlet.view.UrlBasedViewResolver" id="viewResolver">
<property name="viewClass">
<value>
org.springframework.web.servlet.view.tiles2.TilesView
</value>
</property>
WEB-INF/tiles.xml
org.springframework.web.servlet.view.tiles2.TilesView
在Dispatcher Servlet中
<definition name="contact" extends="mainLayout">
<put-attribute name="title" value="Contact Manager" />
<put-attribute name="body" value="/WEB-INF/jsp/contact.jsp" />
</definition>
</tiles-definitions>
<bean class="org.springframework.web.servlet.view.tiles2.TilesConfigurer" id="tilesConfigurer">
<property name="definitions">
<list>
<value>WEB-INF/tiles.xml</value>
</list>
</property>
</bean>
<bean class="org.springframework.web.servlet.view.UrlBasedViewResolver" id="viewResolver">
<property name="viewClass">
<value>
org.springframework.web.servlet.view.tiles2.TilesView
</value>
</property>
<bean id="tilesConfigurer" class="org.springframework.web.servlet.view.tiles2.TilesConfigurer">
<property name="definitions">
<list>
<value>/WEB-INF/tiles.xml</value>
</list>
</property>
</bean>
/WEB-INF/tiles.xml
在web.xml中使用以下代码
<definition name="contact" extends="mainLayout">
<put-attribute name="title" value="Contact Manager" />
<put-attribute name="body" value="/WEB-INF/jsp/contact.jsp" />
</definition>
</tiles-definitions>
<bean class="org.springframework.web.servlet.view.tiles2.TilesConfigurer" id="tilesConfigurer">
<property name="definitions">
<list>
<value>WEB-INF/tiles.xml</value>
</list>
</property>
</bean>
<bean class="org.springframework.web.servlet.view.UrlBasedViewResolver" id="viewResolver">
<property name="viewClass">
<value>
org.springframework.web.servlet.view.tiles2.TilesView
</value>
</property>
<listener>
<listener-class>org.apache.tiles.web.startup.simple.SimpleTilesListener</listener-class>
</listener>
org.apache.tiles.web.startup.simple.SimpleTimeListener
spring tiles应用程序不需要rest,tiles.xml取决于您的要求谢谢,这对我很有帮助
<definition name="contact" extends="mainLayout">
<put-attribute name="title" value="Contact Manager" />
<put-attribute name="body" value="/WEB-INF/jsp/contact.jsp" />
</definition>
</tiles-definitions>
<bean class="org.springframework.web.servlet.view.tiles2.TilesConfigurer" id="tilesConfigurer">
<property name="definitions">
<list>
<value>WEB-INF/tiles.xml</value>
</list>
</property>
</bean>
<bean class="org.springframework.web.servlet.view.UrlBasedViewResolver" id="viewResolver">
<property name="viewClass">
<value>
org.springframework.web.servlet.view.tiles2.TilesView
</value>
</property>