Spring ApacheTiles css

Spring ApacheTiles css,spring,apache,jsp,tiles,Spring,Apache,Jsp,Tiles,我无法加载css文件。尽可能地接近它。谁能告诉我哪里出了问题。提前谢谢 瓷砖定义,其中定义了瓷砖: <?xml version="1.0" encoding="ISO-8859-1" ?> <!DOCTYPE tiles-definitions PUBLIC "-//Apache Software Foundation//DTD Tiles Configuration 3.0//EN" "http://tiles.apache.org/dtds/ti

我无法加载css文件。尽可能地接近它。谁能告诉我哪里出了问题。提前谢谢

瓷砖定义,其中定义了瓷砖:

<?xml version="1.0" encoding="ISO-8859-1" ?>
<!DOCTYPE tiles-definitions PUBLIC
       "-//Apache Software Foundation//DTD Tiles Configuration 3.0//EN"
       "http://tiles.apache.org/dtds/tiles-config_3_0.dtd">
<tiles-definitions>

    <definition name="defaultTemplate" template="/WEB-INF/template/default/template.jsp">
        <put-attribute name="header" value="/WEB-INF/template/default/header.jsp" />
        <put-attribute name="menu" value="/WEB-INF/template/default/menu.jsp" />
        <put-attribute name="body" value="/WEB-INF/template/default/body.jsp" />
        <put-attribute name="footer" value="/WEB-INF/template/default/footer.jsp" />
        <put-attribute name="stylesheets" value="/src/main/resources/css/layout.css" />            
    </definition>


</tiles-definitions>
template.jsp是defalut模板:

<html>
    <head>
    <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
    <title>Default tiles template</title>
     <c:forEach var="css" items="${stylesheets}">
        <link rel="stylesheet" type="text/css" href="<c:url value="${css}"/>">
    </c:forEach>
</head>
<body>
    <div class="page">

        <tiles:insertAttribute name="header" />

        <div class="content">
            <tiles:insertAttribute name="menu" />
            <tiles:insertAttribute name="body" />
        </div>
        <tiles:insertAttribute name="footer" />
    </div>
</body>
</html>
welcomepage.jsp使用template.jsp:

<%@ taglib uri="http://tiles.apache.org/tags-tiles" prefix="tiles"%>
<%@ taglib prefix="form" uri="http://www.springframework.org/tags/form" %>
<%@taglib prefix="c" uri="http://java.sun.com/jsp/jstl/core"%>
<tiles:importAttribute name="stylesheets"/>

<html>
    <head>
    <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
    <title>Default tiles template</title>
     <c:forEach var="css" items="${stylesheets}">
        <link rel="stylesheet" type="text/css" href="<c:url value="${css}"/>">
    </c:forEach>
</head>
<body>
    <div class="page">

        <tiles:insertAttribute name="header" />

        <div class="content">
            <tiles:insertAttribute name="menu" />
            <tiles:insertAttribute name="body" />
        </div>
        <tiles:insertAttribute name="footer" />
    </div>
</body>
</html>
dispatcher-sevrlet.xml:

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:mvc="http://www.springframework.org/schema/mvc" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:p="http://www.springframework.org/schema/p"
xmlns:tx="http://www.springframework.org/schema/tx"
xsi:schemaLocation=" http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd http://www.springframework.org/schema/context 
        http://www.springframework.org/schema/context/spring-context-3.0.xsd http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd
        http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx.xsd">

   <tx:annotation-driven/>

   <mvc:annotation-driven />

   <mvc:resources mapping="/resources/**" location="/resources/" />

  <context:component-scan base-package="intranetwebapp.*" />

  <bean id="viewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver">
    <property name="prefix">
      <value>/WEB-INF/view/</value>
    </property>
    <property name="suffix">
      <value>.jsp</value>
    </property>
  </bean>


    <bean id="dataSource" class="org.apache.commons.dbcp.BasicDataSource"
    destroy-method="close">
    <property name="driverClassName" value="com.mysql.jdbc.Driver" />
    <property name="url" value="jdbc:mysql://localhost:3306/intranetwebapp" />
    <property name="username" value="root" />
    <property name="password" value="gargamel" />
  </bean>

  <bean id="sessionFactory" class="org.springframework.orm.hibernate4.LocalSessionFactoryBean">
    <property name="dataSource" ref="dataSource"></property>
    <property name="hibernateProperties">
      <props>
        <prop 
         key="hibernate.dialect">org.hibernate.dialect.MySQL5Dialect</prop>
        <prop key="hibernate.show_sql">true</prop>
      </props>
    </property>
    <property name="packagesToScan" value="intranetwebapp.entity" />
  </bean>

  <bean id="transactionManager"
    class="org.springframework.orm.hibernate4.HibernateTransactionManager" 
    p:sessionFactory-ref="sessionFactory">
  </bean>



  <!-- Tiles configuration -->

    <bean id="tilesConfigurer"
        class="org.springframework.web.servlet.view.tiles3.TilesConfigurer">
        <property name="definitions">
            <list>
                <value>/WEB-INF/tiles/tiles-definitions.xml</value>
            </list>
        </property>
    </bean>

</beans>

你能试试下面的吗

<head>
    <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
    <title>Default tiles template</title>
    <link rel="stylesheet" href="<c:url value='/resources/css/layout.css'/>">
</head>

或者,您可以在spring模型对象中将样式表变量设置为/resources/css/layout.css,并在jsp中将c:url中的值设置为value='${stylesheet}'。

这不应该是单引号吗${css}。此外,变量中不需要/src/main/。。另外,${stylesheets}不是数组,但您正在尝试对其进行迭代..我尝试了您的解决方案,但它也不起作用。我想这一定是pathoops某个地方的问题。。。这不起作用,因为您正在使用jsp符号来读取一个tiles变量。为什么你不能硬编码样式表路径?所以我应该从tiles defitions中删除属性样式表,然后可以使用它?如果你想使用变量引用路径,你应该从tiles中删除属性样式表,并将其放入控制器中的ModelMap对象中。。或者,您可以使用拦截器将变量添加到会话中。。但我建议您在template.jsp中硬编码css文件,就像我在回答中提到的那样,在这种情况下,您可以完全摆脱样式表变量…我完成了硬编码的最后一个选项,当页面加载时,在web browser developer中,我可以在html代码中看到css链接类似:。但仍然不起作用。