Spring 获取错误未定义[javax.persistence.EntityManagerFactory]类型的限定bean：应为单个匹配bean，但找到2个

我是春天3.2。这是我的配置文件

 <bean id="legacyDataSource" name="legacydb" class="org.springframework.jdbc.datasource.DriverManagerDataSource" lazy-init="true">
    <property name="driverClassName" value="${jdbc.legacy.driverClassName}" />
    <property name="url" value="${jdbc.legacy.url}" />  
    <property name="username" value="${jdbc.legacy.username}" />
    <property name="password" value="${jdbc.legacy.password}" />
</bean>

 <bean id="ls360DataSource" name="Ls360db" class="org.springframework.jdbc.datasource.DriverManagerDataSource" lazy-init="true" >
    <property name="driverClassName" value="${jdbc.ls360.driverClassName}" />
    <property name="url" value="${jdbc.ls360.url}" />  
    <property name="username" value="${jdbc.ls360.username}" />
    <property name="password" value="${jdbc.ls360.password}" />
</bean>

<bean id="legacyTransactionManager" class="org.springframework.orm.jpa.JpaTransactionManager">
    <property name="entityManagerFactory" ref="legacyEmf"/>
</bean>

<bean id="ls360TransactionManager" class="org.springframework.orm.jpa.JpaTransactionManager">
    <property name="entityManagerFactory" ref="ls360Emf"/>
</bean>

<tx:annotation-driven transaction-manager="transactionManager" />

<bean id="legacyEmf" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean" >
    <property name="dataSource" ref="legacyDataSource" />
    <property name="jpaVendorAdapter" ref="vendorAdaptor" />         
    <property name="packagesToScan" value="com.softech.ls360.integration.regulators.plcb.domain"/>
    <property name="jpaProperties">
        <props>
            <prop key="hibernate.dialect">org.hibernate.dialect.SQLServerDialect</prop>
            <prop key="hibernate.max_fetch_depth">3</prop>
            <prop key="hibernate.jdbc.fetch_size">50</prop>
            <prop key="hibernate.jdbc.batch_size">10</prop>
            <prop key="hibernate.show_sql">true</prop>              
        </props>        
    </property>
</bean>   

<bean id="ls360Emf" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean" >
    <property name="dataSource" ref="ls360DataSource" />
    <property name="jpaVendorAdapter" ref="vendorAdaptor" />         
    <property name="packagesToScan" value="com.softech.ls360.integration.regulators.plcb.domain"/>
    <property name="jpaProperties">
        <props>
            <prop key="hibernate.dialect">org.hibernate.dialect.SQLServerDialect</prop>
            <prop key="hibernate.max_fetch_depth">3</prop>
            <prop key="hibernate.jdbc.fetch_size">50</prop>
            <prop key="hibernate.jdbc.batch_size">10</prop>
            <prop key="hibernate.show_sql">true</prop>              
        </props>        
    </property>
</bean>
<context:component-scan base-package="....db" />

为什么我会犯这个错误。我怎样才能解决它

---

谢谢

我今天也有同样的问题。通过以下操作解决了此问题：

首先，我将参数unitName添加到@PersistenceContext的两个实体管理器属性中：

@PersistenceContext(unitName="appPU")
@Qualifier(value = "appEntityManagerFactory")
private EntityManager appEntityManager;

@PersistenceContext(unitName="managerPU")
@Qualifier(value = "managerEntityManagerFactory")
private EntityManager managerEntityManager;

在我的配置文件中，我向bean定义添加了一个属性persistenceUnitName：

<bean id="appEntityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
    <property name="dataSource" ref="dataSource1" />
    <property name="persistenceUnitName" value="appPU" />
    <property name="packagesToScan" value="br.com.app.domain" />
    ...
</bean>

<bean id="managerEntityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
    <property name="dataSource" ref="dataSource2" />
    <property name="persistenceUnitName" value="managerPU" />
    <property name="packagesToScan" value="br.com.app.domain" />
    ...
</bean>

...
...

另外，我想再添加一条有用的评论：您需要扩展web应用程序“web.xml”文件中的部分。由于现在有2个实体管理器，因此需要2个OpenEntityManagerViewFilters。看看这个例子：

<filter>
  <filter-name>OpenEntityManagerInViewFilter1</filter-name>
  <filter-class>org.springframework.orm.jpa.support.OpenEntityManagerInViewFilter</filter-class>
     <init-param>
         <param-name>entityManagerFactoryBeanName</param-name>
         <param-value>appEntityManagerFactory</param-value>
    </init-param>
</filter>

<filter-mapping>
    <filter-name>OpenEntityManagerInViewFilter1</filter-name>
    <url-pattern>/*</url-pattern>
    </filter-mapping>


<filter>
  <filter-name>OpenEntityManagerInViewFilter2</filter-name>
  <filter-class>org.springframework.orm.jpa.support.OpenEntityManagerInViewFilter</filter-class>
    <init-param>
        <param-name>entityManagerFactoryBeanName</param-name>
        <param-value>managerEntityManagerFactory</param-value>
    </init-param>
  </filter>

<filter-mapping>

<filter-name>OpenEntityManagerInViewFilter2</filter-name>
 <url-pattern>/*</url-pattern>
</filter-mapping>

OpenEntityManager视图过滤器1
org.springframework.orm.jpa.support.OpenEntityManagerInViewFilter
EntityManager工厂名称
外观管理工厂
OpenEntityManager视图过滤器1
/*
OpenEntityManager视图过滤器2
org.springframework.orm.jpa.support.OpenEntityManagerInViewFilter
EntityManager工厂名称
managerEntityManagerFactory
OpenEntityManager视图过滤器2
/*

请注意appEntityManagerFactory中的名称“appEntityManagerFactory”= 我也面临着这样的问题并解决了它。请执行以下操作以解决此错误：

将以下行添加到两个模式的所有实体类中

@PersistenceContext(unitName="<persistenceUnit>")
transient EntityManager entityManager;

@PersistenceContext（unitName=”“）
瞬态实体管理器；

---

是您在

persistence.xml

文件中定义的持久化单元的名称。

这很奇怪，因为我今天遇到了完全相同的问题，但@Qualifier不起作用=（.我非常确定我的所有配置都正常，您可以发布整个应用程序上下文吗？谢谢。该解决方案不适用于junit测试（

AbstractTransactionalJUnit4S普林gContextTests

），知道为什么吗？非常感谢！这对我很有效。使用unitName的

@PersistenceContex

就足以解决注入问题。不必使用

@Qualifier

，因为您注入的是EntityManager，而不是EntityManager工厂。这里同样的问题，但建议的解决方案不适用于单元测试。您尝试过吗spring junit测试？

<filter>
  <filter-name>OpenEntityManagerInViewFilter1</filter-name>
  <filter-class>org.springframework.orm.jpa.support.OpenEntityManagerInViewFilter</filter-class>
     <init-param>
         <param-name>entityManagerFactoryBeanName</param-name>
         <param-value>appEntityManagerFactory</param-value>
    </init-param>
</filter>

<filter-mapping>
    <filter-name>OpenEntityManagerInViewFilter1</filter-name>
    <url-pattern>/*</url-pattern>
    </filter-mapping>


<filter>
  <filter-name>OpenEntityManagerInViewFilter2</filter-name>
  <filter-class>org.springframework.orm.jpa.support.OpenEntityManagerInViewFilter</filter-class>
    <init-param>
        <param-name>entityManagerFactoryBeanName</param-name>
        <param-value>managerEntityManagerFactory</param-value>
    </init-param>
  </filter>

<filter-mapping>

<filter-name>OpenEntityManagerInViewFilter2</filter-name>
 <url-pattern>/*</url-pattern>
</filter-mapping>

@PersistenceContext(unitName="<persistenceUnit>")
transient EntityManager entityManager;