Sql server 2005 检索ARITHABORT的当前值

我正在调试一个奇怪的行为，它似乎与ARITHABORT有关。如何检索活动连接的ARITHABORT的当前值

干杯， 阿希姆

---

，这取决于它是打开还是关闭

@@OPTIONS

允许您获取为当前会话设置的当前值的a位字段。
可以使用以下脚本解释位字段

DECLARE @options INT 
SELECT @options = @@OPTIONS 

PRINT @options
IF ( (1 & @options) = 1 ) PRINT 'DISABLE_DEF_CNST_CHK' 
IF ( (2 & @options) = 2 ) PRINT 'IMPLICIT_TRANSACTIONS' 
IF ( (4 & @options) = 4 ) PRINT 'CURSOR_CLOSE_ON_COMMIT' 
IF ( (8 & @options) = 8 ) PRINT 'ANSI_WARNINGS' 
IF ( (16 & @options) = 16 ) PRINT 'ANSI_PADDING' 
IF ( (32 & @options) = 32 ) PRINT 'ANSI_NULLS' 
IF ( (64 & @options) = 64 ) PRINT 'ARITHABORT' 
IF ( (128 & @options) = 128 ) PRINT 'ARITHIGNORE'
IF ( (256 & @options) = 256 ) PRINT 'QUOTED_IDENTIFIER' 
IF ( (512 & @options) = 512 ) PRINT 'NOCOUNT' 
IF ( (1024 & @options) = 1024 ) PRINT 'ANSI_NULL_DFLT_ON' 
IF ( (2048 & @options) = 2048 ) PRINT 'ANSI_NULL_DFLT_OFF' 
IF ( (4096 & @options) = 4096 ) PRINT 'CONCAT_NULL_YIELDS_NULL' 
IF ( (8192 & @options) = 8192 ) PRINT 'NUMERIC_ROUNDABORT' 
IF ( (16384 & @options) = 16384 ) PRINT 'XACT_ABORT' 

DECLARE @options INT 
SELECT @options = @@OPTIONS 

PRINT @options
IF ( (1 & @options) = 1 ) PRINT 'DISABLE_DEF_CNST_CHK' 
IF ( (2 & @options) = 2 ) PRINT 'IMPLICIT_TRANSACTIONS' 
IF ( (4 & @options) = 4 ) PRINT 'CURSOR_CLOSE_ON_COMMIT' 
IF ( (8 & @options) = 8 ) PRINT 'ANSI_WARNINGS' 
IF ( (16 & @options) = 16 ) PRINT 'ANSI_PADDING' 
IF ( (32 & @options) = 32 ) PRINT 'ANSI_NULLS' 
IF ( (64 & @options) = 64 ) PRINT 'ARITHABORT' 
IF ( (128 & @options) = 128 ) PRINT 'ARITHIGNORE'
IF ( (256 & @options) = 256 ) PRINT 'QUOTED_IDENTIFIER' 
IF ( (512 & @options) = 512 ) PRINT 'NOCOUNT' 
IF ( (1024 & @options) = 1024 ) PRINT 'ANSI_NULL_DFLT_ON' 
IF ( (2048 & @options) = 2048 ) PRINT 'ANSI_NULL_DFLT_OFF' 
IF ( (4096 & @options) = 4096 ) PRINT 'CONCAT_NULL_YIELDS_NULL' 
IF ( (8192 & @options) = 8192 ) PRINT 'NUMERIC_ROUNDABORT' 
IF ( (16384 & @options) = 16384 ) PRINT 'XACT_ABORT'