Sql server 2012 具有Group By的列名称不明确

对于下面的查询，我有

不明确的列名“Item”

错误。但是，我已经输入了所需的格式，因为参数位于列的开头

        SELECT  
          [Country Code],
          Item, 
          [FE SSO], 
          [Newest Job Number],
          [Newest Transaction Date],
          Z.ConsignDate AS [ConsignDate],
        FROM DailyOnhand

        LEFT JOIN 
            (SELECT 
              [Job Number], 
              [Item],
              Min([Transaction Day]) AS ConsignDate
            FROM vwAllTxns
            GROUP BY [Job Number], [Item]) Z 
                  ON vwDailyOnhand_v2.[Newest Job Number] = Z.[Job Number] 
                     AND vwDailyOnhand_v2.[Item] = Z.[Item]

感谢您的帮助。

---

谢谢大家!

您需要在

选择中的
项目
前面加上该项目来源表的名称/别名

SELECT  
      d.[Country Code],
      d.Item, 
      d.[FE SSO], 
      d.[Newest Job Number],
      d.[Newest Transaction Date],
      Z.ConsignDate AS [ConsignDate],
    FROM DailyOnHand d
      LEFT JOIN 
        (SELECT 
          v.[Job Number], 
          v.[Item],
          Min(v.[Transaction Day]) AS ConsignDate
        FROM vwAllTxns v
        GROUP BY v.[Job Number], v.[Item]
        ) Z 
              ON d.[Newest Job Number] = Z.[Job Number] 
                 AND d.[Item] = Z.[Item]

您的
from
指定了
dailonhand
，但您的
on
指定了
vwdailonhand\u v2
，我删除了后者并使用了一个别名。
两个表中可能都有一个item列，因此需要事先指定它。此外，子查询也不需要，您可以在分区上使用MIN（）。。用一个简单的连接
    SELECT  
      [Country Code],
      Z.[Item], -- Need to specify which item is source 
      [FE SSO], 
      [Newest Job Number],
      [Newest Transaction Date],
      Z.ConsignDate AS [ConsignDate],
    FROM DailyOnhand

    LEFT JOIN 
        (SELECT 
          [Job Number], 
          [Item],
          Min([Transaction Day]) AS ConsignDate
        FROM vwAllTxns
        GROUP BY [Job Number], [Item]) Z 
              ON vwDailyOnhand_v2.[Newest Job Number] = Z.[Job Number] 
                 AND vwDailyOnhand_v2.[Item] = Z.[Item]