Sql server 2012 比较时差的SQL查询
我使用了下面的代码进行查询，并得到了显示的输出。现在，我想查询如下所述。我该怎么做 查找代码2，检查同一ItemID中代码1是否在代码2之后。如果是，比较时差。如果时间差小于10秒，则显示两个比较的行 预期结果Sql server 2012 比较时差的SQL查询,sql-server-2012,Sql Server 2012,我使用了下面的代码进行查询，并得到了显示的输出。现在，我想查询如下所述。我该怎么做 查找代码2，检查同一ItemID中代码1是否在代码2之后。如果是，比较时差。如果时间差小于10秒，则显示两个比较的行 预期结果 Date Code ItemName ItemID 2017-01-06 11:00:49.000 2 B 98 2017-01-06 11:00:49.000 1 A 98 dbfiddle
Date Code ItemName ItemID
2017-01-06 11:00:49.000 2 B 98
2017-01-06 11:00:49.000 1 A 98
dbfiddle是的，从结果中。第一条记录应该是代码2？@McNets添加了预期的result@Djuka不可以。它可以是1，有时记录可以有代码2，然后又有代码2。所以，我需要检查代码1是否在代码2之后。在ItemID=98的输出中，您有10多条记录。它应该只有2条记录？比较必须在同一个ItemId内。因此，2017年1月6日20:24:55 | 2 | B | 98也应该被取消。此外，ItemId 99仍在显示超过10秒的数据。请澄清您的问题，哪些行不应返回？因为2017-01-06 20:24:55.000 2 B 98和2017-03-14 16:37:42.000 2 B 99，第二个有另一个项目我很抱歉。我没有解释清楚。检查我的输出和预期结果。比较必须在同一个ItemId内进行。当我对数据使用此查询时，我意识到某些具有不同ItemId的数据会进行比较。如果您可以发布更改，我将进行查看。
Date Code ItemName ItemID
2017-01-06 11:00:49.000 2 B 98
2017-01-06 11:00:49.000 1 A 98
2017-01-06 11:00:55.000 2 B 98
2017-01-06 12:01:56.000 1 A 98
2017-01-06 12:02:37.000 2 B 98
2017-01-06 12:03:49.000 1 A 98
2017-01-06 12:05:44.000 2 B 98
2017-01-06 20:24:32.000 1 A 98
2017-01-06 20:24:55.000 2 B 98
2017-03-14 16:37:42.000 2 B 99
2017-03-14 17:40:24.000 1 A 99
2017-03-14 17:40:25.000 2 B 99
2017-03-14 21:28:46.000 1 A 99
2017-03-15 08:03:07.000 2 B 99
2017-03-15 10:43:00.000 1 A 99
2017-03-15 12:01:17.000 2 B 99
2017-03-15 14:18:19.000 2 B 99
Date Code ItemName ItemID
2017-01-06 11:00:49.000 2 B 98
2017-01-06 11:00:49.000 1 A 98
create table results ([Date] datetime, Code int, ItemName char(1), ItemID int);
insert into results values
('2017-01-06 11:00:49', 2, 'B', 98),
('2017-01-06 11:00:49', 1, 'A', 98),
('2017-01-06 11:00:55', 2, 'B', 98),
('2017-01-06 12:01:56', 1, 'A', 98),
('2017-01-06 12:01:58', 1, 'A', 98),
('2017-01-06 12:02:37', 2, 'B', 98),
('2017-01-06 12:03:49', 1, 'A', 98),
('2017-01-06 12:05:44', 2, 'B', 98),
('2017-01-06 20:24:32', 1, 'A', 98),
('2017-01-06 20:24:55', 2, 'B', 98),
('2017-03-07 00:02:27', 1, 'A', 91),
('2017-03-07 00:02:27', 1, 'A', 58),
('2017-03-14 16:37:42', 2, 'B', 99),
('2017-03-14 17:40:24', 1, 'A', 99),
('2017-03-14 17:40:38', 2, 'B', 99),
('2017-03-14 21:28:46', 1, 'A', 99),
('2017-03-15 08:03:07', 2, 'B', 99),
('2017-03-15 10:43:00', 1, 'A', 99),
('2017-03-15 12:01:17', 2, 'B', 99),
('2017-03-15 14:18:19', 1, 'A', 99);
--= set a reset point when ItemId changes, or there is no correlative (2,1) couples
--= keep in mind this solution assumes that first Code must be 2
--
WITH SetReset AS
(
SELECT [Date], Code, ItemName, ItemId,
CASE WHEN LAG([ItemId]) OVER (PARTITION BY ItemId ORDER BY [Date]) IS NULL
OR ([Code] = 2)
OR ([Code] = COALESCE(LAG([Code]) OVER (PARTITION BY ItemId ORDER BY [Date]), [Code]))
THEN 1 END is_reset
FROM results
)
--
--= set groups according to reset points
--
, SetGroup AS
(
SELECT [Date], Code, ItemName, ItemId,
COUNT(is_reset) OVER (ORDER BY [ItemId], [Date]) grp
FROM SetReset
)
--
--= calcs diff date for each group
, CalcSeconds AS
(
SELECT [Date], Code, ItemName, ItemId,
DATEDIFF(SECOND, MIN([Date]) OVER (PARTITION BY grp), MAX([Date]) OVER (PARTITION BY grp)) dif_sec,
COUNT(*) OVER (PARTITION BY grp) num_items
FROM SetGroup
)
--
--= selects those rows with 2 items by group and date diff less than 10 sec
SELECT [Date], Code, ItemName, ItemId
FROM CalcSeconds
WHERE dif_sec < 10
AND num_items = 2
;
GO