Sql server SQL Server-选择一列匹配但另一列不匹配的行
我需要为相同的列名选择数据类型不同的行 这是我的数据集。高亮显示的行应包含在结果中 我尝试了以下SQL脚本,但它没有返回预期的结果Sql server SQL Server-选择一列匹配但另一列不匹配的行,sql-server,Sql Server,我需要为相同的列名选择数据类型不同的行 这是我的数据集。高亮显示的行应包含在结果中 我尝试了以下SQL脚本,但它没有返回预期的结果 SELECT COLUMN_NAME, DATA_TYPE FROM tablecolumns WHERE COLUMN_NAME IN ( SELECT COLUMN_NAME FROM tablecolumns WHERE COLUMN_NAME IN ( SELECT COLUMN_NAME FROM
SELECT COLUMN_NAME, DATA_TYPE
FROM tablecolumns
WHERE COLUMN_NAME IN (
SELECT COLUMN_NAME
FROM tablecolumns
WHERE COLUMN_NAME IN (
SELECT COLUMN_NAME
FROM tablecolumns
GROUP BY DATA_TYPE, COLUMN_NAME
HAVING count(*) = 1)
GROUP BY COLUMN_NAME
HAVING count(*) > 1)
ORDER BY COLUMN_NAME
以下是指向SQL FIDLE的链接如果您使用的是SQL Server 2008或更高版本,则可以使用COUNT()窗口函数来实现所需的功能:
WITH CTE_DistinctColumnsAndTypes
AS
(
SELECT COLUMN_NAME
,DATA_TYPE
FROM tablecolumns
GROUP BY COLUMN_NAME, DATA_TYPE
),
CTE_ColumnsAndTypeCount
AS
(
SELECT COLUMN_NAME
,DATA_TYPE
,COUNT(DATA_TYPE) OVER (PARTITION BY COLUMN_NAME) AS TypeCount
FROM CTE_DistinctColumnsAndTypes
)
SELECT COLUMN_NAME
,DATA_TYPE
FROM CTE_ColumnsAndTypeCount
WHERE TypeCount > 1
首先,您可以使用GROUP BY和HAVING获得具有多个数据类型的列名:
SELECT COLUMN_NAME
FROM tablecolumns
GROUP BY COLUMN_NAME
HAVING count(DISTINCT DATA_TYPE) > 1
然后,您可以使用where IN(..)显示结果中列名称所在的所有行
或者使用内部连接
SELECT a.COLUMN_NAME , a.DATA_TYPE
FROM tablecolumns a
INNER JOIN (
SELECT b.COLUMN_NAME
FROM tablecolumns b
Group by b.COLUMN_NAME
HAVING count(DISTINCT b.DATA_TYPE) > 1
) c ON c.COLUMN_NAME = a.COLUMN_NAME
ORDER BY a.COLUMN_NAME
SELECT a.COLUMN_NAME , a.DATA_TYPE
FROM tablecolumns a
INNER JOIN (
SELECT b.COLUMN_NAME
FROM tablecolumns b
Group by b.COLUMN_NAME
HAVING count(DISTINCT b.DATA_TYPE) > 1
) c ON c.COLUMN_NAME = a.COLUMN_NAME
ORDER BY a.COLUMN_NAME