Sql server 根据另一列的值选择没有特定值的行

我的问题是：

我有一张桌子

     SkillID            EmpCode
    ------------------------------
    2                   A101
    4                   A101
    5                   A101
    8                   A101
    4                   A102
    3                   A102
    1                   A102
    6                   A102
    5                   A102
    7                   A102

现在我必须选择没有skillid1、6和7的EmpCode。 在本例中，应给出EmpCodeA101作为结果。 只有不包括SkillID 1、6和7的EmpCodes才应该是结果

尝试：

SELECT EmpCode
FROM mytable
GROUP BY EmpCode
HAVING COUNT(CASE WHEN SkillID IN (1, 6, 7) THEN 1 END) = 0

您也可以使用

不存在

：

SELECT DISTINCT EmpCode
FROM mytable AS t1
WHERE NOT EXISTS (
  SELECT 1
  FROM mytable AS t2
  WHERE t1.EmpCode = t2.EmpCode AND t2.SkillID IN (1, 6, 7) )

试试：

SELECT EmpCode
FROM mytable
GROUP BY EmpCode
HAVING COUNT(CASE WHEN SkillID IN (1, 6, 7) THEN 1 END) = 0

您也可以使用

不存在

：

SELECT DISTINCT EmpCode
FROM mytable AS t1
WHERE NOT EXISTS (
  SELECT 1
  FROM mytable AS t2
  WHERE t1.EmpCode = t2.EmpCode AND t2.SkillID IN (1, 6, 7) )

---

下面的代码是t-sql：

SELECT DISTINCT EmpCode
FROM Table1
WHERE SkillID NOT IN (1, 6, 7)

---

以下代码在t-sql中：

SELECT DISTINCT EmpCode
FROM Table1
WHERE SkillID NOT IN (1, 6, 7)