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Sql server 用于删除6天前数据的存储过程_Sql Server_Sql Server 2008 - Fatal编程技术网

Sql server 用于删除6天前数据的存储过程

Sql server 用于删除6天前数据的存储过程,sql-server,sql-server-2008,Sql Server,Sql Server 2008,这是我的存储过程 ALTER procedure [dbo].[mtk_sp_Deletion]as begin delete from tbl1 where DateModified< getdate() - 6 delete tbl2 where DateModified < getdate() - 6 delete tbl3 where DateModified < getdate() - 6 end 将过程[dbo].[mtk\

这是我的存储过程

ALTER procedure [dbo].[mtk_sp_Deletion]as
begin
   delete from tbl1
   where DateModified< getdate() - 6

   delete tbl2
   where DateModified < getdate() - 6

   delete tbl3
   where DateModified < getdate() - 6
end
将过程[dbo].[mtk\u sp\u删除]更改为
开始
从tbl1中删除
其中DateModified
现在我只是硬编码值“6”,但我想实现读取文本文件(文本文件包含此值,例如:6、10或12),并获得值,将其传递到此处以删除

请有人帮我如何做到这一点


提前感谢

将值作为参数传递:

ALTER procedure [dbo].[mtk_sp_Deletion](
  @nDays int = 6
)
as

begin
   delete from tbl1
   where DateModified< getdate() - @nDays

   delete tbl2
   where DateModified < getdate() - @nDays

   delete tbl3
   where DateModified < getdate() - @nDays

end
ALTER procedure[dbo]。[mtk\u sp\u删除](
@nDays int=6
)
作为
开始
从tbl1中删除
其中DateModified
如果您想从文本文件中读取该值,请在SO上搜索,您将得到许多答案,例如: