Sql server SSRS-分组-文件夹层次结构

我有下表，数据如下：， 表名：tblFolder

FolderId | FolderName | ParentFolderId 1 | A | Null 2 | B | 1 3 | C | 2 4 | D | Null 5 | E | 4 FolderId | FolderName | ParentFolderId 1 | A |空 2 | B | 1 3 | C | 2 4 | D |空 5 | E | 4 ParentFolderId将FolderId用作ex的父文件夹。文件夹a是文件夹B的父文件夹

我想以以下格式显示上述数据是SSRS报告

-A -B -C -D -E -A -B -C -D -E 所以我的问题是以上面的格式显示报表我的sql查询应该是什么，或者我应该采用什么方法？

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我不想使用递归层次结构，我想通过使用列分组来实现这一点，我们可能需要使用CTE并使用字符串进行一些替换工作，如下所示：

;With cte as 
(
    Select *, convert(varchar(10), Concat('-',FolderName)) as Levl from #Folder where ParentFolderId is null

    Union all

    Select f.Folderid, f.FolderName, f.ParentFolderId, convert(varchar(10),concat(' ',Replace(c.Levl, right(c.levl,len(f.folderName)),f.folderName))) as Levl from cte c inner join #Folder f
        on c.Folderid = f.ParentFolderId
)
select Levl from cte
order by Folderid

    +------+
    | Levl |
    +------+
    | -A   |
    |  -B  |
    |   -C |
    | -D   |
    |  -E  |
    +------+

输出如下：

;With cte as 
(
    Select *, convert(varchar(10), Concat('-',FolderName)) as Levl from #Folder where ParentFolderId is null

    Union all

    Select f.Folderid, f.FolderName, f.ParentFolderId, convert(varchar(10),concat(' ',Replace(c.Levl, right(c.levl,len(f.folderName)),f.folderName))) as Levl from cte c inner join #Folder f
        on c.Folderid = f.ParentFolderId
)
select Levl from cte
order by Folderid

    +------+
    | Levl |
    +------+
    | -A   |
    |  -B  |
    |   -C |
    | -D   |
    |  -E  |
    +------+

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下面是一个标准的递归cte，但我们添加了一个生成的序列以确保正确的表示顺序/嵌套

--为2008年调整--

示例

Declare @YourTable Table ([FolderId] varchar(50),[FolderName] varchar(50),[ParentFolderId] varchar(50))
Insert Into @YourTable Values 
 (1,'A',NULL)
,(2,'B',1)
,(3,'C',2)
,(4,'D',NULL)
,(5,'E',4)

Declare @Top    int         = null      --<<  Sets top of Hier Try 2 
Declare @Nest   varchar(25) = '|-----'  --<<  Optional: Added for readability

;with cteP as (
      Select Seq  = cast(10000+Row_Number() over (Order by FolderName) as varchar(500))
            ,FolderId
            ,ParentFolderId 
            ,Lvl=1
            ,FolderName 
      From   @YourTable 
      Where  IsNull(@Top,-1) = case when @Top is null then isnull(ParentFolderId ,-1) else FolderId end
      Union  All
      Select Seq  = cast(p.Seq+'.'+cast(10000+Row_Number() over (Order by r.FolderName) as varchar(25) )  as varchar(500))
            ,r.FolderId
            ,r.ParentFolderId 
            ,p.Lvl+1
            ,r.FolderName 
      From   @YourTable r
      Join   cteP p on r.ParentFolderId  = p.FolderId)
Select A.FolderId
      ,A.ParentFolderId 
      ,A.Lvl
      ,FolderName = Replicate(@Nest,A.Lvl-1) + A.FolderName
 From cteP A
 Order By Seq

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您的任务是计算标识，即前导空格的计数。恐怕最好的方法是递归计算检查SSRS层次结构报告谢谢回复。在SSRS中，我确实希望显示为FolderName格式，那么在哪一列上可以设置行摸索？