Sql server MSSQL-检查不存在其他值的位置

相对简单的一个（我想），但我不太确定怎么做

我有一组数据，我想返回结果不好的ID，例如，在下面的集合中，只应返回100。200应排除在外，因为其结果为“良好”

    UID ID  Date/Time           Result
    1   100 02/04/2014 08:00    Bad
    2   200 02/04/2014 08:05    Bad
    3   100 03/04/2014 08:10    Bad
    4   100 03/04/2014 08:20    Bad
    5   200 03/04/2014 09:00    Bad
    6   200 03/04/2014 18:00    Good

谢谢你试试这个

SELECT ID FROM TABLE1
WHERE RESULT = 'BAD' AND 
      NOT EXISTS (SELECT * FROM WHERE RESULT = 'GOOD')

---

翻译标题：使用

不存在
：

SELECT t.*
FROM dbo.TableName t
WHERE NOT EXISTS
(
   SELECT 1 FROM dbo.TableName t2
   WHERE t.ID = t2.ID AND t2.Result = 'Good'
)


或
全部
：

SELECT t.*
FROM dbo.TableName t
WHERE 'Bad' = ALL(
   SELECT t2.Result FROM dbo.TableName t2
   WHERE t.ID = t2.ID 
)

如果您想要完整的行，而不仅仅是
ID
s，您可以使用两个窗口聚合：

declare @t table (UID int,ID int,dt datetime,Result varchar(19))
insert into @t(UID,ID,dt,Result) values
(1,100,'2014-04-02T08:00:00','Bad'),
(2,200,'2014-04-02T08:05:00','Bad'),
(3,100,'2014-04-03T08:10:00','Bad'),
(4,100,'2014-04-03T08:20:00','Bad'),
(5,200,'2014-04-03T09:00:00','Bad'),
(6,200,'2014-04-03T18:00:00','Good')

;With MinMax as (
    select *,
        MIN(Result) OVER (PARTITION BY ID) as minR,
        MAX(Result) OVER (PARTITION BY ID) as maxR
    from @t
)
select UID,ID,dt,Result from MinMax
where minR = maxR and minR = 'Bad'

因为当特定行的最小值和最大值相等时，您知道所有观察到的值都相等

结果:

UID         ID          dt                      Result
----------- ----------- ----------------------- -------------------
3           100         2014-04-03 08:10:00.000 Bad
4           100         2014-04-03 08:20:00.000 Bad
1           100         2014-04-02 08:00:00.000 Bad

是否希望ID的不同值不与良好结果关联？
差不多

SELECT DISTINCT ID
FROM   myTable
WHERE  ID NOT IN (SELECT ID FROM myTable WHERE Result = 'Good')

我们应该做到这一点

如果需要“坏”ID的所有数据，则

SELECT *
FROM   myTable
WHERE  ID NOT IN (SELECT ID FROM myTable WHERE Result = 'Good')

你就不能用RESULT='BAD'吗？不需要在里面。