Sql server 如何避免group by中的重复记录?
下面的查询用于查找产品的最低价格 我用字段可用\u计数更新我的表@Rates 但由于分组的原因,结果是重复的 我如何更新这个Sql server 如何避免group by中的重复记录?,sql-server,tsql,sql-server-2005,group-by,Sql Server,Tsql,Sql Server 2005,Group By,下面的查询用于查找产品的最低价格 我用字段可用\u计数更新我的表@Rates 但由于分组的原因,结果是重复的 我如何更新这个 SET NOCOUNT ON DECLARE @Products TABLE (product_id VarChar(50),product_name VarChar(50) ) INSERT INTO @Products Values ('1','Pen'); INSERT INTO @Products Values ('2','Pencil'); INSERT INT
SET NOCOUNT ON DECLARE @Products TABLE (product_id VarChar(50),product_name VarChar(50) )
INSERT INTO @Products Values ('1','Pen');
INSERT INTO @Products Values ('2','Pencil');
INSERT INTO @Products Values ('3','ASchool Bag');
INSERT INTO @Products Values ('4','Book');
INSERT INTO @Products Values ('5','Pencil Box');
SET NOCOUNT ON DECLARE @Rates TABLE (product_id VarChar(50),price int, Avail_Count VarChar(50))
INSERT INTO @Rates Values ('1','10','1');
INSERT INTO @Rates Values ('3','5','5');
INSERT INTO @Rates Values ('1','5','6');
INSERT INTO @Rates Values ('4','20','3');
INSERT INTO @Rates Values ('4','15','2');
INSERT INTO @Rates Values ('5','30','1');
;WITH CTE AS (
SELECT
count(*) over() Total_Record,
p.product_id, p.product_name, ISNULL(MIN(r.price), 0) AS MinPrice,
case when ISNULL(MIN(r.price), 0) > 0 then 1 else 0 end as sortOrder,
R.Avail_Count
FROM
@Products p LEFT OUTER JOIN @Rates r
ON
r.product_id = p.product_id
GROUP BY
p.product_id, p.product_name,R.Avail_Count
),ROWNUM as (Select *,ROW_NUMBER() OVER (ORDER BY sortOrder desc, MinPrice asc,Product_name)
AS RowNumber from CTE )
Select * from ROWNUM
我不知道你想展示哪一个。您得到的是重复项,因为您将avail_count包括在GROUP BY中,并且它们具有不同的值。是否希望avail_计数值恰好与最小值位于同一行上?如果是,则:
;WITH x AS
(
SELECT
Total_Record = COUNT(*) OVER(),
rn = ROW_NUMBER() OVER (PARTITION BY p.product_id ORDER BY r.price),
p.product_id,
p.product_name,
MinPrice = COALESCE(r.price, 0),
sortOrder = CASE WHEN COALESCE(r.price, 0) > 0 THEN 1 ELSE 0 END
FROM
@Products AS p
LEFT OUTER JOIN
@Rates AS r
ON r.product_id = p.product_id
)
SELECT
Total_Record,
product_id,
product_name,
MinPrice,
sortOrder,
RowNumber = ROW_NUMBER() OVER (ORDER BY sortOrder DESC, MinPrice, product_name)
FROM x WHERE rn = 1;
如果没有,那么您需要显示实际的所需结果,而不仅仅是解释您不想要重复的结果。我不确定您想要显示哪个可用计数。您得到的是重复项,因为您将avail_count包括在GROUP BY中,并且它们具有不同的值。是否希望avail_计数值恰好与最小值位于同一行上?如果是,则:
;WITH x AS
(
SELECT
Total_Record = COUNT(*) OVER(),
rn = ROW_NUMBER() OVER (PARTITION BY p.product_id ORDER BY r.price),
p.product_id,
p.product_name,
MinPrice = COALESCE(r.price, 0),
sortOrder = CASE WHEN COALESCE(r.price, 0) > 0 THEN 1 ELSE 0 END
FROM
@Products AS p
LEFT OUTER JOIN
@Rates AS r
ON r.product_id = p.product_id
)
SELECT
Total_Record,
product_id,
product_name,
MinPrice,
sortOrder,
RowNumber = ROW_NUMBER() OVER (ORDER BY sortOrder DESC, MinPrice, product_name)
FROM x WHERE rn = 1;
如果没有,则您需要显示实际的预期结果,而不仅仅是解释您不想要重复的结果。如何按照最低价格显示等效的“可用计数”。对不起,请根据样本数据显示预期结果。没有人想解决文字问题。如何根据MinPrice显示等效的“可用数量”。对不起,请根据示例数据显示所需结果。没有人想解决文字问题。