Tsql 从下一行的开始日期算起，当前行的驱动器结束日期

有人能帮我从开始日期创建结束日期吗

产品指的是一家公司进行测试，而该公司的产品在不同日期进行多次测试，并记录测试日期以确定产品状况，即结果ID。 我需要建立StartDate，它是testDate，EndDate，它是下一行的开始日期。但是，如果多个连续测试产生相同的OutcomeID，我只需要返回一行，其中包含第一个测试的开始日期和最后一个测试的结束日期。换句话说，如果结果ID在几个连续测试中没有改变。 这是我的数据集

DECLARE @ProductTests TABLE


(
  RequestID int not null,
  ProductID int not null,
  TestID int not null,
  TestDate datetime null,
  OutcomeID int 
)
insert into @ProductTests
(RequestID ,ProductID ,TestID ,TestDate ,OutcomeID )
select 1,2,22,'2005-01-21',10
union all
select 1,2,42,'2007-03-17',10
union all
select 1,2,45,'2010-12-25',10
union all
select 1,2,325,'2011-01-14',13
union all
select 1,2,895,'2011-08-10',15
union all
select 1,2,111,'2011-12-23',15
union all
select 1,2,636,'2012-05-02',10
union all
select 1,2,554,'2012-11-08',17
结果:
11月7日，但仍未得到答复
这就是我的解决方案
不是很漂亮，但很管用

我的提示是关于窗口、排名和聚合函数，如行数、排名、平均值、总和等。
当您想要编写raport，并在SQLServer2012中变得非常强大时，这些都是必不可少的

我还使用了CTE公共表表达式，但它可以写成子查询或临时表

;with cte ( ida, requestid, productid, testid, testdate, outcomeid) as
(
-- select rows where the outcome id is changing 
select b.* from 
(select  ROW_NUMBER() over( partition by requestid, productid order by testDate) as id, * from #ProductTests)a 
right outer join 
(select  ROW_NUMBER() over(partition by requestid, productid order by testDate) as id, * from #ProductTests) b
on a.requestID = b.requestID and a.productID = b.productID and a.id +1  = b.id 
where 1=1 
--or a.id = 1
and a.outcomeid <> b.outcomeid or b.outcomeid is null or a.id is null
)
select --*
a.RequestID,a.ProductID,a.TestDate AS StartDate   ,MIN(b.TestDate) AS EndDate ,a.OutcomeID  
from  cte a left join cte b on a.requestid = b.requestid and a.productid = b.productid and a.testdate < b.testdate
group by a.RequestID,a.ProductID ,a.OutcomeID,a.TestDate
order by StartDate

实际上，你的问题似乎有两个问题。一个是如何根据包含相同值的特定条件对序列行进行分组。另一个是标题中实际列出的，即如何使用下一行的StartDate作为当前行的EndDate

就个人而言，我会按照我提到的顺序解决这两个问题，所以我会首先解决分组问题。在这种情况下，正确分组数据的一种方法是使用双重排序，如下所示：

WITH partitioned AS (
  SELECT
    *,
    grp = ROW_NUMBER() OVER (PARTITION BY RequestID, ProductID            ORDER BY TestDate)
        - ROW_NUMBER() OVER (PARTITION BY RequestID, ProductID, OutcomeID ORDER BY TestDate)
  FROM @ProductTests
)
, grouped AS (
  SELECT
    RequestID,
    ProductID,
    StartDate = MIN(TestDate),
    OutcomeID
  FROM partitioned
  GROUP BY
    RequestID,
    ProductID,
    OutcomeID,
    grp
)
SELECT *
FROM grouped
;

这将为数据示例提供以下输出：

RequestID  ProductID  StartDate   OutcomeID
---------  ---------  ----------  ---------
1          2          2005-01-21  10
1          2          2011-01-14  13
1          2          2011-08-10  15
1          2          2012-05-02  10
1          2          2012-11-08  17

很明显，有一件事还没有完成，那就是结束日期，现在是关心它的时候了。再次使用ROW_NUMBER对分组CTE的结果集进行排名，然后在使用外部联接将结果集与自身联接时，使用联接条件中的排名：

WITH partitioned AS (
  SELECT
    *,
    grp = ROW_NUMBER() OVER (PARTITION BY RequestID, ProductID            ORDER BY TestDate)
        - ROW_NUMBER() OVER (PARTITION BY RequestID, ProductID, OutcomeID ORDER BY TestDate)
  FROM @ProductTests
)
, grouped AS (
  SELECT
    RequestID,
    ProductID,
    StartDate = MIN(TestDate),
    OutcomeID,
    rnk = ROW_NUMBER() OVER (PARTITION BY RequestID, ProductID ORDER BY MIN(TestDate))
  FROM partitioned
  GROUP BY
    RequestID,
    ProductID,
    OutcomeID,
    grp
)
SELECT
  g1.RequestID,
  g1.ProductID,
  g1.StartDate,
  g2.StartDate AS EndDate,
  g1.OutcomeID
FROM grouped g1
LEFT JOIN grouped g2
  ON g1.RequestID = g2.RequestID
 AND g1.ProductID = g2.ProductID
 AND g1.rnk = g2.rnk - 1
;

您可以尝试此查询，以验证它是否返回了您想要的输出。
非常感谢@Andriy M这是我所需要的。对不起，我不在家，不能早点答复。
;with cte ( ida, requestid, productid, testid, testdate, outcomeid) as
(
-- select rows where the outcome id is changing 
select b.* from 
(select  ROW_NUMBER() over( partition by requestid, productid order by testDate) as id, * from #ProductTests)a 
right outer join 
(select  ROW_NUMBER() over(partition by requestid, productid order by testDate) as id, * from #ProductTests) b
on a.requestID = b.requestID and a.productID = b.productID and a.id +1  = b.id 
where 1=1 
--or a.id = 1
and a.outcomeid <> b.outcomeid or b.outcomeid is null or a.id is null
)
select --*
a.RequestID,a.ProductID,a.TestDate AS StartDate   ,MIN(b.TestDate) AS EndDate ,a.OutcomeID  
from  cte a left join cte b on a.requestid = b.requestid and a.productid = b.productid and a.testdate < b.testdate
group by a.RequestID,a.ProductID ,a.OutcomeID,a.TestDate
order by StartDate

WITH partitioned AS (
  SELECT
    *,
    grp = ROW_NUMBER() OVER (PARTITION BY RequestID, ProductID            ORDER BY TestDate)
        - ROW_NUMBER() OVER (PARTITION BY RequestID, ProductID, OutcomeID ORDER BY TestDate)
  FROM @ProductTests
)
, grouped AS (
  SELECT
    RequestID,
    ProductID,
    StartDate = MIN(TestDate),
    OutcomeID
  FROM partitioned
  GROUP BY
    RequestID,
    ProductID,
    OutcomeID,
    grp
)
SELECT *
FROM grouped
;

RequestID  ProductID  StartDate   OutcomeID
---------  ---------  ----------  ---------
1          2          2005-01-21  10
1          2          2011-01-14  13
1          2          2011-08-10  15
1          2          2012-05-02  10
1          2          2012-11-08  17

WITH partitioned AS (
  SELECT
    *,
    grp = ROW_NUMBER() OVER (PARTITION BY RequestID, ProductID            ORDER BY TestDate)
        - ROW_NUMBER() OVER (PARTITION BY RequestID, ProductID, OutcomeID ORDER BY TestDate)
  FROM @ProductTests
)
, grouped AS (
  SELECT
    RequestID,
    ProductID,
    StartDate = MIN(TestDate),
    OutcomeID,
    rnk = ROW_NUMBER() OVER (PARTITION BY RequestID, ProductID ORDER BY MIN(TestDate))
  FROM partitioned
  GROUP BY
    RequestID,
    ProductID,
    OutcomeID,
    grp
)
SELECT
  g1.RequestID,
  g1.ProductID,
  g1.StartDate,
  g2.StartDate AS EndDate,
  g1.OutcomeID
FROM grouped g1
LEFT JOIN grouped g2
  ON g1.RequestID = g2.RequestID
 AND g1.ProductID = g2.ProductID
 AND g1.rnk = g2.rnk - 1
;