Sql server 使用不同的'组合两个查询；从'；表，但类似'；加入'；桌子

我试图将两个查询合并到一个结果集中

问题1：

SELECT t1.evalID, t2.[Order], COUNT(t2.StepID) AS 'Total Categories'
FROM Evals t1
JOIN Steps t2 ON t1.TemplateID = t2.TemplateID 
JOIN GradingCats t3 ON t2.StepID = t3.StepID 
GROUP BY t1.EvalID, t2.[Order]
ORDER BY t2.[Order]

问题2：

SELECT t4.EvaluatorID, t6.StepID, t6.[Order], COUNT(t4.Grade) AS 'Grades Entered'
FROM Grading t4
JOIN GradingCats t5 ON t4.GradingCatID = t5.GradingCatID 
JOIN Steps t6 ON t5.StepID = t6.StepID
GROUP BY t6.StepID, t4.EvaluatorID, t6.[Order]

我的最终目标是确定评估的哪些步骤缺少分数

编辑（样本数据）： 问题#1

问题2

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从第一个查询开始，该查询显示了与EVAL关联的所有步骤，您可以左外连接第二个查询，查询右侧为NULL的步骤将是缺少等级的步骤

为了做到这一点，您的表格中必须有某种方式将

评分

链接到

评估

。从你发布的代码中看，这个专栏并不明显，但我假设它在那里。也许是通过

GradingCats

在简短的psuedo代码中，仅说明我的意思：

SELECT ...
FROM Evals e
INNER JOIN Steps s ON e.TemplateID = s.TemplateID 
LEFT OUTER JOIN Grading g ON g.EvalID = e.EvalID  --use whatever means you have to show which Eval a Grade is from
LEFT OUTER JOIN Steps gs ON {join to Grading through GradingCats as in your second query}
WHERE gs.StepID IS NULL

在分析此查询的结果时，每个评估的所有步骤都将在

s.StepID

中，当同一行的

gs.StepID

为空时，这意味着该步骤没有得到分数

请注意，您不希望在此查询中执行任何分组，因为您需要行级分析。

一位同事（比我更了解数据）稍微修改了我的查询：

SELECT query1.stepID, Categories, Graded
FROM
(
    SELECT rs.stepid, COUNT(c.category) AS 'Categories'
    FROM Evals e
    JOIN RunScriptSteps rs ON e.TemplateID = rs.TemplateID
    JOIN GradingCats c ON rs.StepID = c.StepID
    WHERE EvalID = *(someNumber)*
    GROUP BY rs.stepid
)AS query1
LEFT JOIN
(
    SELECT s.StepID, COUNT(Grade) AS 'Graded'
    FROM Grading g
    JOIN GradingCats c ON g.GradingCatID = c.GradingCatID
    JOIN Steps s ON c.StepID = s.StepID
    WHERE EvalID = *(someNumber)*
    GROUP BY s.stepid
) AS query2
ON query1.stepid = query2.stepid
ORDER BY stepid ASC

---

这不像一个

UNION ALL

那么简单，是吗？如果没有，示例数据和期望的结果可能会有所帮助。另一方面，我建议尽快改掉使用别名的习惯，如

t1

，

t2

，…

t6

。您需要有类似的列（数据类型和计数。并在所有查询之间进行并集。不太确定这是否是并集。听起来更像是外部联接，但这是基于问题最后一句的猜测。没有样本数据和所需结果，问题不清楚，无法回答。@TabAlleman更正…我尝试了并集。我还尝试了一些外部联接作为示例好吧，但显然不是正确的。

SELECT ...
FROM Evals e
INNER JOIN Steps s ON e.TemplateID = s.TemplateID 
LEFT OUTER JOIN Grading g ON g.EvalID = e.EvalID  --use whatever means you have to show which Eval a Grade is from
LEFT OUTER JOIN Steps gs ON {join to Grading through GradingCats as in your second query}
WHERE gs.StepID IS NULL

SELECT query1.stepID, Categories, Graded
FROM
(
    SELECT rs.stepid, COUNT(c.category) AS 'Categories'
    FROM Evals e
    JOIN RunScriptSteps rs ON e.TemplateID = rs.TemplateID
    JOIN GradingCats c ON rs.StepID = c.StepID
    WHERE EvalID = *(someNumber)*
    GROUP BY rs.stepid
)AS query1
LEFT JOIN
(
    SELECT s.StepID, COUNT(Grade) AS 'Graded'
    FROM Grading g
    JOIN GradingCats c ON g.GradingCatID = c.GradingCatID
    JOIN Steps s ON c.StepID = s.StepID
    WHERE EvalID = *(someNumber)*
    GROUP BY s.stepid
) AS query2
ON query1.stepid = query2.stepid
ORDER BY stepid ASC