Sql server T-SQL创建一个ID列
我使用的是SQL Server 2008 R2,我有以下数据集:Sql server T-SQL创建一个ID列,sql-server,sql-server-2008,rank,row-number,contiguous,Sql Server,Sql Server 2008,Rank,Row Number,Contiguous,我使用的是SQL Server 2008 R2,我有以下数据集: +---------+--------------+--------------+----------+------------+------------+ | Dossier | refmouvement | refadmission | refunite | datedeb | datefin | +---------+--------------+--------------+----------+-------
+---------+--------------+--------------+----------+------------+------------+
| Dossier | refmouvement | refadmission | refunite | datedeb | datefin |
+---------+--------------+--------------+----------+------------+------------+
| P001234 | 2567 | 1234 | 227 | 2012-01-01 | 2012-01-02 |
| P001234 | 2568 | 1234 | 227 | 2012-01-02 | 2012-01-03 |
| P001234 | 2569 | 1234 | 224 | 2012-01-03 | 2012-01-06 |
| P001234 | 2570 | 1234 | 232 | 2012-01-06 | 2012-01-10 |
| P001234 | 2571 | 1234 | 232 | 2012-01-10 | 2012-01-15 |
| P001234 | 2572 | 1234 | 232 | 2012-01-15 | 2012-01-20 |
| P001234 | 2573 | 1234 | 232 | 2012-01-20 | 2012-01-25 |
| P001234 | 2574 | 1234 | 224 | 2012-01-25 | 2012-01-29 |
| P001234 | 2575 | 1234 | 227 | 2012-01-29 | 2012-02-05 |
| P001234 | 2576 | 1234 | 227 | 2012-02-05 | 2012-02-10 |
| P001234 | 2577 | 1234 | 232 | 2012-02-10 | 2012-02-15 |
| P001234 | 2578 | 1234 | 201 | 2012-02-15 | 2012-02-26 |
+---------+--------------+--------------+----------+------------+------------+
此数据集按datedeb
排序,也称为startdate
您可以注意到,这是一个连续的数据集,datefin
等于下一行的datedeb
我需要创建一个ID
列,该列将根据refundite
和datedeb
列提供唯一的ID,如下所示:
+----+---------+--------------+--------------+----------+------------+------------+
| ID | Dossier | refmouvement | refadmission | refunite | datedeb | datefin |
+----+---------+--------------+--------------+----------+------------+------------+
| 1 | P001234 | 2567 | 1234 | 227 | 2012-01-01 | 2012-01-02 |
| 1 | P001234 | 2568 | 1234 | 227 | 2012-01-02 | 2012-01-03 |
| 2 | P001234 | 2569 | 1234 | 224 | 2012-01-03 | 2012-01-06 |
| 3 | P001234 | 2570 | 1234 | 232 | 2012-01-06 | 2012-01-10 |
| 3 | P001234 | 2571 | 1234 | 232 | 2012-01-10 | 2012-01-15 |
| 3 | P001234 | 2572 | 1234 | 232 | 2012-01-15 | 2012-01-20 |
| 3 | P001234 | 2573 | 1234 | 232 | 2012-01-20 | 2012-01-25 |
| 4 | P001234 | 2574 | 1234 | 224 | 2012-01-25 | 2012-01-29 |
| 5 | P001234 | 2575 | 1234 | 227 | 2012-01-29 | 2012-02-05 |
| 5 | P001234 | 2576 | 1234 | 227 | 2012-02-05 | 2012-02-10 |
| 6 | P001234 | 2577 | 1234 | 232 | 2012-02-10 | 2012-02-15 |
| 7 | P001234 | 2578 | 1234 | 201 | 2012-02-15 | 2012-02-26 |
+----+---------+--------------+--------------+----------+------------+------------+
WITH CTEHelper AS
(SELECT ROW_NUMBER() OVER(ORDER BY datedeb) AS RowNum,
refunite,
datedeb
FROM dbo.Sometable),
CTERecursive AS (
SELECT crt.RowNum,
crt.refunite,
crt.datedeb,
1 AS Id -- Starting rank
FROM CTEHelper crt
WHERE crt.RowNum = 1
UNION ALL
SELECT crt.RowNum,
crt.refunite,
crt.datedeb,
CASE WHEN prev.refunite = crt.refunite THEN prev.Id ELSE prev.Id + 1 END
FROM CTEHelper crt INNER JOIN CTERecursive prev ON crt.RowNum = prev.RowNum + 1
)
SELECT crt.id,
s.*
FROM CTERecursive crt
JOIN Sometable s ON s.refunite = crt.refunite AND s.datedeb = crt.datedeb
我就是不能用RANK()
、ROW\u NUMBER()
或densite\u RANK()
函数或两者的组合来实现这一点,我到处都找过了,但什么也找不到,也许我没有使用正确的关键字,但我就是想不出来
任何帮助都将不胜感激
谢谢
以下是我迄今为止尝试过的代码:
SELECT
ROW_NUMBER() over(order by t1.[datedeb]) as [ID1],
dense_Rank() over(partition by t1.[refunite] order by t1.[datedeb]) as [ID2],
t1.[Dossier]
,t1.[refmouvement]
,t1.[refadmission]
,t1.[refunite]
,t1.[datedeb]
,t1.[datefin]
,t2.[refmouvement] as [prev_refmouvement]
,t2.refunite as prev_refunite
FROM [sometable] t1
LEFT OUTER JOIN [sometable] t2 /*self join*/
ON t2.datefin = t1.datedeb
AND t1.[refadmission] = t2.[refadmission]
ORDER BY
t1.[datedeb]
这就是它给我的:
+-----+-----+---------+--------------+--------------+----------+------------+------------+-------------------+---------------+
| ID1 | ID2 | Dossier | refmouvement | refadmission | refunite | datedeb | datefin | prev_refmouvement | prev_refunite |
+-----+-----+---------+--------------+--------------+----------+------------+------------+-------------------+---------------+
| 1 | 1 | P001234 | 2567 | 1234 | 227 | 2012-01-01 | 2012-01-02 | NULL | NULL |
| 2 | 2 | P001234 | 2568 | 1234 | 227 | 2012-01-02 | 2012-01-03 | 2567 | 227 |
| 3 | 1 | P001234 | 2569 | 1234 | 224 | 2012-01-03 | 2012-01-06 | 2568 | 227 |
| 4 | 1 | P001234 | 2570 | 1234 | 232 | 2012-01-06 | 2012-01-10 | 2569 | 224 |
| 5 | 2 | P001234 | 2571 | 1234 | 232 | 2012-01-10 | 2012-01-15 | 2570 | 232 |
| 6 | 3 | P001234 | 2572 | 1234 | 232 | 2012-01-15 | 2012-01-20 | 2571 | 232 |
| 7 | 4 | P001234 | 2573 | 1234 | 232 | 2012-01-20 | 2012-01-25 | 2572 | 232 |
| 8 | 2 | P001234 | 2574 | 1234 | 224 | 2012-01-25 | 2012-01-29 | 2573 | 232 |
| 9 | 3 | P001234 | 2575 | 1234 | 227 | 2012-01-29 | 2012-02-05 | 2574 | 224 |
| 10 | 4 | P001234 | 2576 | 1234 | 227 | 2012-02-05 | 2012-02-10 | 2575 | 227 |
| 11 | 5 | P001234 | 2577 | 1234 | 232 | 2012-02-10 | 2012-02-15 | 2576 | 227 |
| 12 | 1 | P001234 | 2578 | 1234 | 201 | 2012-02-15 | 2012-02-26 | 2577 | 232 |
+-----+-----+---------+--------------+--------------+----------+------------+------------+-------------------+---------------+
沙兹
结果:
RowNum refunite datedeb Rnk
----------- ----------- ----------------------- ---
1 227 2012-01-01 00:00:00.000 1
2 227 2012-01-02 00:00:00.000 1
3 224 2012-01-03 00:00:00.000 2
4 232 2012-01-06 00:00:00.000 3
5 232 2012-01-10 00:00:00.000 3
6 232 2012-01-15 00:00:00.000 3
7 232 2012-01-20 00:00:00.000 3
8 224 2012-01-25 00:00:00.000 4
9 227 2012-01-29 00:00:00.000 5
10 227 2012-02-05 00:00:00.000 5
11 232 2012-02-10 00:00:00.000 6
12 201 2012-02-15 00:00:00.000 7
当然,您可以在WITH中有多个表,从而消除表变量。 根据Bogdan Sahlean的回答,您可以这样重写:
+----+---------+--------------+--------------+----------+------------+------------+
| ID | Dossier | refmouvement | refadmission | refunite | datedeb | datefin |
+----+---------+--------------+--------------+----------+------------+------------+
| 1 | P001234 | 2567 | 1234 | 227 | 2012-01-01 | 2012-01-02 |
| 1 | P001234 | 2568 | 1234 | 227 | 2012-01-02 | 2012-01-03 |
| 2 | P001234 | 2569 | 1234 | 224 | 2012-01-03 | 2012-01-06 |
| 3 | P001234 | 2570 | 1234 | 232 | 2012-01-06 | 2012-01-10 |
| 3 | P001234 | 2571 | 1234 | 232 | 2012-01-10 | 2012-01-15 |
| 3 | P001234 | 2572 | 1234 | 232 | 2012-01-15 | 2012-01-20 |
| 3 | P001234 | 2573 | 1234 | 232 | 2012-01-20 | 2012-01-25 |
| 4 | P001234 | 2574 | 1234 | 224 | 2012-01-25 | 2012-01-29 |
| 5 | P001234 | 2575 | 1234 | 227 | 2012-01-29 | 2012-02-05 |
| 5 | P001234 | 2576 | 1234 | 227 | 2012-02-05 | 2012-02-10 |
| 6 | P001234 | 2577 | 1234 | 232 | 2012-02-10 | 2012-02-15 |
| 7 | P001234 | 2578 | 1234 | 201 | 2012-02-15 | 2012-02-26 |
+----+---------+--------------+--------------+----------+------------+------------+
WITH CTEHelper AS
(SELECT ROW_NUMBER() OVER(ORDER BY datedeb) AS RowNum,
refunite,
datedeb
FROM dbo.Sometable),
CTERecursive AS (
SELECT crt.RowNum,
crt.refunite,
crt.datedeb,
1 AS Id -- Starting rank
FROM CTEHelper crt
WHERE crt.RowNum = 1
UNION ALL
SELECT crt.RowNum,
crt.refunite,
crt.datedeb,
CASE WHEN prev.refunite = crt.refunite THEN prev.Id ELSE prev.Id + 1 END
FROM CTEHelper crt INNER JOIN CTERecursive prev ON crt.RowNum = prev.RowNum + 1
)
SELECT crt.id,
s.*
FROM CTERecursive crt
JOIN Sometable s ON s.refunite = crt.refunite AND s.datedeb = crt.datedeb
哇!这太棒了!非常感谢你!这将帮助我节省很多时间!你们真是精英啊!:)