Sql server 递归CTE SQL（父-子）

我正在使用SQL Server 2012

位置明细表

OID     LOCATIONNAME    PARENTID
1           GLOBAL          0
2           NORTH           1
3           SOUTH           1
4           NORTH1          2
5           SOUTH1          3

LOCATIONSITECONFIG表

OID LOCATIONID  SITENAME
1       2        TEST

OID LOCATIONDETAILOID   SITENAME
1       2               TEST
2       1               NEWTEST

我使用递归CTE查询

;WITH LOCALSITEHIERARCHY AS
(
    SELECT  A.OID
            ,A.PARENTOID
            ,CAST(A.LOCATIONNAME + ' ( ' + LSC.SITENAME + ' )' AS NVARCHAR(100)) AS NAME
            ,LSC.OID AS SITEOID
    FROM LOCATIONDETAIL A
            INNER JOIN LOCATIONSITECONFIG LSC 
                ON LSC.LOCATIONDETAILOID = A.OID                
    WHERE
            LSC.SITENAME <> 'GLOBAL' AND LSC.RECSTATUS = 'A'
    UNION ALL
    SELECT 
        A.OID
        ,A.PARENTOID
        ,CAST(A.LOCATIONNAME AS NVARCHAR(100))                  
        ,LH.SITEOID 
    FROM LOCATIONDETAIL A 
        INNER JOIN LOCALSITEHIERARCHY LH ON A.PARENTOID = LH.OID
)

SELECT * FROM LOCALSITEHIERARCHY

上述查询返回 全球，北，北1，南1，南1 以及NORTH（测试）和NORTH1（记录副本）

我希望查询返回 全球、北（测试）、北1、南1、南1

---

如果子项已创建站点，则应忽略查询。请将您的CTE更改为以GLOBAL作为锚定成员开始，以提供帮助。递归部分需要调整以包括SITENAME，这是通过合并（如果位置没有SITENAME）和子查询完成的

with LOCALSITEHIERARCHY
     as (
     select A.OID
          , A.PARENTOID
          , cast(A.LOCATIONNAME+' ( '+LSC.SITENAME+' )' as nvarchar(100)) as NAME
          , LSC.OID as SITEOID
          , cast(row_number() over(partition by parentoid order by A.LOCATIONNAME) as varchar(max)) as [PATH]
     from LOCATIONDETAIL as A
          inner join LOCATIONSITECONFIG as LSC on LSC.LOCATIONDETAILOID = A.OID
     where 1 = 1
           and A.PARENTOID is null
           and LSC.RECSTATUS = 'A'
     union all
     select A.OID
          , A.PARENTOID
          , cast(coalesce(A.LOCATIONNAME+' ( '+
                         (
                             select SITENAME
                             from LOCATIONSITECONFIG C
                             where C.LOCATIONDETAILOID = A.OID
                         )+' )', A.LOCATIONNAME) as nvarchar(100)) as NAME
          , coalesce((select C.OID from LOCATIONSITECONFIG C where C.LOCATIONDETAILOID = A.OID),NULL) as SITEOID
          , [path]+'-'+cast(row_number() over(partition by A.parentoid order by A.LOCATIONNAME) as varchar(max))
     from LOCATIONDETAIL as A
          inner join LOCALSITEHIERARCHY as LH on A.PARENTOID = LH.OID)

     select * from LOCALSITEHIERARCHY order by [PATH];

结果输出如下图所示

---

将您的CTE更改为以GLOBAL作为锚定成员开始。递归部分需要调整以包括SITENAME，这是通过合并（如果位置没有SITENAME）和子查询完成的

with LOCALSITEHIERARCHY
     as (
     select A.OID
          , A.PARENTOID
          , cast(A.LOCATIONNAME+' ( '+LSC.SITENAME+' )' as nvarchar(100)) as NAME
          , LSC.OID as SITEOID
          , cast(row_number() over(partition by parentoid order by A.LOCATIONNAME) as varchar(max)) as [PATH]
     from LOCATIONDETAIL as A
          inner join LOCATIONSITECONFIG as LSC on LSC.LOCATIONDETAILOID = A.OID
     where 1 = 1
           and A.PARENTOID is null
           and LSC.RECSTATUS = 'A'
     union all
     select A.OID
          , A.PARENTOID
          , cast(coalesce(A.LOCATIONNAME+' ( '+
                         (
                             select SITENAME
                             from LOCATIONSITECONFIG C
                             where C.LOCATIONDETAILOID = A.OID
                         )+' )', A.LOCATIONNAME) as nvarchar(100)) as NAME
          , coalesce((select C.OID from LOCATIONSITECONFIG C where C.LOCATIONDETAILOID = A.OID),NULL) as SITEOID
          , [path]+'-'+cast(row_number() over(partition by A.parentoid order by A.LOCATIONNAME) as varchar(max))
     from LOCATIONDETAIL as A
          inner join LOCALSITEHIERARCHY as LH on A.PARENTOID = LH.OID)

     select * from LOCALSITEHIERARCHY order by [PATH];

结果输出如下图所示

---

您想返回全球（最新）、北方（测试）、北方1、南方1吗？您想返回全球（最新）、北方（测试）、北方1、南方1吗？谢谢Koen，回答得很好。让我试着回你电话，我试过解决办法。应该相应地显示SiteOID，这里是LOCATIONSITECONFIG中的最后一个OID正在重复。我想让NORTH（Test）将siteoid设置为1，将Global（NewTEST）设置为2。你能帮个忙吗？你的意思是第四列SITEOID应该是1，2，NULL，NULL，NULL？如果位置存在sitename，则仅显示siteoid？谢谢Koen，答案草拟得很好。让我试着回你电话，我试过解决办法。应该相应地显示SiteOID，这里是LOCATIONSITECONFIG中的最后一个OID正在重复。我想让NORTH（Test）将siteoid设置为1，将Global（NewTEST）设置为2。你能帮个忙吗？你的意思是第四列SITEOID应该是1，2，NULL，NULL，NULL？如果位置存在sitename，则仅显示siteoid？