Sql server 需要增加一个GUID,10次中有9次我将重新检查您正在尝试执行的操作。与其增加GUID,不如只添加一个额外的序列列来消除歧义?因此,它们应该是“随机的”因为它们是全球唯一的……为什么要让下一代GUID变得可预测? LEFT([ID], 19) + RIGH
Sql server 需要增加一个GUID,10次中有9次我将重新检查您正在尝试执行的操作。与其增加GUID,不如只添加一个额外的序列列来消除歧义?因此,它们应该是“随机的”因为它们是全球唯一的……为什么要让下一代GUID变得可预测? LEFT([ID], 19) + RIGH,sql-server,tsql,uniqueidentifier,Sql Server,Tsql,Uniqueidentifier,需要增加一个GUID,10次中有9次我将重新检查您正在尝试执行的操作。与其增加GUID,不如只添加一个额外的序列列来消除歧义?因此,它们应该是“随机的”因为它们是全球唯一的……为什么要让下一代GUID变得可预测? LEFT([ID], 19) + RIGHT(CONVERT(uniqueidentifier, CONVERT(binary(16), CONVERT(binary(16), [ID]) + CONVERT(bigint, 1))), 17) AS 'MyNewID' declar
需要增加一个GUID,10次中有9次我将重新检查您正在尝试执行的操作。与其增加GUID,不如只添加一个额外的序列列来消除歧义?因此,它们应该是“随机的”因为它们是全球唯一的……为什么要让下一代GUID变得可预测?
LEFT([ID], 19) + RIGHT(CONVERT(uniqueidentifier, CONVERT(binary(16), CONVERT(binary(16), [ID]) + CONVERT(bigint, 1))), 17) AS 'MyNewID'
declare @guid uniqueidentifier, @binaryUpper8 binary(8), @binaryLower8 binary(8), @binary16 binary(16), @bigint bigint
set @guid = 'A6BC60AD-A4D9-46F4-A7D3-98B2A7237A9E'
set @binary16 = cast(@guid as binary(16))
--harvest lower 8 bytes
select @binaryUpper8= substring(@binary16, 1, 8)
,@binaryLower8 = substring(@binary16, 9, 8)
set @bigint = cast(@binaryLower8 as bigint)
--increment
set @bigint = @bigint + 1
--convert back
set @binaryLower8 = cast(@bigint as binary(8))
set @binary16 = @binaryUpper8 + @binaryLower8
set @guid = cast(@binary16 as uniqueidentifier)
select @guid
create function [dbo].[IncrementGuid](@guid uniqueidentifier)
returns uniqueidentifier
as
begin
declare @guid_binary binary(16), @b03 binary(4), @b45 binary(2), @b67 binary(2), @b89 binary(2), @bAF binary(6)
select @guid_binary = @guid
select @b03 = convert(binary(4), reverse(substring(@guid_binary,1,4)))
select @b45 = convert(binary(2), reverse(substring(@guid_binary,5,2)))
select @b67 = convert(binary(2), reverse(substring(@guid_binary,7,2)))
select @b89 = convert(binary(2), substring(@guid_binary,9,2))
select @bAF = convert(binary(6), substring(@guid_binary,11,6))
if (@b03 < 'FFFFFFFF')
begin
select @b03 = convert(binary(4), cast(@b03 as int) + 1)
end
else if (@b45 < 'FFFF')
begin
select @b45 = convert(binary(2), cast(@b45 as int) + 1)
end
else if (@b89 < 'FFFF')
begin
select @b89 = convert(binary(2), cast(@b89 as int) + 1)
end
else
begin
select @bAF = convert(binary(6), cast(@bAF as bigint) + 1)
end
return convert(binary(16), reverse(convert(char(4),@b03)) + reverse(convert(char(2),@b45)) + reverse(convert(char(2),@b67)) + convert(char(2),@b89) + convert(char(6),@bAF))
end