TSQL Msg 1013“使用相关名称来区分它们。”
在过去的两个小时里,我仔细研究了很多建议,不知道如何解决这个问题TSQL Msg 1013“使用相关名称来区分它们。”,tsql,sql-server-2008,Tsql,Sql Server 2008,在过去的两个小时里,我仔细研究了很多建议,不知道如何解决这个问题 SET DATEFORMAT DMY DECLARE @Source DATETIME = '01/01/2001' DECLARE @Destenaition DATETIME = '01/01/2020' SELECT ST.[Group], ST.Shop, SUM(ST.Purchased) AS Total, CHG.Charged FROM (SELECT Person
SET DATEFORMAT DMY
DECLARE @Source DATETIME = '01/01/2001'
DECLARE @Destenaition DATETIME = '01/01/2020'
SELECT ST.[Group],
ST.Shop,
SUM(ST.Purchased) AS Total,
CHG.Charged
FROM (SELECT Personals.Groups.[Name] AS 'Group',
Cards.vPurchases.PersonalID,
Personals.Registry.[Name],
SUM(Cards.vPurchases.Ammont) AS Purchased,
Cards.vPurchases.ShopName AS Shop
FROM Cards.vPurchases
INNER JOIN Personals.Registry
ON Personals.Registry.Id = Cards.vPurchases.PersonalID
INNER JOIN Personals.Groups
ON Personals.Registry.[Group] = Personals.Groups.Id
INNER JOIN Personals.Groups
ON Personals.Groups.Id = CHG.GroupID
WHERE Cards.vPurchases.[TimeStamp] >= @Source
AND Cards.vPurchases.[TimeStamp] <= @Destenaition
GROUP BY Cards.vPurchases.PersonalID,
Personals.Registry.[Name],
Personals.Groups.[Name],
Cards.vPurchases.ShopName) ST,
(SELECT PG.Id AS GroupID,
SUM(Cards.vCharges.Amount) AS Charged
FROM Cards.vCharges
INNER JOIN Personals.Registry
ON Personals.Registry.Id = Cards.vCharges.PersonalID
INNER JOIN Personals.Groups AS PG
ON Personals.Registry.[Group] = PG.Id
WHERE Cards.vCharges.[TimeStamp] >= @Source
AND Cards.vCharges.[TimeStamp] <= @Destenaition
GROUP BY Personals.Groups.[Name]) AS CHG
GROUP BY ST.Shop,
ST.[Group]
然后我得到这个错误:
Msg 1013,16级,状态1,第6行,对象个人组和
FROM子句中的Personals.group具有相同的公开名称。使用
关联名称以区分它们
谢谢。您在第一个子查询中使用了两次Personals.Groups表。
如果您真的想要表Personals.Groups,您需要给它们一个别名,然后在查询的其余部分中使用该别名,而不是表名
INNER JOIN Personals.Groups as PG1
及
如果您只需要一个,您可以将on子句组合起来,只使用一个
INNER JOIN Personals.Groups
ON Personals.Registry.[Group] = Personals.Groups.Id and
Personals.Groups.Id = CHG.GroupID
INNER JOIN Personals.Groups
ON Personals.Registry.[Group] = Personals.Groups.Id and
Personals.Groups.Id = CHG.GroupID