Sql server 插入1或0，其中EXCEPT在比较表时返回值

使用SQL Server 2014，我如何返回一个1或0的表，然后根据[Loan Identifier]对多个字段名的相似表中存在匹配项的1进行计数。我目前有一个名为dbo.Tape的表，它是原始表，然后是用户正在更新的dbo.[Tape Capture]。两个表中的[贷款标识符]相同

如果你能帮忙，谢谢你

SELECT       
   [Loan Identifier], [Completion date], [Tenure], [Underwriter name] 
FROM 
   dbo.Tape

EXCEPT

SELECT      
    [Loan Identifier], [Completion date], [Tenure], [Underwriter name]  
FROM 
    dbo.[Tape Capture]

如果

dbo.Tape

中的

[Completion date]

与

dbo.[Tape Capture]

中的

[Completion date]

匹配，那么我想返回1，否则返回零。然后我想对每列中的所有这些值求和。比如说,

dbo。[磁带捕获]：

[Loan Identifier], [Completion date], [Tenure], [Underwriter name] 
1                    01/01/2016       Freehold     James Mac
2                    01/01/2016       Leasehold    James Mac
3                    02/01/2016       Freehold     James Mac
4                    01/01/2016       Leasehold    James Mac
5                    03/01/2016       Freehold     James Mac

[Loan Identifier], [Completion date], [Tenure], [Underwriter name] 
1                    01/01/2016       Freehold     James Mac
2                    01/01/2016       Freehold     James Mac
3                    01/01/2016       Freehold     James Mac
4                    01/01/2016       Freehold     James Mac
5                    01/01/2016       Freehold     James Mac

dbo.Tape：

[Loan Identifier], [Completion date], [Tenure], [Underwriter name] 
1                    01/01/2016       Freehold     James Mac
2                    01/01/2016       Leasehold    James Mac
3                    02/01/2016       Freehold     James Mac
4                    01/01/2016       Leasehold    James Mac
5                    03/01/2016       Freehold     James Mac

[Loan Identifier], [Completion date], [Tenure], [Underwriter name] 
1                    01/01/2016       Freehold     James Mac
2                    01/01/2016       Freehold     James Mac
3                    01/01/2016       Freehold     James Mac
4                    01/01/2016       Freehold     James Mac
5                    01/01/2016       Freehold     James Mac

然后，我希望结果表能够容纳：

[Loan Identifier], [Completion date], [Tenure], [Underwriter name] 
1                    1                  1          1
2                    1                  0          1
3                    0                  1          1
4                    1                  0          1
5                    0                  1          1

---

从这里，我想总结每列中的值。

示例数据和期望的结果将有助于解释您想要做什么。现在还不清楚你想要什么样的结果。嗨，戈登，谢谢。我对我的问题进行了编辑以使其更清晰。样本数据和期望的结果将有助于解释您想要做什么。现在还不清楚你想要什么样的结果。嗨，戈登，谢谢。我对我的问题进行了编辑，使之更清楚。

SELECT T.[Loan Identifier], 
       CASE 
         WHEN TC.[Completion date] = T.[Completion date] THEN 1 
         ELSE 0 
       END AS [Completion date], 
       CASE 
         WHEN TC.[Tenure] = T.[Tenure] THEN 1 
         ELSE 0 
       END AS [Tenure], 
       CASE 
         WHEN TC.[Underwriter name] = T.[Underwriter name] THEN 1 
         ELSE 0 
       END AS [Underwriter name] 
FROM   [dbo].[Tape] AS T 
       LEFT JOIN [dbo].[Tape Capture] AS TC 
              ON T.[Loan Identifier] = TC.[Loan Identifier]