Sql server 显示存在两列的所有表-SQL Server 2008

我想搜索同时包含“Documentversionid”和“ClientMedicationID”列的所有表

试试这个：

SELECT t1.TABLE_NAME
FROM
(
    SELECT TABLE_NAME 
    FROM INFORMATION_SCHEMA.COLUMNS 
    WHERE COLUMN_NAME LIKE '%Documentversionid%'
) t1
INNER JOIN
(
    SELECT TABLE_NAME 
    FROM INFORMATION_SCHEMA.COLUMNS 
    WHERE COLUMN_NAME LIKE '%ClientMedicationID%'
) t2
    ON t1.TABLE_NAME = t2.TABLE_NAME

这应该做到：

SELECT COUNT(*) as COUNT, TABLE_SCHEMA, TABLE_NAME, COLUMN_NAME  
FROM `information_schema`.`columns` 
WHERE `TABLE_SCHEMA`='<YOUR DATABASE>' AND 
   (`COLUMN_NAME` = 'Documentversionid' OR `COLUMN_NAME`='ClientMedicationID') 
GROUP BY `TABLE_NAME` HAVING COUNT > 1

选择COUNT（*）作为计数、表模式、表名称、列名称
来自'information\u schema`.'columns`
其中`TABLE_SCHEMA`=''和
（`COLUMN\u NAME`='Documentversionid'或`COLUMN\u NAME`='ClientMedicationID'）
按计数大于1的“表名称”分组