Sql server 获取聚合日期统计信息/数据透视的最快方法

我试图写一份相当普通的审计报告；一段时间内添加到表中的行数；对照以前的周期进行报告，以了解数据的趋势

我有一个表，用于审核数据库中行的创建。它有一个字段ROWENTEREDATE date time。我希望每周/每月/当前季度/年度创建一份审计报告

在我的头脑中，我把它看作是对日期周围数据的多次传递；这在我的数据库中是相当昂贵的。我目前的理由是

我一开始是为我的年/月/季度制定日期

set datefirst 1

declare @dateranges table (
    rangelabel varchar(100), 
    startdate datetime, 
    enddate datetime, 
    myrowcount integer identity(1,1) 
    )


insert into @dateranges (Rangelabel, startdate, enddate)
select 
    'Current Year', 
    DATEADD(yy, DATEDIFF(yy,0,GETDATE()), 0),
    DATEADD(ms,-3,DATEADD(yy, DATEDIFF(yy,0,GETDATE()  )+1, 0))


    insert into @dateranges (Rangelabel, startdate, enddate)
select 
    'Current Quarter', 
    DATEADD(qq, DATEDIFF(qq,0,GETDATE()), 0),
    DATEADD(qq, DATEDIFF(qq, - 1, getdate()), - 1)


insert into @dateranges (Rangelabel, startdate, enddate)
select 
    'Current Month', 
    DATEADD(month, DATEDIFF(month, 0, getdate()), 0),
    DATEADD(s,-1,DATEADD(mm, DATEDIFF(m,0,GETDATE())+1,0))

如果我的表是tblofuselfacts，而我的日期行是RowEnteredDate，那么获取聚合的最佳方式是什么；被白天打破了

Date Range    Mon    Tues     Wed     Thu    Fri    Sat    Sun 
Year To date  12000  13000    12000   3200   98000  8900   4000 
Quarter 1        302    407      201     97     1732   120     37 
Month ...

使用这样的查询，我可以很容易地得到每天的总数

select
    count(*) ,
    datepart(weekday, RowEnteredDate)
    from 
        tblOfUsefullFacts aa
    Where 
        datepart(weekday, RowEnteredDate) is not null
    group by datepart(weekday, RowEnteredDate)
    order by datepart(weekday, RowEnteredDate) sac

这将逐行选择数据输出；我可以通过旋转和循环来获取数据。我有点紧张，因为实际数字在百万分之十，如果我能避免的话，我不想影响基本的处理

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由于我需要在多个过程中执行此操作，是否有一种更轻松的方法来执行此操作，而无需运行循环来获取总数？或者我的模糊大脑忽略了SQL中的一个机制。

这应该给你一个方法。很抱歉出现语法错误，它未经测试

   ;with cte as 
    (
        select
            d.rangelabel,
            datepart(weekday, RowEnteredDate) as WkDay,
            count(*) as RowCt
        from tblOfUsefullFacts f
        join @dateranges d on f.RowEnteredDate between d.startdate and d.enddate
        Where datepart(weekday, RowEnteredDate) is not null
        group by  d.rangelabel,datepart(weekday, RowEnteredDate)
    )
    select
        RangeLabel,
        sum(case when WkDay = 1 then RowCt else 0 end) as Sunday,
        sum(case when WkDay = 2 then RowCt else 0 end) as Monday,
        sum(case when WkDay = 3 then RowCt else 0 end) as Tuesday,
        sum(case when WkDay = 4 then RowCt else 0 end) as Wednesday,
        sum(case when WkDay = 5 then RowCt else 0 end) as Thursday,
        sum(case when WkDay = 6 then RowCt else 0 end) as Friday,
        sum(case when WkDay = 7 then RowCt else 0 end) as Saturday
    from cte
    group by RangeLabel

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根据我今天早上的测试；获得信息和最终支点肯定比三次传球快。谢谢：）