Sql server 使用SQL Server中不同表中的数据创建逗号分隔的值字符串
我有以下数据库模型：Sql server 使用SQL Server中不同表中的数据创建逗号分隔的值字符串,sql-server,group-by,stuff,Sql Server,Group By,Stuff,我有以下数据库模型： criteria table: criteria_id criteria_name is_range 1 product_category 0 2 product_subcategory 0 3 items 1 4 criteria_4 1 evaluation_grid table: eval
criteria table:
criteria_id criteria_name is_range
1 product_category 0
2 product_subcategory 0
3 items 1
4 criteria_4 1
evaluation_grid table:
evaluation_grid_id criteria_id start_value end_value provider property_1 property_2 property_3
1 1 3 NULL internal 1 1 1
2 1 1 NULL internal 1 1 1
3 2 1 NULL internal 1 2 1
4 3 1 100 internal 2 1 1
5 4 1 50 internal 2 2 1
6 1 2 NULL external 2 8 1
7 2 2 NULL external 2 5 1
8 3 1 150 external 2 2 2
9 3 1 100 external 2 3 1
product_category table:
id name
1 test1
2 test2
3 test3
product_subcategory table:
id name
1 producttest1
2 producttest2
3 producttest3
criteria start_value end_value provider property_1 property_2 property_3
product_category test3, test1 NULL internal 1 1 1
product_subcategory producttest1 NULL internal 1 2 1
items 1 100 internal 2 1 1
criteria_4 1 50 internal 2 2 1
product_category test2 NULL external 2 8 1
product_subcategory producttest2 NULL external 2 5 1
items 1 150 external 2 2 2
criteria_4 1 100 external 2 3 1
SELECT c.criteria_name AS criteria
,CASE WHEN c.criteria_id = 1
THEN
(IsNull(STUFF((SELECT ', ' + RTRIM(LTRIM(pc.name))
FROM product_category pc
INNER JOIN [evaluation_grid] eg ON eg.start_value=pc.id
WHERE srsg.criteria_id=c.criteria_id
FOR XML PATH('')), 1, 2, ''), ''))
WHEN c.criteria_id = 2
THEN (IsNull(STUFF((SELECT ' , ' + RTRIM(LTRIM(psc.name))
FROM product_subcategory psc
INNER JOIN [evaluation_grid] eg ON eg.start_value=psc.id
WHERE srsg.criteria_id=c.criteria_id
FOR XML PATH('')
), 1, 3, ''), ''))
ELSE
CAST(eg.start_value AS VARCHAR)
END AS start_value
,eg.end_value AS end_value
,eg.provider AS provider
,eg.property_1 AS property_1
,eg.property_2 AS property_2
,eg.property_3 AS property_3
FROM [evaluation_grid] eg
INNER JOIN criteria c ON eg.criteria_id = crs.criteria_id
GROUP BY c.criteria_name,c.criteria_id,c.is_range,eg.start_value,eg.end_value,eg.provider,eg.property_1,eg.property_2,eg.property_3
criteria start_value end_value provider property_1 property_2 property_3
product_category test3, test1, test2 NULL internal 1 1 1
product_category test3, test1, test2 NULL external 2 8 1
product_category test3, test1, test2 NULL internal 1 1 1
product_subcategory producttest1,producttest2 NULL internal 1 2 1
product_subcategory producttest1,producttest2 NULL external 2 5 1
items 1 100 internal 1 1 1
items 1 150 external 2 2 2
criteria_4 1 50 internal 2 2 1
criteria_4 1 100 external 2 3 1
criteria start_value end_value provider property_1 property_2 property_3
product_category test3, test1 NULL internal 1 1 1
product_subcategory producttest1 NULL internal 1 2 1
items 1 100 internal 2 1 1
criteria_4 1 50 internal 2 2 1
product_category test2 NULL external 2 8 1
product_subcategory producttest2 NULL external 2 5 1
items 1 150 external 2 2 2
criteria_4 1 100 external 2 3 1
SELECT c.criteria_name AS criteria
,CASE WHEN c.criteria_id = 1
THEN
(IsNull(STUFF((SELECT ', ' + RTRIM(LTRIM(pc.name))
FROM product_category pc
INNER JOIN [evaluation_grid] eg ON eg.start_value=pc.id
WHERE srsg.criteria_id=c.criteria_id
FOR XML PATH('')), 1, 2, ''), ''))
WHEN c.criteria_id = 2
THEN (IsNull(STUFF((SELECT ' , ' + RTRIM(LTRIM(psc.name))
FROM product_subcategory psc
INNER JOIN [evaluation_grid] eg ON eg.start_value=psc.id
WHERE srsg.criteria_id=c.criteria_id
FOR XML PATH('')
), 1, 3, ''), ''))
ELSE
CAST(eg.start_value AS VARCHAR)
END AS start_value
,eg.end_value AS end_value
,eg.provider AS provider
,eg.property_1 AS property_1
,eg.property_2 AS property_2
,eg.property_3 AS property_3
FROM [evaluation_grid] eg
INNER JOIN criteria c ON eg.criteria_id = crs.criteria_id
GROUP BY c.criteria_name,c.criteria_id,c.is_range,eg.start_value,eg.end_value,eg.provider,eg.property_1,eg.property_2,eg.property_3
criteria start_value end_value provider property_1 property_2 property_3
product_category test3, test1, test2 NULL internal 1 1 1
product_category test3, test1, test2 NULL external 2 8 1
product_category test3, test1, test2 NULL internal 1 1 1
product_subcategory producttest1,producttest2 NULL internal 1 2 1
product_subcategory producttest1,producttest2 NULL external 2 5 1
items 1 100 internal 1 1 1
items 1 150 external 2 2 2
criteria_4 1 50 internal 2 2 1
criteria_4 1 100 external 2 3 1
criteria start_value end_value provider property_1 property_2 property_3
product_category test3, test1 NULL internal 1 1 1
product_subcategory producttest1 NULL internal 1 2 1
items 1 100 internal 2 1 1
criteria_4 1 50 internal 2 2 1
product_category test2 NULL external 2 8 1
product_subcategory producttest2 NULL external 2 5 1
items 1 150 external 2 2 2
criteria_4 1 100 external 2 3 1
SELECT c.criteria_name AS criteria
,CASE WHEN c.criteria_id = 1
THEN
(IsNull(STUFF((SELECT ', ' + RTRIM(LTRIM(pc.name))
FROM product_category pc
INNER JOIN [evaluation_grid] eg ON eg.start_value=pc.id
WHERE srsg.criteria_id=c.criteria_id
FOR XML PATH('')), 1, 2, ''), ''))
WHEN c.criteria_id = 2
THEN (IsNull(STUFF((SELECT ' , ' + RTRIM(LTRIM(psc.name))
FROM product_subcategory psc
INNER JOIN [evaluation_grid] eg ON eg.start_value=psc.id
WHERE srsg.criteria_id=c.criteria_id
FOR XML PATH('')
), 1, 3, ''), ''))
ELSE
CAST(eg.start_value AS VARCHAR)
END AS start_value
,eg.end_value AS end_value
,eg.provider AS provider
,eg.property_1 AS property_1
,eg.property_2 AS property_2
,eg.property_3 AS property_3
FROM [evaluation_grid] eg
INNER JOIN criteria c ON eg.criteria_id = crs.criteria_id
GROUP BY c.criteria_name,c.criteria_id,c.is_range,eg.start_value,eg.end_value,eg.provider,eg.property_1,eg.property_2,eg.property_3
criteria start_value end_value provider property_1 property_2 property_3
product_category test3, test1, test2 NULL internal 1 1 1
product_category test3, test1, test2 NULL external 2 8 1
product_category test3, test1, test2 NULL internal 1 1 1
product_subcategory producttest1,producttest2 NULL internal 1 2 1
product_subcategory producttest1,producttest2 NULL external 2 5 1
items 1 100 internal 1 1 1
items 1 150 external 2 2 2
criteria_4 1 50 internal 2 2 1
criteria_4 1 100 external 2 3 1
如有任何建议，我们将不胜感激，谢谢 遵循这些要求有点困难。您能否查看下面的设置和结果，并让我们知道所需的结果集应该是什么
declare @criteria table (criteria_id int, criteria_name varchar(50), is_range bit)
insert into @criteria
values(1, 'product_category', 0), (2, 'product_subcategory', 0), (3, 'items', 1), (4, 'criteria_4', 1);
declare @evaluation_grid table (evaluation_grid_id int, criteria_id int, start_value int, end_value int, [provider] varchar(50), property_1 int, property_2 int, property_3 int);
insert into @evaluation_grid
values
(1, 1, 3, NULL, 'internal', 1, 1, 1),
(2, 1, 1, NULL, 'internal', 1, 1, 1),
(3, 2, 1, NULL, 'internal', 1, 2, 1),
(4, 3, 1, 100, 'internal', 2, 1, 1),
(5, 4, 1, 50, 'internal', 2, 2, 1),
(6, 1, 2, NULL, 'external', 2, 8, 1),
(7, 2, 2, NULL, 'external', 2, 5, 1),
(8, 3, 1, 150, 'external', 2, 2, 2),
(9, 4, 1, 100, 'external', 2, 3, 1)
declare @product_category table (id int, [name] varchar(50))
insert into @product_category
values (1, 'test1'), (2, 'test2'), (3, 'test3'), (4, 'test4');
declare @product_subcategory table (id int, [name] varchar(50))
insert into @product_subcategory
values (1, 'producttest1'), (2, 'producttest2'), (3, 'producttest3');
select c.criteria_name,
stuff(( select ',' + ipc.[name]
from @evaluation_grid ieg
join @product_category ipc on ieg.start_value = ipc.id
where [provider] = eg.[provider] and property_1 = eg.property_1 and property_2 = eg.property_2 and property_3 = eg.property_3
order by ieg.evaluation_grid_id
for xml path('')), 1 ,1, '') as start_value,
end_value,
[provider],
property_1,
property_2,
property_3
from @evaluation_grid eg
join @criteria c on eg.criteria_id = c.criteria_id
where c.is_range = 0
group
by c.criteria_name, end_value, [provider], property_1, property_2, property_3
union all
select c.criteria_name, cast(start_value as varchar(10)), end_value, [provider], property_1, property_2, property_3
from @evaluation_grid eg
join @criteria c on eg.criteria_id = c.criteria_id
where c.is_range = 1;
据我所知，这个查询返回您所寻找的确切输出
with cte as (
select c.criteria_name,
eg.evaluation_grid_id,
case when c.criteria_id = 1 then pc.[name]
when c.criteria_id = 2 then psc.[name]
else null end pc_cat,
c.criteria_id,c.is_range, eg.start_value, eg.end_value,
eg.[provider], eg.property_1, eg.property_2,eg.property_3
from @evaluation_grid eg
join @criteria c ON eg.criteria_id = c.criteria_id
left join @product_category pc on eg.start_value=pc.id
left join @product_subcategory psc on eg.start_value=psc.id)
select c.criteria_name as criteria,
case when c.is_range=0 then
STUFF((SELECT ', ' + RTRIM(LTRIM(c2.pc_cat))
FROM cte c2
WHERE c2.criteria_id=c.criteria_id
and c2.is_range=c.is_range
and c2.[provider]=c.[provider]
and c2.property_1=c.property_1
and c2.property_2=c.property_2
and c2.property_3=c.property_3
FOR XML PATH('')), 1, 2, '')
else max(cast(c.start_value as varchar(50))) end as start_value,
c.end_value, c.[provider], c.property_1, c.property_2, c.property_3
from cte c
group by c.criteria_name, c.criteria_id, c.is_range, c.end_value,
c.[provider], c.property_1, c.property_2, c.property_3
order by max(c.evaluation_grid_id);
criteria start_value end_value provider property_1 property_2 property_3
product_category test3, test1 NULL internal 1 1 1
product_subcategory producttest1 NULL internal 1 2 1
items 1 100 internal 2 1 1
criteria_4 1 50 internal 2 2 1
product_category test2 NULL external 2 8 1
product_subcategory producttest2 NULL external 2 5 1
items 1 150 external 2 2 2
criteria_4 1 100 external 2 3 1
这非常接近，但我需要保持表格评估网格的顺序，我也尝试了union，但没有成功。输出应该像我在这里指定的“我试图实现的是返回如下值：”。您是指
start\u值