Sql 按顺序编号的值组（包括重复）_Sql_Sql Server_Datetime_Window Functions_Gaps And Islands

Sql 按顺序编号的值组（包括重复）

sql sql-server datetime

Sql 按顺序编号的值组（包括重复）,sql,sql-server,datetime,window-functions,gaps-and-islands,Sql,Sql Server,Datetime,Window Functions,Gaps And Islands,我有下表： IF OBJECT_ID('tempdb..#Temp') IS NOT NULL DROP TABLE #Temp CREATE TABLE #Temp ( ID INT, Category VARCHAR(100), [Date] DATE ) INSERT INTO #Temp VALUES (1,'AAA','20200625'), (1,'BBB','20200626'), (1,'BBB','20200627'), (1,'AAA','2

我有下表：

IF OBJECT_ID('tempdb..#Temp') IS NOT NULL
    DROP TABLE #Temp
CREATE TABLE #Temp
(
    ID INT,
    Category VARCHAR(100),
    [Date] DATE
)
INSERT INTO #Temp VALUES 
(1,'AAA','20200625'),
(1,'BBB','20200626'),
(1,'BBB','20200627'),
(1,'AAA','20200628'),
(1,'AAA','20200629'),
(1,'BBB','20200630'),
(1,'AAA','20200701'),
(2,'AAA','20200625'),
(2,'BBB','20200626'),
(2,'BBB','20200627'),
(2,'AAA','20200628'),
(2,'AAA','20200629'),
(2,'BBB','20200630'),
(2,'AAA','20200701')

我不知道如何将一个连续整数分配给这样的类别：

ID  Category    Date        GroupNumber
-------------------------------------------
1   AAA         25/06/2020  1
1   BBB         26/06/2020  2
1   BBB         27/06/2020  2
1   AAA         28/06/2020  3
1   AAA         29/06/2020  3
1   BBB         30/06/2020  4
1   AAA         01/07/2020  5
2   AAA         25/06/2020  1
2   BBB         26/06/2020  2
2   BBB         27/06/2020  2
2   AAA         28/06/2020  3
2   AAA         29/06/2020  3
2   BBB         30/06/2020  4
2   AAA         01/07/2020  5

ID  Category    Date        DateFrom    DateTo
--------------------------------------------------
1   AAA         25/06/2020  25/06/2020  25/06/2020
1   BBB         26/06/2020  26/06/2020  27/06/2020
1   AAA         28/06/2020  28/06/2020  29/06/2020
1   BBB         30/06/2020  30/06/2020  30/06/2020
1   AAA         01/07/2020  01/07/2020  01/07/2020
2   AAA         25/06/2020  25/06/2020  25/06/2020
2   BBB         26/06/2020  26/06/2020  27/06/2020
2   AAA         28/06/2020  28/06/2020  29/06/2020
2   BBB         30/06/2020  30/06/2020  30/06/2020
2   AAA         01/07/2020  01/07/2020  01/07/2020

我尝试了不同的窗口函数组合，但没有成功。目标是将数据上卷，使其看起来像这样：

ID  Category    Date        GroupNumber
-------------------------------------------
1   AAA         25/06/2020  1
1   BBB         26/06/2020  2
1   BBB         27/06/2020  2
1   AAA         28/06/2020  3
1   AAA         29/06/2020  3
1   BBB         30/06/2020  4
1   AAA         01/07/2020  5
2   AAA         25/06/2020  1
2   BBB         26/06/2020  2
2   BBB         27/06/2020  2
2   AAA         28/06/2020  3
2   AAA         29/06/2020  3
2   BBB         30/06/2020  4
2   AAA         01/07/2020  5

ID  Category    Date        DateFrom    DateTo
--------------------------------------------------
1   AAA         25/06/2020  25/06/2020  25/06/2020
1   BBB         26/06/2020  26/06/2020  27/06/2020
1   AAA         28/06/2020  28/06/2020  29/06/2020
1   BBB         30/06/2020  30/06/2020  30/06/2020
1   AAA         01/07/2020  01/07/2020  01/07/2020
2   AAA         25/06/2020  25/06/2020  25/06/2020
2   BBB         26/06/2020  26/06/2020  27/06/2020
2   AAA         28/06/2020  28/06/2020  29/06/2020
2   BBB         30/06/2020  30/06/2020  30/06/2020
2   AAA         01/07/2020  01/07/2020  01/07/2020

这是一个间隙和孤岛问题，您希望将“相邻行”分组在一起。要获得您想要的最终结果，最简单的方法可能是使用行号之间的差异来标识组：

select id, category, min(date) datefrom, max(date) dateto
from (
    select t.*, 
        row_number() over(partition by id order by date) rn1,
        row_number() over(partition by id, category order by date) rn2
    from #temp t
) t
group by id, category, rn1 - rn2
order by id, datefrom

：

id | category | datefrom | dateto -: | :------- | :--------- | :--------- 1 | AAA | 2020-06-25 | 2020-06-25 1 | BBB | 2020-06-26 | 2020-06-27 1 | AAA | 2020-06-28 | 2020-06-29 1 | BBB | 2020-06-30 | 2020-06-30 1 | AAA | 2020-07-01 | 2020-07-01 2 | AAA | 2020-06-25 | 2020-06-25 2 | BBB | 2020-06-26 | 2020-06-27 2 | AAA | 2020-06-28 | 2020-06-29 2 | BBB | 2020-06-30 | 2020-06-30 2 | AAA | 2020-07-01 | 2020-07-01 id |类别|日期从|日期到 -: | :------- | :--------- | :--------- 1 | AAA | 2020-06-25 | 2020-06-25 1 | BBB | 2020-06-26 | 2020-06-27 1 | AAA | 2020-06-28 | 2020-06-29 1 | BBB | 2020-06-30 | 2020-06-30 1 | AAA | 2020-07-01 | 2020-07-01 2 | AAA | 2020-06-25 | 2020-06-25 2 | BBB | 2020-06-26 | 2020-06-27 2 | AAA | 2020-06-28 | 2020-06-29 2 | BBB | 2020-06-30 | 2020-06-30 2 | AAA | 2020-07-01 | 2020-07-01

这是一个间隙和孤岛问题，您希望将“相邻行”分组在一起。要获得您想要的最终结果，最简单的方法可能是使用行号之间的差异来标识组：

select id, category, min(date) datefrom, max(date) dateto
from (
    select t.*, 
        row_number() over(partition by id order by date) rn1,
        row_number() over(partition by id, category order by date) rn2
    from #temp t
) t
group by id, category, rn1 - rn2
order by id, datefrom

：