SQL Server中的复杂分组查询
下面是我的SQL查询。我需要更改它,这样我就可以获得每个SQL Server中的复杂分组查询,sql,sql-server,Sql,Sql Server,下面是我的SQL查询。我需要更改它,这样我就可以获得每个wkld\u日期的总工作量或所有工作量。当我给出条件ssawd.wkld_date=201803时,此代码非常有效,但我希望它返回根据wkld_date分组的工作负载总和。请帮忙。非常感谢 select ISNULL(SUM(ssawd.WORKLOAD), 0) w3 from AGMT_MAN_SCH_SS ssams inner join AGMT_WKLD_SUMMARY_SS ssaws o
wkld\u日期的总工作量或所有工作量。当我给出条件ssawd.wkld_date=201803
时,此代码非常有效,但我希望它返回根据wkld_date
分组的工作负载总和。请帮忙。非常感谢
select
ISNULL(SUM(ssawd.WORKLOAD), 0) w3
from
AGMT_MAN_SCH_SS ssams
inner join
AGMT_WKLD_SUMMARY_SS ssaws on ssams.SCHEDULE_ID = ssaws.SCHEDULE_ID
and ssams.SNAP_DATE = ssaws.SNAP_DATE
inner join
AGMT_WKLD_DETAIL_SS ssawd on ssaws.summary_id = ssawd.summary_id
and ssaws.SNAP_DATE = ssawd.SNAP_DATE
inner join
AGREEMENT ag on ssams.agmt_id = ag.AGMT_ID
where
ssaws.STAFF_ID = 4331
and ssawd.wkld_date = 201803
and ((ag.AGMT_ACTCPLTDATE is not null
and ag.AGMT_ACTCPLTDATE > '2018-01-01')
or ag.AGMT_ACTCPLTDATE is null)
and ((ag.AGMT_TERMDATE is not null
and ag.AGMT_TERMDATE > '2018-01-01')
or ag.AGMT_TERMDATE is null)
and dateadd(year, 10, ag.AGMT_ACTCOMMENTDATE) > '2018-01-01'
and UPPER(ssaws.POST_TYPE) NOT LIKE UPPER('Unnamed')
and ssams.agmt_id != 140
and (ssams.INTM_SNAP_DATE in (select max(INTM_SNAP_DATE)
from AGMT_MAN_SCH ams
where ams.AGMT_ID = ag.AGMT_ID
and ams.SNAP_TYPE = 'I')
or ssams.LATEST_SNAP_DATE in (select max(LATEST_SNAP_DATE)
from AGMT_MAN_SCH ams
where ams.AGMT_ID = ag.AGMT_ID
and ams.SNAP_TYPE = 'F')
)
听起来你想要一个简单的分组语句。在您的情况下,它将如下所示:
SELECT ssawd.wkld_date, sum(ssawd.WORKLOAD) w3
from AGMT_MAN_SCH_SS ssams
inner join AGMT_WKLD_SUMMARY_SS ssaws on ssams.SCHEDULE_ID = ssaws.SCHEDULE_ID and ssams.SNAP_DATE = ssaws.SNAP_DATE
inner join AGMT_WKLD_DETAIL_SS ssawd on ssaws.summary_id = ssawd.summary_id and ssaws.SNAP_DATE = ssawd.SNAP_DATE
inner join AGREEMENT ag on ssams.agmt_id = ag.AGMT_ID
where ssaws.STAFF_ID = 4331
and ((ag.AGMT_ACTCPLTDATE is not null and ag.AGMT_ACTCPLTDATE > '2018-01-01') or ag.AGMT_ACTCPLTDATE is null)
and ((ag.AGMT_TERMDATE is not null and ag.AGMT_TERMDATE > '2018-01-01') or ag.AGMT_TERMDATE is null)
and dateadd(year, 10, ag.AGMT_ACTCOMMENTDATE) > '2018-01-01'
and UPPER(ssaws.POST_TYPE) NOT LIKE UPPER('Unnamed')
and ssams.agmt_id != 140
and (ssams.INTM_SNAP_DATE in
(select max(INTM_SNAP_DATE) from AGMT_MAN_SCH ams where ams.AGMT_ID = ag.AGMT_ID and ams.SNAP_TYPE = 'I' )
or ssams.LATEST_SNAP_DATE in
(select max(LATEST_SNAP_DATE) from AGMT_MAN_SCH ams where ams.AGMT_ID = ag.AGMT_ID and ams.SNAP_TYPE = 'F'))
GROUP BY ssawd.wkld_date
注意,我已经从WHERE语句中删除了ssawd.wkld_date,将其添加到返回的字段中,并在GROUP BY语句的末尾使用它 听起来你想要一个简单的groupby语句。在您的情况下,它将如下所示:
SELECT ssawd.wkld_date, sum(ssawd.WORKLOAD) w3
from AGMT_MAN_SCH_SS ssams
inner join AGMT_WKLD_SUMMARY_SS ssaws on ssams.SCHEDULE_ID = ssaws.SCHEDULE_ID and ssams.SNAP_DATE = ssaws.SNAP_DATE
inner join AGMT_WKLD_DETAIL_SS ssawd on ssaws.summary_id = ssawd.summary_id and ssaws.SNAP_DATE = ssawd.SNAP_DATE
inner join AGREEMENT ag on ssams.agmt_id = ag.AGMT_ID
where ssaws.STAFF_ID = 4331
and ((ag.AGMT_ACTCPLTDATE is not null and ag.AGMT_ACTCPLTDATE > '2018-01-01') or ag.AGMT_ACTCPLTDATE is null)
and ((ag.AGMT_TERMDATE is not null and ag.AGMT_TERMDATE > '2018-01-01') or ag.AGMT_TERMDATE is null)
and dateadd(year, 10, ag.AGMT_ACTCOMMENTDATE) > '2018-01-01'
and UPPER(ssaws.POST_TYPE) NOT LIKE UPPER('Unnamed')
and ssams.agmt_id != 140
and (ssams.INTM_SNAP_DATE in
(select max(INTM_SNAP_DATE) from AGMT_MAN_SCH ams where ams.AGMT_ID = ag.AGMT_ID and ams.SNAP_TYPE = 'I' )
or ssams.LATEST_SNAP_DATE in
(select max(LATEST_SNAP_DATE) from AGMT_MAN_SCH ams where ams.AGMT_ID = ag.AGMT_ID and ams.SNAP_TYPE = 'F'))
GROUP BY ssawd.wkld_date
注意,我已经从WHERE语句中删除了ssawd.wkld_date,将其添加到返回的字段中,并在GROUP BY语句的末尾使用它 您好,谢谢您的回复,我试过了,但没有返回任何一行。不要回答重复的问题。您好,谢谢您的回复,我试过了,但没有返回任何一行。不要回答重复的问题。可能的重复可能的重复